Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In a solid atom M occupies ccp lattice and ((1)/(3)) of tetrahedral voids are occupied by atom N, find the formula of solid formed by M and N .

Answer»

`MN`
`M_(3)N`
`MN_(3)`
`M_(3)N_(2)`

Solution :Hint : If the total number of M atoms in n, then then number of tetrahedral voids `=2n`
Given that `((1)/(3))RD` of tetrahedral voids are OCCUPIED i.e., `((1)/(3))xx2n` are occupied by N atom.
`therefore M:N rArr M_(3)N_(2)`
2.

In a solid AB of NaCl structure, A atoms occupy the corners of the cubic unit cell. If all the corner atoms are removed then the formula of the unit cell will be:

Answer»

`A_(4)B_(4)`
B
`A_(3)B_(4)`
AB

ANSWER :C
3.

In a solid AB having the NaCl structure, A atom occupies the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

Answer»

`AB_(2)`
`A_(2)B`
`A_(4)B_(3)`
`A_(3)B_(4)`

ANSWER :D
4.

In a solid AB having the NaCZ structure. ‘A’ atoms occupy the corners of the cubic unit cell. If all the edge-centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

Answer»

`AB_2`
`A_2B`
`A_4B_3`
`A_3B_4`

ANSWER :C
5.

In a solid (AB) having rock salt type structure all the atoms along body diagonal plane are removed the formula of the remaining unit cell will be

Answer»

AB
AB
`A_(2)B`
`A_(3)B_(2)`

SOLUTION :`PH-OVERSET(O)overset(||)(C)-CH_(2)-PH`does not give `(+)` ve Halform Test.
6.

In a solid 'AB' having NaCl structure, 'A' atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed,then the resultant stiochiometry of the solid is

Answer»

`AB_(2)`
`A_(2)B`
`A_(4) B_(3)`
`A_(3)B_(4)`

Solution :No. of atoms (A) on the corners = 8
No. of atoms (A) on the face centres = 6
Removing face centred atoms along one of the axes means removal of 2A atoms so that
No. of A atoms per UNIT cell
`= 8 xx ( 1)/( 8 ) + 4 xx ( 1)/( 2) = 3 `
No. of B atoms per unit cell in NACL type structure=4. Formula = `A_(3) B_(4)`
7.

In a sodium chloride crystal, each chloride ion is surrounded by

Answer»

6 SODIUM IONS
6 CHLORIDE ions
8 sodium ions
4 sodium ions.

Solution :6 sodium ions
8.

In a sodium chloride crystal, each chloride ion is surrounded by:

Answer»

6 SODIUM ions
6 CHLORIDE ions
8 sodium ions
4 sodium ions

Answer :A
9.

IN a sodium chloride crystal, each chloride ion is surrounded by :

Answer»

6 SODIUM ions
6 CHLORIDE ions
8 sodium ions
4 sodium ions

Answer :A
10.

In a S_(N)2 substitution reaction of the type R-Br+Cl^(-) overset(DMF)to R-Cl+Br^(-) which one of the following has thehighest relative rate?

Answer»

`CH_(3)-underset(CH_(3))underset(|)OVERSET(CH_(3))overset(|)(C)-CH_(2)Br`
`CH_(3)CH_(2)Br`
`CH_(3)-CH_(2)-CH_(2)Br`
`CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)Br`

Solution :Rates of `S_(N)2` reactions are influenced by steric factors. Since `CH_(3)CH_(2)Br` has the least steric hindrance, therefore, it REACTS at the fastest rate.
11.

In a simple Galvanic cell , which is in standard state, half cell reactions with their appropriate oxidation potentials are {:(Pb (s) - 2e^(-) to Pb^(2+) (aq) E^(@) = +0.13 "volt") , (Ag (s) - e^(-) to Ag^(2+) (aq) E^(@) = - 0.80 "volt"):} Which of the following reaction takes place ?

Answer»

`PB^(2+) (AQ.) + 2 Ag (s) to 2 Ag^(+) (aq.) + Pb (s)`
`Pb^(2+) (aq.) + Ag(s) to Ag^(+) (aq.) + Pb (s)`
`Ag^(+) (aq.) + Pb(s) to Ag(s) + Pb^(2+) (aq.)`
`2 Ag^(+) (aq.) + Pb(s) to 2 Ag(s) + Pb^(2+) (aq.)`

Solution :Check the spontaneity of each reaction by finding E.M.F. For a SPONTANEOUS reaction, EMF should be +ve .
12.

In a S_(N)2 substitution reaction of the type R-Br+Cl^(-)overset(DMF)rarr R-Cl+Br^(-)which one of the following has the highest relative rate ?

Answer»

`CH_(3)-CH_(2)-CH_(2)Br`
`CH_(3)-UNDERSET(CH_(3))underset("|")("C ")H-CH_(2)Br`
`CH_(3)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")("C ")-CH_(2)Br`
`CH_(3)CH_(2)Br`

Solution :For such a reaction the rate of `SN^(2)` SUBSTITUTION reaction is maximum in case of `CH_(3)CH_(2)Br` because `SN^(2)` mechanism is followed in case of primary and secondary halidesi.e.,`SN^(2)` reaction is favored by small groups on the CARBON atom attached to halogens so`CH_(3)CH_(2)Br gt CH_(3)CH_(2)CH_(2)Br gt CH_(3)-underset(CH_(3))underset("|")("C ")H-Br gt CH_(3)-overset(CH_(3))overset("|")underset(CH_(3))underset("|")("C ")-Br`i.e., option (D) is correct.
13.

In a single isolated atomof hydrogen electron make transition from4^(th)excited state to grond state producingmaximumpossible number of wavelengthsif the 2^(nd)lowest energy of theselinesis used to further excite an already excitedsample of Li^(2+)ion then transition will be

Answer»

`12rarr 15`
`9 RARR 12`
`6 rarr 9`
`3 rarr 6`

ANSWER :B
14.

In a S_(N)^(1) reaction on chiral centres, there is

Answer»

100% RETENTION
100% inversion
100% recenisation
inversion is more than retention LEADING to recenisation

Answer :D
15.

In a simple cubic crystal, the corner atom touches

Answer»

3 other atoms
4 other atoms
6 other atoms
8 other atoms

Answer :C
16.

In a simple cubic crystal, each atom is shared by

Answer»

2 UNIT cells
4 unit cells
6 unit cells
8 unit cells

Answer :D
17.

In a simple cubic cell, the number of atoms present :

Answer»

4
2
3
5

Answer :D
18.

In a simple cubic cell, each atom on a corner is shared by:

Answer»

2 UNIT cells
1 unit cell
8 unit cells
4 unit cells

Answer :C
19.

In a set of the given reactions, acetic acid yielded a product iC. CH_(3)COOH+PCl_(5) to A overset(C_(6)H_(6))underset(Anh. AlCl_(3))toB overset(C_(2)H_(5)MgBr)underset("ether")toC Product C would be

Answer»

`CH_(3)CH(OH)C_(2)H_(5)`
`CH_(3)COC_(6)H_(5)`
`CH_(3)CH(OH)C_(6)H_(5)`
`CH_(3)-OVERSET("C"_(2)H_(5))overset(|)C(OH)C_(6)H_(5)`

Solution :`CH_(3)COOH+PCl_(5) to underset((A))(CH_(3)COCL) overset(C_(6)H_(6))underset("anhy. "AlCl_(3)) to underset((B))(C_(6)H_(5)COCH_(3))overset(C_(2)H_(5)MGBR)underset("ether")to underset((C )) (C_(6)H_(5)overset(" "C_(2)H_(5))overset(|)underset(OH)underset(|)C-CH_(3))`
20.

In a set of reactions, propionic acid yielded a compound D underset((A))(CH_(3)CH_(2)COOH) overset(SOCl_(2))(rarr) B overset(NH_(3))(rarr) C overset(Br_(2)//KOH)(rarr) D The structure of D would be

Answer»

`CH_(3)CH_(2)NH_(2)`<BR>`CH_(3)CH_(2)CH_(2)NH_(2)`
`CH_(3)CH_(2)CONH_(2)`
`CH(3)CH_(2)NHCH_(3)`.

Solution :`underset((A))(CH_(3)CH_(2)COOH) OVERSET(SOCl_(2))(rarr) underset((B))(CH_(3)CH_(2)COCl) underset(-NH_(4)Cl)overset(NH_(3)" excess")(rarr) underset((C))(CH_(3)CH_(2)CONH_(2)) overset(Br_(2)//KOH)(rarr) underset((D))(CH_(3)CH_(2)NH_(2))`
21.

In a set of the given reactions, acetic acid yielded a product C. CH_3COOH + PCl_5 to A underset(Anh. AlCl_3)overset(C_6H_6)to B underset"Ether " overset(C_2H_5MgBr)to C Product C would be

Answer»

`CH_3-overset(C_2H_5)overset|C(OH)C_6H_5`
`CH_3CH(OH)C_2H_5`
`CH_3COC_6H_5`
`CH_3CH(OH)C_6H_5`

SOLUTION :
22.

In a set of reactions propionic acid yielded compound D, CH_(3)CH_(2)COOHoverset(SOCl_(2))toBoverset(NH_(3))toCunderset(Br_(2))overset(KOH)toDThe structure of D would be :

Answer»

`CH_(3)CONH_(2)`
`CH_(3)CH_(2)NHCH_(3)`
`CH_(3)CH_(2)NH_(2)`
`CH_(3)CH_(2)CH_(2)NH_(2)`.

SOLUTION :`CH_(3)CH_(2)COOHoverset(SOCl_(2))toCH_(3)CH_(2)COClunderset(-HCl)overset(NH_(3))toCH_(3)CH_(2)CONH_(2)underset(KOH)overset(Br_(2))toCH_(3)CH_(2)NH_(2)`
23.

In a set of reactions acetic acid yields a product [D] The structures of [D] would be: CH_(3)COOHoverset(SOCl_(2))to[A]overset(C_(6)H_(5))underset(Anhy. AlCl_(3))to[B] overset(HCN)to[C]overset(HOH)to[D]

Answer»

`C_(6)H_(5)CH_(2)-overset(OH)overset(|)UNDERSET(CN)underset(|)(C)-CH_(3)`
`C_(6)H_(5)-overset(CN)overset(|)underset(OH)underset(|)(C)-CH_(3)`
`C_(6)H_(5)-overset(OH)overset(|)underset(CH_(3))underset(|)(C)-COOH`

SOLUTION :
24.

In a set of reactions, ethyl benzene yielded a product D. 'D' would be :

Answer»




SOLUTION :
25.

In a set of reactions p- nitrotoluene yielded a produce E The product E would be

Answer»




SOLUTION :
26.

In a set of reactions, ethyl benzene yielded a product D. 'D' would be :

Answer»




SOLUTION :
27.

In a set of degenerate orbitals, the electrons distribute themselves to retain like spins as far as possible. The statement is attributed to

Answer»

PAULI EXCLUSION principle
Aufbau principle
Hund's rnle of MAXIMUM multiplicity
Slater's RULE.

Solution :By DEFINITION ofHund.s rule:
28.

In a set of reaction, m bromobenzoic acid gave a product D. Identify the product D.

Answer»




SOLUTION :
29.

In a set of reaction, ethyl benzene yielded a product D. The product D would be

Answer»




SOLUTION :The SEQUENCE of REACTION is as FOLLOWS:
.
30.

In a set of reactions, acetic acid yielded a product D. The structure of D would be :

Answer»




ANSWER :A
31.

in aset of degenerate orbitals the electrons distribute themselves to retailsimilar spins as far as possible. This statement is attributed to

Answer»

PAULI's EXCLUSION principle
hunds rule
Aufbau principle
slatersrule

Answer :B
32.

In a secondary cell ,

Answer»

the electrical energy obtained is first hand
magnitude of emf DEPENDS on charging
the electrical energy is developed within the cell
we can draw a CURRENT of high magnitude

Solution :During charging concentration of `H_(2)SO_(4)` increases and the emf depends on it . In a SECONDARY cell electrical energy is first stored as chemical energy . HENCE high magnitude current is not available .
33.

In a second order reaction, if one of the concentration is excess, the order of the reaction is ________ order reaction.

Answer»

FIRST
PSEUDO first
THIRD
zero

ANSWER :B
34.

In a saturated solution of the sparingly soluble strong electrolyte AglO_(3) (s) hArr Ag^(+)(aq)+IO_(3)^(-)(aq). If the solubility product constant K_(sp) " of " AgIO_(3) at a given temperature is 1.0xx10^(-8), what is the mass of AgIO_(3) contained in 100 ml of its saturated solution ?

Answer»

`1.0xx10^(-4)G`
`28.3xx10^(-2)g`
`2.83xx10^(-3)g`
`1.0xx10^(-7)g`

Solution :Let s =SOLUBILITY
`AgIO_(3) hArr underset(s)(Ag^(**)) ** underset(s)(IO_(3))`
`K_(sp)=[Ag^(+)][IO_(3)^(-)]=sxxs=s^(2)`
Given `K_(sp)=1xx10^(-8)`
`therefore s= sqrt(K_(sp))=sqrt(1xx10^(-8))`
`=1.0xx10^(-4) "mol"//"LIT"=1.0xx10^(-4)xx283`g/lit
`(because` Molecular mass of `Ag IO_(3)=283)`
`=(1.0xx10^(-4)xx283xx100)/(1000)gm//100ml`
`=2.83xx10^(-3)gm//100ml`
35.

In a saturated solution of the sparingly soluble strong electrolyte AgIO_(3) (Molecular mass = 283) the equilibrium which sets in is AgIO_(3_(s)) hArr Ag_((aq))^(-) + IO_(3_(aq))^(-) If the solubility product constant K_(sp) of AgIO_(3) at a given temperature is 1.0 xx 10^(-8), what is the mass of AgIO_(3) contained in 100 ml of its saturated solution

Answer»

`28.3 xx 10^(-2) g`
`2.83 xx 10^(-3) g`
`1.0 xx 10^(-7) g`
`1.0 xx 10^(-4)g`

Solution :`AgIO_(3_((s))) hArr Ag_((aq))^(+) + IO_(3_((aq)))^(-)`
`K_(sp) = [AG^(+)] [IO_(3)^(-)]`
`1.0 xx 10^(-8) = s^(2)`
`s = 10^(-4)` mol/litre
`= (10^(-4) xx 283)/(1000) xx 100 = 283 xx 10^(-5) = 2.83 xx 10^(-3)` g/100 ML.
36.

In a saturated solution of the sparingly soluble strong electrolyte. AgIO_(3) (molecular mass = 283), the equilibrium which sets in is :AgIO_(3)(s)hArr Ag^(+)(aq)+IO_(3)^(-)(aq)If the solubility product constant, K_(sp) of AgIO_(3)at a given temperature is 1.0xx10^(-8), what is the mass of AgIO_(3) contained in 100ml of its saturated solution ?

Answer»

`2.83xx10^(-3)g`
`1.0xx10^(-7)g`
`1.0xx10^(-4)g`
`28.3xx10^(-2)g`

Solution :`AgIO_(3)(s)hArr Ag^(+)(aq)+IO_(3)^(-)(aq)`
Let the solubility of `AgIO_(3)` in a saturated solution = s
`K_(sp)=[Ag^(+)][IO_(3)^(-)]=s xx s =s^(2)`
or `s=sqrt(K_(sp))=sqrt(1.0xx10^(-8))=10^(-4)mol L^(-1)`
Concentration `=10^(-4)xx 283 g L^(-1)`
or`=(10^(-4)xx283xx100)/(1000)`
`=2.83xx10^(-3)` g per 100 ml .
37.

In a saturated solution of electrolyte, the ionic product of their concentration are constant at constant temperature and this constant for electrolyte is known as

Answer»

IONIC product
Solubility product
Ionization CONSTANT
Dissociation constant

ANSWER :B
38.

In a saturated solution of calcium phosphate, the concentration of PO_(4)^(3-) ions is 3.3xx10^(-7)M. The K_(sp) of Ca_(3)(PO_(4))_(2) will be :

Answer»

`1.32xx10^(-31)`
`1.32xx10^(-32)`
`1.32xx10^(-33)`
`1.32xx10^(-35)`

ANSWER :B
39.

In a sample of wood, the reading of a counter is 32 dpm and in a fresh sample of tree it is 122dpm . Due to error counter gives the reading 2 dpm in absence of .^(14)C . Half life of .^(14)C is 5770 years . The approximate age (in years) of wood sample is :

Answer»

7997.2
57570
11540
15140

Answer :C
40.

In a sample of hydrogen atom containing 1 mole of H atoms, electrons in 30% of H-atoms are in 1^"st" excited state and remaining are in 2^"nd" excited state and ground state . If the total energy emitted when all electrons return to ground state is 642.24 kJ, find % of electron in 2^"nd" excited state . Energy level in H-atom =E_1=-13.6 eV, E_2=-3.4 eV, E_3= -1.5 eV and (1 eV/ species =96 kJ /mole)

Answer»


ANSWER :30
41.

In a sample of pitchblende the ratio of ""^(206)Pb, ""^(238)U= 0.2: 1 by weight. If the disintegration constant of ""^(238)U " is " 1.54 xx 10^(-10) per year and all Pb is supposed to be originated from uranium, what will be the age of the mineral?

Answer»

SOLUTION :INITIAL moles: `N^(0)""^(238)U rarr ""^(206)PB`
Moles after time `t: (N^(0)-x) " " x`
`(WT. "of " ""^(206)Pb)/("wt. of" ""^(238)U)= (0.2)/(1)`
`therefore ("mole of" Pb^(206))/("mole of " U^(238))=(0.2//206)/(1//238)= (0.231)/(1)`
or `(x)/(N^(0)-x)= 0.231`
Adding 1 in both sides, `1+ (x)/(N^(0)-x)= 0.231 +1`
`(N^(0))/(N^(0)-x)= 1.231`
We have, `lamda= (2.303)/(t) "log" (N^(0))/(N)`
or `lamda= (2.303)/(t)"log" (N^(0))/(N^(0)-x)`
`1.54 xx 10^(-10) = (2.303)/(t) "log" 1.231`
`t= 1.35 xx 10^(9)` years
42.

In a sample of pitchblende the atomic ratio is ""^(206)Pb, ""^(238)U= 0.23: 1. Calculate the age of the mineral, if half-life of uranium is taken as 4.5 xx 10^(9) years. All lead originated from uranium.

Answer»

SOLUTION :`1.34 XX 10^(9)` YEARS
43.

In a sample of H-atom if only 3 atoms are present and all are in 6th excited state then maximum possible photons of different wavelengths are

Answer»

9
10
11
12

Solution :De-exciatation of `e^(-)` from `n=7^(TH)` to ground state DIRECTLY and INDIRECT when only 3 atoms are present.

Maximum POSSIBLE photons of DIFFERENT wavelength are `=6+3+2=11`
44.

In a sample of H-atom electrons make transition from 5^(th) excited state to ground state, producing all possible types of photons, then number of lines in infrared region are

Answer»

4
5
6
3

Solution :
maximum number of lines produced =`(6(6-1))/2=15`
out of these 15 lines.
5 lines belong to ultra violet REGION and 4 lines are in visible region and rest are in INFRARED region.
45.

In a salt bridge,KCI is used because:

Answer»

It is an electrolyte
It is good CONDUCTOR of electricity
The transport NUMBER of `K^+` and `CI^-`IONS are nearly same or both have same ionic MOBILITY
`Cu, Hg, AG`

Answer :C
46.

In a salt bridge KCl is used because

Answer»

KCl is present in the calomel electrode
`K^(+) "and" Cl^(-)` ion have the same TRANSPORT NUMBER
`K^(+) "and" Cl^(-)` are isoelectrons
KCl is an electrolyte

Answer :B
47.

In a reversible reaction two substances are in equilibrium. If the concentration of each is double the equilibrium is:

Answer»

REDUCED to HALF of its ORIGINAL VALUE
reduced to 1/4th of its original value
doubled
constant

Answer :D
48.

in areversible reactiontheenergyofactivationof theforwardreactionis 50 kcal . the energyof activationfor thereverse reaction will be

Answer»

lt 50 kcal
50kcal
either greater tan or lessthan50 kcal
gt 50 kcal

SOLUTION : theactivation energyof areaverse reactiondecidewhetaher the givenreactionisexothermic orendothmicso the energyof activationof reversereactioniseither greateror lessthan50 kcalin CASEOF exothermic reactiontheactivationenergyforreverse REACTION is morethanactivationenergy oftah forward reactionandin caseof endothermicreactiontheactivation ENERGY for reversereactionis lessthan activation energy of theforward reaction .
49.

In a reversible reaction , the enthalpy change and the activation energy in the forward direction are respectively -x kJ mol^(-1) and y kJ mol^(-1) is

Answer»

y-X
(x + y)
(x-y)
`-x-y`

ANSWER :B
50.

In a reversible reaction, the enthalpy change and the activation energy in the forward direction are respectively -xkJmol and y kJ mol ^(-1) . Therefore , the energy of activation in the backward direction is ........

Answer»

`(y-x) "KJ MOL"^(-1)`
`(x+y)J mol^(-1)`
`(x-y)kJ mol^(-1)`
`(x+y)xx10^3J mol^(-1)`

SOLUTION :
`(x+y)"kJ mol"^(-1)`
`(x+y) xx10^3"J mol"^(-1)`