Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Give the significance of a 'lattice point.

Answer»

Solution :The location of the constituent PARTICLES of a solid is CALLED LATTICE point. The constituent particles could be an atom, MOLECULE or ion.
Discussion
2.

Give the significance of (+) sign in the name D-(+)-glucose.

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SOLUTION :(+)SIGN INDICATES dextro-rotatory NATURE of GLUCOSE.
Discussion
3.

Give the schematicrepresentation of linear polymers, branchedchain polymer and crossintermolecular forces of elastomersand fibres.

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SOLUTION :
Discussion
4.

Glucosegivessilvermirrorwith Tollen's reagent . It showsthe presence of ………. .

Answer»

an ACIDIC GROUP
an alcoholicgroup
a ketonicgroup
an ALDEHYDICGROUP

ANSWER :D
Discussion
5.

Give the ring-chain tautomers of 4-ketopentanoic acid (Laevulic acid):

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SOLUTION :
Discussion
6.

Glucose gives silver mirror with ammoniacal nitrate because it has

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aldehyde group
ester group
ketone group
ALCOHOLIC silver NITRATE

Solution :GLUCOSE gives silver MIRROR with AMMONIACAL silver nitrate because the presence of -CHO group (aldehyde group) in the structure of glucose.
Discussion
7.

Give the resonating structures of NO_(2)and N_(2)O_(5)

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SOLUTION :
Discussion
8.

Glucose gives test with :

Answer»

TOLLEN's reagent
Fehling's solution
Benedict's solution
All

Answer :D
Discussion
9.

Glucose gives silver mirror test with Tollen's reagent.It shows the presence of

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an ACID group
an ALCOHOLIC group
a ketonic group
an aldehydic group.

Solution :GLUCOSE being an ALDEHYDE reduces TOLLENS reagent.
Discussion
10.

Give the resonating structures of NO_(2) and N_(2)O_(5).

Answer»

SOLUTION :RESONATING structures of `NO_(2)`

Reasonating STRUCTURE of `N_(2)O_(5)`
Discussion
11.

Glucose gives positive test with

Answer»

FEHLING's solution
Tollens' reagent
SCHIFF's reagent
Sodium bisulphite.

Solution :Glucosedoesn.treact with Schiff reagentand sodiumbisulphitebecausesignificantconcentration of -CHO group is REQUIRED for thesetests.
Discussion
12.

Give the resonating structures of NO_2and N_2O_5

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SOLUTION :
Discussion
13.

Glucose gives silver mirror test with Tollen's reagent. It shows the presence of

Answer»

CARBOXYLIC GROUP
ALCOHOLIC group
Ketonic group
ALDEHYDIC group

Answer :D
Discussion
14.

Give the resonating structures of NO_2 and N_2O_5 .

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SOLUTION :RESONATING STRUCTURES of `NO_2` are :
Discussion
15.

Give the resonance structure of carboxylate anion.

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SOLUTION :
Discussion
16.

Glucose gives many reactions of aldehyde because:

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It is hydrolysed to acetaldehyde
It is a polyhydroxy ketone
It is a CYCLIC aldehyde
It is a HEMIACETAL in equilibrium with
its aldehyde FORM in solution

Answer :B
Discussion
17.

Give the relationship between the following paris of compounds.

Answer»


Answer :(a) functional ISOMERS(B) ENANTIOMERS(c) Geometrical isomers(d) Diastereomers
Discussion
18.

Glucose gives many reactions of aldehyde, because

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It is hydrolysed to acetaldehyde
It is POLYHYDROXY ketone
It is a cyclic aldehyde
It is a HEMIACETAL in EQUILLIBRIUM with its aldehyde FORM in solution

Solution :It is a hemiacetal in equilibrium with its aldehyde form in solution.
Discussion
19.

Give the relationship between the equivalent weight and molecular weight of KMnO_(4) in ( a) acidic (b) alkaline and (c ) neutral media.

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Solution :(a) `E = M //5` (b) In STRONGLY ALKALINE medium, `E= M` . In WEAKLY alkaline medium `E= M//3`(c ) `E = M//3`. Refer to page.
Discussion
20.

Glucose + Fructose+ Monnose underset("(Excess)")overset(PhNHNH_(2))rarr How many osazone ?

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SOLUTION :N//A
Discussion
21.

Glucose, fructose, galactose, mannose, sucrose.

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SOLUTION :SUCROSE. It is a DISACCHARIDE WHEREAS other are MONOSACCHARIDES.
Discussion
22.

Give the relationship between molar conducitivity and specific conductivity.

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SOLUTION :`wedge_(m)=kappaxx(1000)/(M)`, where `KAPPA` is specific conductivity in S `cm^(-1)` and M is the MOLAR concentration in mol `L^(-1)`, `wedge_(m)` is in S `cm^(2)mol^(-1)`
or `wedge_(m)=(kappa)/(M)` where `kappa` is S `m^(-1)`, M is in mol `m^(-3),wedge_(m)` is in S `m^(2)mol^(-1)`.
Discussion
23.

Glucose froms an oxime but glucose pentaacetate does not. Explain.

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SOLUTION :Glucose reacts with `NH_2OH` VIA the OPEN chain form which has the free `-CH=O` group to form glucose oxime. Glucose pentaacetate , on the otherhand , cannot be CONVERTED into the open chain form because its anomeric hydroxyl group (i.e., `C_1-OH`) is acetylated and HENCE does not form the oxime.
Discussion
24.

Give the relationship between equivalent and molar conductance of a givne solution?

Answer»

Solution :`wedge_(m)=KAPPA=(1000)/("MOLARITY") and wedge_(EQ)=kappaxx(1000)/("Normality")therefore(wedge_(m))/(wedge_(eq))=kappaxx("Normality")/("Molarity")`
Discussion
25.

Glucose reacts with acetic anhydride in the pressence of pyridine to give

Answer»

di ACETATE
TETRA acetate
PENTA acetate
hexa acetate

SOLUTION :penta acetate
Discussion
26.

Give the relation between solublity of gas in liquid and Henry's constant.

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Solution :Higher the VALUE of `K_(H)` at a given PRESSURE the lower is the solubility of the gas in the liquid.
Discussion
27.

Explain the reduction of nitro methane in different medium.

Answer»

SOLUTION :Nitro METHANE on REDUCTION with `Zn"/"NH_4Cl` (nuetral medium reduction) will give ethyl hydroxylamine as product.
`{:(CH_3NO_2+4[H]overset(Zn"/"NH_4Cl)(to)CH_3NHOH+H_2O),("Methyl hydroxylamine "):}`.
Discussion
28.

Glucose forms many derivatives. The derivative which will help to prove the furanose structure is:

Answer»

OSAZONE
Benzoyl
Acetyl
Isopropylidene

Answer :C
Discussion
29.

Give the reason which prompted Bartlett to prepare first noble gas compound.

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SOLUTION :Bartlett observed that ionisation enthalpies of Xe and `O_2` are similar. After the PREPARATION of `O_2^(+)PtF_6^(-)` was reported, `O_2^(+) PtF_6^(-)` was reported , he thought `Xe^(+) PtF_6^(-)` compound could be PREPARED (Xe in PLACE of `O_2`).
Discussion
30.

Glucose forms many derivatives. The derivative which will help to prove the furanose structure is

Answer»

Acetyl
Benzoyl
Osazone
Isopropylidene

Solution :Formation of isopropylidene DERIVATIVE requires the presence of two adjacent free OH group in cis-orientation which is present only in the furnaose form and HENCE isopropylidene formation proves the presence of FURANOSE form.
Discussion
31.

Give the reduction of nitromethane in (a) acid medium, (b) neutral medium.

Answer»

Solution :NITRO METHANE on REDUCTION with `Sn"/"HCl` (ACID medium reduction) produce methylamine as product.
`{:(CH_3NO_2+6[H]overset(Sn"/"HCl)(to)CH_3-NH_2+2H_2O),(" Nitro methaneMethylamine "):}`.
Discussion
32.

Glucose form hemiacetal between CHO group and -OH group on

Answer»

C-2
C-3
C-4
C-5

Answer :D
Discussion
33.

Give the reason for the formation of a light yellow or white ppt. in the group II even if it may not be because of some metal ion.

Answer»

Solution :Yellow or WHITE PPT. is formed due to the oxidation of `H_(2)S` GAS by some oxidising agents to sulphur which FLOATS on the surface
`BaSO_(3)+2HCl+2H_(2)StoBaCl_(2)+3H_(2)O+underset(("yellow"))(3S)`
`2NaNO_(2)+H_(2)S+2HClto2NO+2NaCl+2H_(2)O+underset(("yellow"))(S)`
`2FeCl_(3)+H_(2)Sto2FeCl_(2)+2HCl+underset(("Yellow"))(S)`
Discussion
34.

Give the reason for the bleaching action of Cl_(2)

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Solution :In presencee of moisture or in aqueous solution, `Cl_(2)` libertes NASCENT oxygen.
`Cl_(2) + H_(2)O rarr 2 HCl underset("Nascent oxygen")([O])`
This nascent oxygen BRINGS about the oxidation of coloured substances PRESENT in vegetable and organic matter to colourless substances.
Coloured SUBSTANCE + O `rarr` Colourless substance
Thus, the bleaching action of `Cl_(2)` is due to oxidation. Since the bleaching effect of `Cl_(2)` is permanent, it is used to bleach cotton and textiles and WOOD pulp for manufacture of paper and rayon.
Discussion
35.

Glucose does not reacts with

Answer»

`Br_(2)/H_(2)O`<BR>`H_(2)NOH`
HI
`NaHSO_(3)`

Solution :`NaHSO_(3)`
Discussion
36.

Glucose fails to react with A) NaHSO_(3) B) Schiff’s reagent C) PhNHNH_(2) D) Br_(2).H_(2)O

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A,B
A,C
B,D
C,D

Answer :A
Discussion
37.

Give the reason for the bleaching property of chlorine.

Answer»

Solution :In aqueous solution or in presence of moisture, chlorine liberates nascent oxygen `Cl_2+H_2Oto2HCl+[O]` This nascent oxygen brings about oxidation of coloured SUBSTANCES PRESENT in vegetable and organic MATTER to COLOURLESS substances.
Discussion
38.

Give the reason for bleaching action of Cl_2.

Answer»

Solution :`Cl_2` in presence of moisture produces NASCENT hydrogen which is RESPONSIBLE for bleaching PROPERTY.
`Cl_(2) + H_(2)O to underset(HCl + [O])(HOCl) + HCl`
Coloured matter `+ [O] to` Colourless
Discussion
39.

Give the reason for bleaching action of Cl_(2). (with reaction)

Answer»

Solution :`{:(Cl_(2)+H_(2)OrarrHCl+HOCl),("HOCl"RARR HCl+[O]),(barul(""Cl_(2)+H_(2)Orarr2HCl+[O]" " )"NASCENT OXYGEN"),("Wet coloured material "+[O]rarr"colourless"):}`
Discussion
40.

Glucose does not give violet colour with

Answer»

`NaHSO_(3)`
Tollen's REAGENT
FEHLING's SOLUTION
SCHIFF's reagent

Solution :Schiff.s reagent
Discussion
41.

Give the reason for bleaching action of Cl_2

Answer»

Solution :In PRESENCE of moisture or in aqueous solution, `Cl_2` liberates nascent oxygen.
`Cl_2 + H_2O to 2HCl + UNDERSET("Nascent oxygen")([O])`
This nascent oxygen brings about the oxidation of coloured substances PRESENT in vegetable and organic matter to convert them to colourless substances.
Coloured SUBSTANCE + O ` to` Colourless substance
Thus, the bleaching action of `Cl_2` is due to oxidation.
Discussion
42.

Glucose does not give2,4- DNPtest , Schiff's test or does not give sodium bisulphite adduct. Give reacsons. Or Despire having an aldehyde group, glucose not give 2,4-DNP test ? What does this indicate ?

Answer»

Solution :Although the open chain structure of glucose does contains an aldehyde group , yetit does not give certain characteristic reactions of the `-CHO` group. Fro example, it neither with2,4-dinitrophenylhydrazine to form a 2,4-DNP derivative nor it gives Schiff's test not it REACTS with a concentrated solution of sodium bisulphite to give sodium bisulphate adduct. (The reason being that glucose actually exists in the CYCLIC hemiacetal form with only a small amount `(LT 0.05 %)` of the open chain form. Since the concentration of therefore , formation of 2,4-DNP derivative or `NaHSO_3` adduct or observation of Schiff's test cannot disturb the equilibrium to regenerate more of the open chain form from the cyclic hemiacetal form and hence does not give these TESTS.
Discussion
43.

Give the reactions of nitrous acid with primary secondary and tertiary amines.. (b) Name the products with chemical reactions when the following compounds are hydrolysed: (i) CH_(3)CJH_(2)CN woth dil. HCl (ii) CH_(3)CN with alkaline H_(2)O_(2) (iii) C_(2)H_(5)NC with di. HCl (iv) C_(2)H_(5)NO_(2) with dil. HCl (c ) Explain the formation of the mixture of (i) PhCH_(2)CHO and (ii) PhCOMePh(CHOH)CH_(2)NH_(2) (A) is treated with nitrous acid (d) How nitrobenzene is identified by using Mulliken-Baker test?

Answer»

SOLUTION :

Discussion
44.

Glucose does not react with

Answer»

`Br_2//H_2O`
`NH_2OH`
`(CH_3CO)_2O`
`NaHSO_3`

ANSWER :D
Discussion
45.

Give the reason for bleaching action of Cl_(2).

Answer»


SOLUTION :(i) Bleaching action of `Cl_(2)` is due to its oxidising PROPERTY.
(ii) In aqueous solution, `Cl_(2)` liberates nascent oxygen which brings about the oxidation of coloured substances present in vegetables and organic matter to colourless substances.
`Cl_(2)+H_(2)O rarr 2HCl+[O]`
Coloured substance `+ [O] rarr` colurless substance.
Discussion
46.

Glucose dissolves in water to give a neutral solution. What information do you get from this with regard to the structure of glucose?

Answer»

Solution :This INDICATES that the glucose molecule does not CONTAIN a carboxyl group.
`-overset(O)overset(||)"C"-H`
Discussion
47.

Give the reagents in the following reactions:

Answer»

Solution :(a) `1. Br_(2)+FE,2. Sn+HCl, overset(Θ)H`
`3. HNO_(2),0-5^(@)C,4. CUBR`
(b) `1. Sn+HCl,2.Ac_(2)O`
`3. HNO_(3)+H_(2)SO_(4) ,4. overset(Θ)(O)H`
`5. Br_(2)+Fe,6. HNO_(2),0-5^(@)C`
`7. CuBr,8. Sn+HCl:overset(Θ)(O)H`
`9.HNO_(2),0-5^(@)C,10 H_(3)PO_(2)`
(c) `1. Br_(2)+Fe, 2. overset(Θ)(O) H`
`3.HNO_(2),0-5^(@)C,4. CuBr`
(d) `1. Br_(2)+Fe,2. Sn+HCl:overset(Θ)(O)H`
`3. HNO_(2),0-5^(@)C,4.H_(3)PO_(2)`
(E) `1.Sn+HCl,2. Ac_(2)O`
`3.Br_(2)+Fe,4. overset(Θ)(O)H`
`5.HNO_(2),0-5^(@)C,6. CuBr`
f. `1.Br_(2)+Fe,2.HNO_(2),0-5^(@)C`
`3.H_(3)PO_(2)`
Discussion
48.

Give the reactions of alcohols with phosphorus halides.

Answer»

Solution :`to` Alcohols react with PHOSPHORUS halides such as `PCI_(5), PCI_(3), Pl_(3)` etc. to form corresponding alkyl halides. Phosphorus tribromides and phosphorus tri-iodides are prepared in situ during the REACTION by ACTION of phosphorus on bromine and iodine.
`3R - OH + P_(3)(X = Br, I) to 3R – X + H_(3)PO_(3)`
`R - OH + PCl_(5) to R - Cl + POCI_(3) + HCI`
Discussion
49.

Glucose contains in addition to aldehyde group

Answer»

ONE secondary OH and FOUR primary OH GROUPS
One primary OH and four secondary OH groups
Two primary OH and THREE secondary OH groups
Three primary OH and two secondary OH groups

Solution :
Discussion
50.

Give the reaction prodcuts when acetophenon, acetaldehyde and cyclohexane undergo reaction with diazomethane.

Answer»

Solution :The products of the GIVEN reactions are as FOLLOWS :
`Ph= overset(O) overset(||)(C)-CH_(3) overset(CH_(2)N_(2)) to Ph-CH_(2)- overset(O) overset(||)(C)-CH_(3)`
`CH_(3)overset(O)overset(||)(C)-H overset(CH_(2)N_(2))toH_(2)C-overset(O) overset(||)(C)-CH_(3)`
Discussion