Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Give the reaction of hydroxyl group with chlorobenzene.

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Solution :Chlorobenzene can be converted into phenol by heating in aqueous sodium hydroxide solution at a temperature of 623 k and a pressure of 300 atmospheres.

The EFFECT is pronounced when `(-NO_(2))` GROUP is introduced at ortho and para positions. HOWEVER, no effect on REACTIVITY of haloarenes is OBSERVED by the presence of electron with drawing group at meta - position.
Discussion
2.

Glucose can't be classified as

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hexose
carbohydrate
aldose
oligosaccharide

Solution :GLUCOSE is ALDOHEXOSE. Glucose is a monosaccharide, i.e. it can not be HYDROLYSED further to simple sugars. Oligosaccharides on hydrolysis GIVE 2-10 molecules of monosaccharides.
Discussion
3.

Give the reaction for the preparation of phenol from cumene.

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SOLUTION :Phenol can be PREPARED from CUMENE in the following STEPS :
Discussion
4.

Glucose contains :

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One-CHO group
Five -OH groups
One primary ALCOHOLIC group and four secondary ALCOHOL groups
All are correct

Answer :D
Discussion
5.

Give the properties of inter halogen compounds.

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Solution :PROPERTIES of inter halogen compounds:
(i) The central atom will be the larger one.
(II) It can be formed only between two halogen and not more than two halogens.
(iii) Fluorine can.t act as a central metal atom being the smallest one.
(iv) Due to HIGH ELECTRONEGATIVITY with small size fluorine helps the central atoms to attain high COORDINATION number
v. They can undergo the auto ionization.
vi. They are strong oxidizing agents.
Discussion
6.

Give the products of the reaction : "Product of reaction (d)" underset(DMF)overset(NaCN)to

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SOLUTION :
Discussion
7.

Givethe products of thereactionof styreneoxidewith (a)NaSH (b)LiAID_(4) ( c) MeOH // H^(+) ( d) HBr(1 eq)

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SOLUTION :
Discussion
8.

Glucose cannot be classified as:

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A hexone
A carbohydrate
An oligosaccharide
An aldose

Answer :C
Discussion
9.

Give the products of the reaction :

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SOLUTION :
Discussion
10.

Glucose can be classified as

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aldohexose
carbohydrate
reducing sugar
monosaccharide.

Answer :A::B::C
Discussion
11.

Give the products of the reaction :

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SOLUTION :
Discussion
12.

Glucose and urea are generally ……………….. under room temperature.

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SOLUTION :SOFT SOLIDS
Discussion
13.

Give the products of the reaction :

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SOLUTION :
Discussion
14.

Glucose and sucrose can be distinguished by ..........or ..............solution.

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SOLUTION :TOLLENS' REAGENT or FEHLING's solution
Discussion
15.

Give the products of the reaction :

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SOLUTION :
Discussion
16.

Glucose and Sucrose are soluble in water but cyclohexane or benzene are insoluble in water. Explain.

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SOLUTION :Glucose contain five -OH groups and SUCROSE contains eight -OH groups in their molecules. These -OH groups from HYDROGEN bonds with water. So glucose and sucrose are soluble in water.
But CYCLOHEXANE and benzene do not contain -OH groups. So they cannot form hydrogen bonds with water and are insoluble. MOREOVER, cyclohexane and benzene are non-planar compounds and such compounds do not dissolve in polar solvents like water.
Discussion
17.

Give the products of the reaction :

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SOLUTION :no REACTION (or POSSIBLE DEHYDRATION)
Discussion
18.

Glucose and mannose are

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EPIMERS
Anmers
CONFORMERS
FUNCTIONAL ISOMERS

ANSWER :A
Discussion
19.

Give the products of the reaction :

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SOLUTION :
Discussion
20.

Glucose and mannose are…….. .

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epimers
anomers
KETO HEXOSES
DISACCHARIDES

ANSWER :A
Discussion
21.

Give the products of the reaction :

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SOLUTION :
Discussion
22.

Glucose and mannose are :

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Keto-hexoses
ANOMERS
EPIMERS
Disaccharides

Solution :GLUCOSE and MANNOSE are C-3 Epimer
Discussion
23.

Give the products of the reaction :

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SOLUTION :
Discussion
24.

Glucose and fructose give the same osazone ? Explain.

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Solution :During osazone formation , the reaction OCCURS only at `C_1` and `C_2` while rest of the MOLECULE REMAINS intact, Since glucose and fructose differ from each other only in the ARRANGEMENT of ATOMS at `C_1` and `C_2`, therefore , they give the same osazone.
Discussion
25.

Give the products of the reaction :

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SOLUTION :
Discussion
26.

Glucose and glycine.

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Answer :GLUCOSE gives positive test with tollen's reagent and FEHLING SOLUTION while GLYCINE does not give these tests.
Discussion
27.

Give the products of the reaction :

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SOLUTION :
Discussion
28.

Give the products of the following reactions HC-=C CH_(2)CH_(2)CH_(3)underset(Delta)overset(KMnO_(4))rarrZ

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Solution :`X:(CH_(3))_(2)CHCOOH+HOOC CH_(2)CH_(2)CH_(3)`
`Y:2CH_(3)CH_(2)COOH`, SYMMETRICAL internal ALKYNES give one acid
`Z:CH_(3)COOH+HOOC CH_(2)CH_(2)COOH+HOOC CH_(2)CH_(3)`
Discussion
29.

Glucose and fructose differ in :

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Taste
Action of heat
Action of TOLLEN's reagent
Direction of OPTICAL rotation

Answer :D
Discussion
30.

Give the products of the following reactions CH_(3)CH_(2)C-=C CH_(2)CH_(3)underset(Delta)overset(KMnO_(4))rarrY

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SOLUTION :`X:(CH_(3))_(2)CHCOOH+HOOC CH_(2)CH_(2)CH_(3)`
`Y:2CH_(3)CH_(2)COOH`, symmetrical internal alkynes give one ACID
`Z:CH_(3)COOH+HOOC CH_(2)CH_(2)COOH+HOOC CH_(2)CH_(3)`
Discussion
31.

Glucose and fructose can be distinguished by

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Lucas TEST
NINHYDRIN test
Benedict reagent test
All the above

Answer :C
Discussion
32.

Give the products of the following reactions CH_(3)C-=C CH_(2)CH_(2)C-=C CH_(2)CH_(3)underset(Delta)overset(KMnO_(4))rarrW

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Solution :`X:(CH_(3))_(2)CHCOOH+HOOC CH_(2)CH_(2)CH_(3)`
`Y:2CH_(3)CH_(2)COOH`, symmetrical INTERNAL ALKYNES give one acid
`Z:CH_(3)COOH+HOOC CH_(2)CH_(2)COOH+HOOC CH_(2)CH_(3)`
Discussion
33.

Glucose and fructose consists of aldehydic and ketonic functional groups respectively, yet fehlings reagent cannot be used to distinguish them, why?

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Solution :Because in ALKALINE MEDIUM, FRUCTOSE isomerizes to glucose, thereby ANSWERING Fehling.s TEST.
Discussion
34.

Give the products of the reaction :

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SOLUTION :
Discussion
35.

Give the products of the reaction :

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SOLUTION :
Discussion
36.

Glucose and fructose are readily distinguished by using :

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MOLISCH test
Saliwanoff test
Tollen.s reagent
None of these

Answer :B
Discussion
37.

Give the products of the following reactions (CH_(3))_(2)CHC-=C CH_(2)CH_(2)CH_(3)underset(Delta)overset(KMnO_(4))rarrX

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Solution :`X:(CH_(3))_(2)CHCOOH+HOOC CH_(2)CH_(2)CH_(3)`
`Y:2CH_(3)CH_(2)COOH`, symmetrical INTERNAL alkynes give ONE acid
`Z:CH_(3)COOH+HOOC CH_(2)CH_(2)COOH+HOOC CH_(2)CH_(3)`
Discussion
38.

Give the products of nitrobenzene when it is reacted with the following: a. Pd//H_(2) b. P//HI c. Fe//HCl d. PPh_(3) e. PhNH_(2) f. PhCH_(2)CN g. NH_(2)OH h. RMgBr//H_(2)O

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Solution :

a,b,c and d are reduction produicts , e,f and H are congdentionproducts in which NITROSO group NO BEHAVE like CARBONYL group.
Discussion
39.

Glucose and fructose are chain isomers.TRUE/FALSE

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ANSWER :GLUCOSE and FRUCTOSE are FUNCTIONAL ISOMERS.
Discussion
40.

Give the products of the following: i. Benzene + Cylohexanol (BF_(3), 60^(@)C) ii. Benzene + CH_(2) = CHCH_(2)Cl (ZnCl_(2)) and H_(2)SO_(4) iii. Benzene + Ethylene oxide + AlCk_(3) iv. Benzene + CH_(2)Cl_(2) + alCl_(3) rarr (A) (B) overset(C_(6)H_(6) + AlCl_(3)|)(larr) v. Benzene + ClCH_(2)CH_(2)Cl + AlCl_(3) rarr (C) (D) overset(C_(6)H_(6)+ AlCl_(3)|)(larr) vi. Benzene + Phosgene (COCl_(2)) overset(AlCl_(3))(rarr) (E) overset(H_(3)O^(o+))(rarr) (F) vii. Toulene + Maloncianthydride overset(AlCL_(5)(rarr) (A) underset(H_(3)PO_(4))(rarr) (B) underset(HCl) overset(Zn-Hg)(rarr) (C) viii. Explain how alkyl benzene naphalene, anthracene and phenanthrene can bedistinguished form one another F.C. reaction ?

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Solution :

VIII. Any aromatic compound that can be alkylated in `F.C`. Reaction gives a DISTINCTIVE colour when treated with `CHCl_(3) + AlCl_(3)`. The colouris due to the formation of `Ar_(3)C^(o+)AlCl_(4)^(o+)`. as sjpwm.

Benzene derivaties give an orange to RED colour, naphalenes give bluwe anthrancenes givegreen, and phenantheres give PURPLE.
Discussion
41.

Glucose and fructose are :

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CHAIN isomers
Position isomers
Functional isomers
Optical isomers

Answer :C
Discussion
42.

Give the products of the following:

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Solution :a. `LAH` reduce both the

and `(-COOH)` GROUPS to ALCOHOL, while `NaBH_(4)` reduces only

(b) LAH reduces both the (-CH=O) and ester (-COOMe) groups to alcool, while `NaBH_(4)` reduces only the (-CH=O) group
Discussion
43.

Glucose and fructose

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Answer :Glucose declourises and colour of `Br_(2)` WATER and oxidised to Gluconic acid.
Fructose does not REACT with `Br_(2)` water.
Discussion
44.

Give the products of the following and the name of the reactions:

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Solution :
d. Clemmensen reduction is acid sensitive, so it would reduce `(C=O)` to `(-CH_(2))` GROUP and simultaneously dehydration of alcohol will OCCUR.

e. Wolff-Kishner reduction is base sensitive, so it would reduce `(C=O)` to `(-CH_(2)-)` group and simultaneously dehydrohalogenation of `RX` will occur.

f. Both `LAH` and `NaBH_(4)` reduce `(-CH=O)` group tp `(-CH_(2)OH)` group. But `lAH` reduces `1^(@)` and `2^(@) RX` to `RH`, but `NaBH_(4)` does not reduce `1^(@) RX`, whereas both `LAH` and `NaBH_(4)` do not reduce `ArX`.

g. `LAH` reduces `R-NO_(2)` (aliphatic nitro group) to `R-NH_(2)`, and `Ar-NO_(2)`(aromatic nitro group) to `Ar-N=N-Ar` (azo group), whereas `NaBH_(4)` does not reduce either of them.

h. Ranet `Ni`, under high temperature and pressure, reduces all the double bonds of the benzene ring.

i. Under the given conditions, all the double bonds of the benzene are REDUCED.

j. It is a Birch reduction and reduces one double bond of the benzene ring to give a compound containing containing isolated diene.

k. Lindlar's catalyst converts `(C=C)` to `(C=C)` bond to give cis-alkene `(syn-addition of H_(2))`, whereas Birch reduction `(Na+liq.NH_(3)+EtOH)` converts `(C-=C)` to `(C=C)` bond to give trans-alkene (anti-addition of `H_(2))`
Discussion
45.

Give the products of a. p-Benzoquinone and b. PhCH=CH-CHO with i. H_(2)+Pt ii. H_(2)+Pd-C (1 atm) iii. LAH iv. NaBH_(4) v. Zn+HAc vi. NH_(2)NH_(2)+KOH+glycol+Delta vii. HI+P viii. LAH+AlCl_(3) ix. (Me_(2)CHO-)_(3) Al+Me_(2)CHOH x. Li or Na, liq. NH_(3)+EtOH xi. Na+EtOH

Answer»

Solution :
Birch reduction only TERMINAL `(==)` bond with `CHO` group, it is terminal `(=)` bond.
(Birch reduction does not reduce ISOLATED double bond and ALSO `gt C=0` group.)
Discussion
46.

Glucose and fructose :

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Are ISOMERIC COMPOUNDS
Are POLYHYDROXY compounds
SHOWS epimerization
All

Answer :D
Discussion
47.

Give the products in the carbylamine reaction of ethylamine.

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SOLUTION :The REACTION is as follows :
`CH_(3)-CH_(2)-NH_(2) OVERSET(CHCl_(2)) underset(KOHDelta)to(A) overset(H_(2)O)to(B)+C`
`A=CH_(3)-CH_(2)-overset(+)N-=barC B=CH_(3)-CH_(2)-NH_(2)C=HCO_(2)H`
Discussion
48.

Glucose and cane sugar can't be distinguished by

Answer»

FEHLING's solution
BAEYER's reagent
Tollens' reagent
Benedict's solution

ANSWER :B
Discussion
49.

Give the products expected(if any) when ethylbenzene reacts under the following conditions. (A) Br_(2) in C Cl_(4) (dark) (B) HNO_(3), H_(2)SO_(4) (C) conc. H_(2)SO_(4) (D) C_(2)H_(5)-overset(O)overset("||")(C)-Cl, AlCl_(3) (1.1 equiv.) then H_(2)O (E) CH_(3)Br, AlCl_(3) (F) Br_(2), FeBr_(3)

Answer»


ANSWER :`(##MOT_CON_JEE_CHE_C05_E03_012_A01##)`
Discussion
50.

Glucose and cane sugar can be distinguished by:

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Fehling.s solution
Baeyer.s reagent
Molisch.s test
Iodine solution

Answer :A
Discussion