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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
For the adsorption of a gas on a solid, the plot of log(x/m) versus log P is linear with slope equal to: |
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Answer» k |
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| 2. |
For the adsorption of a gas on a solid, the plot of log(x/m) versus log p is linear with slope equal to |
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Answer» k |
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| 3. |
For the adsorption of solution on a solid surface x/m = kc^(1//n). Adsorption isotherm of "log" (x/m) vs log C was found of the type (Fig). This is when C = ........ |
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Answer» |
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| 4. |
For the adsoprtion of a gas on a solid, the plot of log ""x/m versus log P is linear with slope equal to ( n is whole number)" |
| Answer» ANSWER :D | |
| 5. |
For the adiabatic expansion of an ideal gas: |
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Answer» `PV^gamma`=CONSTANT |
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| 6. |
For tetrahedral coordination number , the radius ratio, r^(+) //r^(-) is : |
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Answer» `0.225-0.414` |
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| 7. |
For tetrahedral co-ordination, the radius ration ( r_(+)//r_(-)) should be : |
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Answer» 0.155-0.225 |
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| 8. |
For testingsodium carbonatesolutionfor thepresent of suplhiate ions as impuritiesone should add : |
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Answer» Excess hydrochloric acid andsilvernitrate solution |
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| 9. |
For testing SO_(4)^(2-) with BaCl_(2) solution why should sodium carbonate not be acidified with too much of conc. HCl. |
| Answer» Solution :In the PRESENCE of CONC. HCL, `BaCl_(2)` itself will be precipitated the precipitated `BaCl_(2)` is mistaken as `BaSO_(4)` | |
| 10. |
For testing nitrogen in organic compounds, they are fused with sodium metal, extracted with water, and treated with FeSO_4 soln. and acidified.The presence of nitrogen is indicated by a blue or green colour or precipitate . This test is not given by |
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Answer» UREA |
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| 11. |
Forsubstrates in column- I match the number of mol of CH_(3)MgX required per mol. |
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Answer» |
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| 12. |
For synthetic polymer which of the following is correct option ? |
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Answer» `barM_(W)gtbarM_(N)` |
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| 13. |
For substance having orthorhombic crystalline system edge length would be a ne b ne cand angles are .... |
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Answer» `alpha = beta = gamma ne90^@` |
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| 14. |
For strong electrolytes, the plot or molar conductance versus sqrt(C) is: |
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Answer» parabolic |
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| 15. |
For strong reducing agent which of the following is true statement ? |
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Answer» Its REDUCTION POTENTIAL is less. |
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| 16. |
For strong electrolytes the molar conductivity increases on dilution and reaches a maximum value at infinite dilution. Justify this statement. |
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Answer» Solution :For a strong electrolyte, at high concentration , the number of constituent ions of the electrolyte in a given volume is high and HECE the attractive force between the oppositely charged ions is also high. The ions also EXPERIENCED a viscous drag due to GREATER solvation. These factors attribute for the low molar conductivity at high concentration. When the dilution increases, the ions are far APART and the attractive forces decreases. At infinite dilution, the ions are so far apart, the interaction between them becomes insignificant and HENCE the molar conductivity increases and reaches a maximum value at infinite dilution. |
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| 17. |
Forsterlization and perservation of squashes which one of the following is used ? |
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Answer» Chlorine |
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| 18. |
For spontanity of a cell, which is correct ? |
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Answer» `DELTAG = 0 , DELTAE = 0` |
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| 19. |
For spontaneous reaction ,the change in free energy should be… |
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Answer» positive |
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| 20. |
For some reactionsthe standard reduction potentials are given below : Zn^(2+) + 2 e to Zn , "" E^(@) = -0.762 V Fe^(2+) + 2e to Fe , "" E^(@) = -0.440 V Cu^(2+) + 2e to Cu ,"" E^(@) = + 0.345 V Ag^(+) + e to Ag "" E^(@) = + 0.800V Which one of the following is most easily oxidised ? |
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Answer» Zn |
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| 21. |
For spontaneity of a cell, which is correct |
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Answer» `DeltaG=0, E^(@)=0` For SPONTANEITY `(DeltaG=-ve)` `becauseDeltaG=-ve, DeltaE=+ve`. |
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| 23. |
For spontaneity of a cell, which is correct? |
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Answer» `DELTAG= 0.DeltaE=0` |
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| 24. |
For solution of weak electrolytic, the degree of ionization |
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Answer» Will be RECIPROCAL to the dilution |
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| 25. |
For solid hArr liquid equilibrium, the correct statements, when forward reaction predominates is : 1. Increase in pressure if solid is ice 2. Decrease in pressure if solid is ice 3. Decrease in pressure if solid is other than ice 4. Increase in temperature if solid is ice 5. Decrease in temperature if solid is ice |
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Answer» `1,2,3` Also melting INCREASES with increases in TEMPERATURE. |
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| 26. |
For solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fration of M in solution is shown in the following figure. Here X_(L)" and " X_(M) represent mole fractions of L and M, respectively, in the solution, The correct statement(s) applicable to this system (are) |
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Answer» The point Z represents VAPOUR pressure of liquid M and Raoult's law is obeyed form `X_(L)=0 " to " X_(L)=1`  (b,d) For ideal solution obeying Raoult's law. `P_(L)=(1-X_(M))P_(L)^(@)-X_(M)P_(L)^(@)` `"Graph betwee"P_(L)&"slope=-ve` Since the solution EXHIBITS position exhibits Raoult's Law. L-M interaction`ltL-L & M -M` interactions point Z represents intercept intercept whic is `P_(L)^(@)"when" X_(L)to 1`. Thus, both statements (b) and (d) are correct. |
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| 27. |
For SO_(2)Cl_(2(g))toSO_(2(g))+Cl_(2(g)), time required for 99.9% completion of the process is found to be 100 sec, then specific rate ? |
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Answer» `6.93xx10^(-3)M.s^(-1)` |
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| 28. |
For SO_2Cl_2(g)to SO_2(g) + Cl_2(g)Pressures of SO_2Cl_2 att = 0 and t =20 minutes respectively are 700 mm & 350 mm. When log (P_0//p)is plotted against time (t), slope equals to |
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Answer» `1.505xx10^(-2)s^(-1)` |
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| 29. |
For SO_2Cl_2(g) to SO_2(g) +Cl_2(g) , Pressure of SO_2Cl_2changed from 5 atm to 4 atm in 10 min. Then, pressure of SO_2Cl_2at the end of 30 minutes will be (in atm) |
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Answer» 2.56 |
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| 30. |
For similar orbitals having different values of n: |
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Answer» the most probable distance INCREASES with increases in `N` |
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| 31. |
For silver metal, the threshold frequency v_(0) is 1.13x10^(17)Hz. What is the maximum kinetic energy of the photoelectrons produces by shining U.V light of 15.0Å wavelength on the metal? |
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Answer» `2XX10^(17)J` |
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| 32. |
For selective hydrogenation of alkynes into alkene the catalyst used is |
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Answer» Ni at `250^@` C |
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| 33. |
For s-orbital, 4pi r^(2) Psi_(r)^(2) us r is plotted. Select correct statement (s). Note: S = spherical surface at given distance. P = Point (very small volume) at given distance. |
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Answer» Order of probability of finding an electron at points is `P_(4) gt P_(3) gt P_(2) gt P_(1)`. |
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| 34. |
For same mass of two different ideal gases of molecular weights M_(1) and M_(2) plots oflog V vs lot P at a given constant temperature are shown. Identify the correct option |
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Answer» `M_(1)gtM_(2)` `PV=nRT=w/MRT "" ( :. n=w//M)` For same mass of gases and at constant temperature wRT is constant (K). `:.PV=K/M` TAKING LOG both sides we get `log P+logV="log"K/M` `logV=-logP+"log"K/M` comparing this with straight line equation `y=mx+c` For ideal gas 1, `("Intercept")_(1)="log"K/(M_(1))` for ideal gas 2, `("Intercept")_(2)="log"K/(M_(2))` `:. "log"K/(M_(2))gt"log"K/(M_(1))` (from GRAPH) or `K/(M_(2))gtK/(M_(1))impliesM_(1)gtM_(2)` |
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| 35. |
For second order reaction |
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Answer» `K=(2.303)/(t)LOG.(B(a-x))/(a(b-x))` |
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| 36. |
For reversible and irreversible adiabatic expansion of ideal gas incorrect statement is :- |
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Answer» `(T_(F))_(rev)LT(T_(f))_(IR r)` |
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| 37. |
For reducing one mole of MnO4- ion to Mn2+ ions, the number of Farady of electricity is : |
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Answer» 5 |
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| 38. |
For reducing 1 mole of Fe^(2+) ions to Fe , the number of Faradays of electricity required are: |
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Answer» 2 |
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| 39. |
For reaction x+y+z rarr products the rate law is given by rate =k[x]^(3//2)[y]^(1//2) what is the overall order of the reaction and what is the order of reaction with respect to Z. |
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Answer» Solution :RATE `K[x]^(3//2)[y]^(1//2)` OVERALL order`=(3/2+1/2)=2` i.e, SECOND order reaction . Since it the rateexperience does not contain the concentration of Z, the reaction is zero order with respect to Z . |
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| 40. |
For reactions of metals to form their oxide one gram O_(2) molecule is used may be plotted graphically against temperature Select incorrect using given Ellingham diagram (given above) |
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Answer» At ` 710^(@)C-2CO(g)+O_(2)(g) RARR 2CO_(2)(g), DeltaG^(0)=x kJ//mol` |
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| 41. |
For reaction PCl_3 (g) + Cl_2 (g) ⇌ PCl_5 (g) the value of K_c at 250^oC is 26 mol^(-1) litre^(-1). The value of K_P at this temperature will be : |
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Answer» 0.61 `ATM^(-1)` |
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| 42. |
For reaction ArarrB, the rate constant k_(1)=A_(1)^(-Ea_(1//(RT))) and for the reactio XrarrY, the rate constant k_(2)=A_(2)^(-Ea_(1//(RT))) . If A_(1)=10^(8),A_(2)=10^(10) and E_(a_(1))=600 cal /mol, E_(a_(2))=1800 cal/mol then the temperature at which k_(1)=k_(2) is (Given :R=2 cal/K-mol) |
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Answer» 1200 K |
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| 43. |
For reaction M to M^(n+)+"ne"^(-) |
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Answer» `E=E^(0)+(2.303RT)/(nF)LOG""([M^(n+)])/([M])` |
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| 44. |
For reaction AtoB the rate constant k_(1)=A_(1)e^(-Ea_(1)//RT) and for the reaction PtoQ the rate constant k_(2)=A_(2)e^(-Ea_(2)//RT). If A_(1)=10^(8),A_(2)=10^(10) and E_(a_(1))=600,E_(a_(2))=1200, then the temperature at which k_(1)=k_(2) is |
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Answer» `600/RK` `2.303"log"(10^(8))/(10^(10))=(600-1200)/(RT),2.303xx(-2)=(-600)/(RT),T=600/(2.303xx2xxR)=(600/4.606R))` Kelvin |
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| 45. |
For reaction Ato products, initially 8M ofA is take. In 20 minutes the concentration of Ais reduced to 4M. In next 10 minutes the concentration of A is reduced to 2M. Report the order of the reaction. |
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Answer» |
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| 46. |
For reaction Ararr Bthe rate of reaction incrases by a factor of 1.857 when the concentration of A is increased by 1.5 times . The order of reaction with respect to A is |
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Answer» 1 `n= ("LOG"1.837)/("log"1.5)=1.5` |
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| 47. |
For reaction aA to xP, when [A]=2.2mM, the rate was found to be 2.4m M s^(-1). On reducing concentraion of A to half, the rate changes to 0.6m M s^(-1). The order of reaction with respect to A is |
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Answer» `1.5` |
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| 48. |
For reaction a A tox P , when [A] = 2.2 mM , the rate was found to be 2.4 m M s^(-1) . On reducing concentration of A to half , the rate changes to 0.6 m M s^(-1) . The order of reaction with respect to A is |
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Answer» 1.5 Rate of constant = `[A]^(a)` Order of reaction = a `[A]_(1) = 2.2` mM , `r_(1) = 2.4 m M s^(-1) "" … (i)` `[A]_(2) = 2.2//2 m M , r_(1) = 0.6 m M s^(-1)` or `(2.4)/(4) "" … (ii)` On REDUCING the CONCENTRATION of A to HALF , the rate of reaction is decreased by four times . Rate of reaction = `[A]^(2)` Order of reaction = 2 . |
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| 49. |
For reaction A_((g))toB_((g))+C_((g))+D_((g)) at 750 K the rate constant is 2.3xx10^(-3)"min"^(-1). Starting with a pressure of 400 mm of Hg at this temperature in a closed container how, many minuteswould it take for the pressure in the container to become 760mm Hg (log 11=1.041) |
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Answer» 360 `t_(1)=0}400""0""0""0` `t_(2)=t}400-x""x""x""x` `implies400+2x=760,2x=360,x=180` `Kxt=2.303log((P_(0))/(P_(t))),2.3xx10^(-3)xxt=2.303xxlog(400/220),t=10^(3)xxlog(40/22)` `=10^(3)xx0.2595=259.59` MIN`~=` 260 min |
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| 50. |
For reaction Ag_(2)O(s)rarr2Ag(s)+(1//2)O_(2)(g) the value of DeltaH=30.56 " kJ mol"^(-1) and DeltaS = 0.066 kJK^(-1)mol^(-1). Temperature at which free energy change for reaction will be zero, is |
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Answer» Solution :`DeltaG=DeltaH-TDeltaS` `DeltaG=0` at EQUILIBRIUM `THEREFORE DeltaH=TDeltaS` or `30.56=Txx0.066` T=463 K. |
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