Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Finely divided Nickel is a better adsorbent than Nickel crystal.

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Solution :As the ADSORPTION is a SURFACE PHENOMENON it depends on the surface area of adsorbent. i.e., higher the surface area, higher is the amount adsorbed.
Finely DIVIDED Nickel has LONGER surface area and it is a better adsorbent than Nickel crystal.
2.

Finely divided iron is used as a catalyst in an industrial process. The name of the process is

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CONTACT PROCESS.
Haber's process.
HYDROGENATION process.
Oxidation process.

ANSWER :B
3.

Finelydivided iron combines with CO to give :

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`Fe(CO)_4`
`Fe(CO)_5`
`Fe(CO)_6`
`Fe(CO)_7`

Answer :B
4.

Finely divided iron combines with CO to give _________.

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`Fe(CO)_5`
`Fe_2(CO)_9`
`Fe_2(CO)_(12)`
`Fe(CO)_6`

Answer :A
5.

Find Z_(eff) (using Slater's Rule) on 3d electron of Cu(29)

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8.3
6.85
7.85
None of these

Solution :`Cu(29)=(1S^(2))(2s^(2)2p^(6))(3s^(2)3p^(6))(4s^(1))(3D^(10))`
`sigma=9xx0.35+18xx1`
`Z_(EFF)=Z-sigma=29-9xx0.35-18`
`Z_(eff)=11-3.15=7.85`
6.

Finely divided catalyst is more effective because____________.

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it INCREASES activation energy
it SHIFTS the equilibrium position to the left hand side
it PROVIDES greater surface area
it increases the rate of forward reaction

Answer :C
7.

Fire extinguishers contain H_2SO_4 and,

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`NaHCO_3 `and `Na_2CO_3`
`NaHCO_3` SOLUTION
`Na_2CO_3`
`CaCO_3`

ANSWER :A
8.

Find wrong statement

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`CuCl_(2)` is used as catalyst in Deacon's process.
`I_(2)` does not show bleaching property
Bond polarity `=H-Cl gt H-F`
`BaF_(2)` is more soluble among the FLUORIDES of Mg, Ca,Sr and Ba

Solution :(c ) HF is a weak acid and due to high electronegativity `H-F gt HCL` -Bond pobrity
(d) `I_(2)` SHOWS bleaching property `CaoCl_(2) + 2KI + HCl rarr 2CaCl_(2) + KCl + H_(2) O + I_(2)`
9.

Find trelationship between given pair :

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SOLUTION :N//A
10.

Find total planes in CH_(4) containing maximum no. of atoms :-

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`4`
`10`
`6`
`12`

SOLUTION :`N//A`
11.

Find total number of species in which Zn metal is soluble under oridnary condition (R.T.). H_(2)O,"dil".H_(2)SO_(4),"conc". H_(2)SO_(4),"dil".HNO_(3),"conc".HNO_(3),"dil". HCl,NaOH(aq),AgNO_(3)(aq.),CuSO_(4)(aq.)

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Solution :`ZN+"dil".H_(2)SO_(4)rarrZnSO_(4)(AQ)+H_(2)uarr`
`Zn+"CONC".H_(2)SO_(4)rarrZnSO_(4)(aq)+SO_(2)uarr`
`Zn+"dil". HNO_(3)rarrZn(NO_(3))_(2)(aq)+N_(2)Ouarr`
`Zn+"conc."HNO_(3)rarrZn(NO_(3))_(2)(aq)+NO_(2)uarr`
`Zn+"dil". HClrarrZnCl_(2)(aq)+H_(2)RARR`
`Zn+NaOHrarrNa_(2)Zn(OH)_(4)(aq)+H_(2)uarr`
`Zn+AgNO_(3)rarrZn(NO_(3))_(2)+Agdarr`
`Zn+CuSO_(4)rarrZnSO_(4)+Cudarr`
12.

Find total number of stereoisomers for each compound given below :

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Solution :`(1) 2^(4) rArr16,`
(2) `(1) 2^(2) rArr4,`
(3) `(1) 2^(4) =16 ("n=4 stereogenic centre")`
(4)`(1) 2^(2)rArr4 ("molecule unsymmetrical"),`
(5) `(1) 2^(2)rArr4`
(6) `(1) 2^(2)rArr4 ("molecule unsymmetrical"),`
(7) `(1) 2^(2)rArr4`
(8) `S.LrArr3 ("molecule SYMMETRICAL")`
(9)
13.

Find total number of orbital which can overlap colaterally, (if inter nuclear axis is z): s, p_(x), p_(y), p_(z), d_(xy), d_(yz), d_(xz), d_(z), d_(x^(2)-y^(2))

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<P>

SOLUTION :`(p_(x), p_(y), d_(xy), d_(YZ), d_(XZ), d_(x^(2)-y^(2)))`
14.

Findthe workdonewhen one mole of thegas isexpandedreversibly po and isothermallyfrom5 atmto 1e atm at 25^(@) C.

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Solution :`W = -2.303nRT LOG(P_(1))/(P_(2)) = - 3988 J`
15.

Find the work done when one mole of the gas is expanded reversibly and isothermally from 5 atm to 1 atm at 25^(@)C

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SOLUTION :`w=-3.988kJ`
16.

Find the work done when 1 mole of hydrogen expands isothermally from 15 to 50 litres against a constant pressure of 1 atm at 25^(@)C.

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ANSWER :(-718 CAL)
17.

Find thework done in each case :(a)Whenone moleof ideal gas in 10 liter container aat 1 atm,is allowed to enter a vaccuated bulb of capacity 100 liter. (b)When1 moleof gas expands from1 liter to 5 liter a against constant stamospherice pressue .

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SOLUTION :N//A
18.

Find the volume of CO_(2) obtained at S.T.P. on heating 200 gm of 50% pure CaCO_(3) -

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11.2 litre
22.4 litre
44.8 litre
None of these

Answer :B
19.

Find the velocity of an electron emitted by a metal whose threshold frequency is 2.25 xx 10^(14) sec^(-1) . When exposed to visible light of wavelength 5.0 xx 10^(-7) m.

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Solution :`phi = hv_(0)`
`= 6.6 xx 10^(-34) xx 2.25 xx 10^(14) = 0.928 eV`
Total ENERGY given by the visible light `= ( h C)/(lambda)`
` = ( 6.6 xx 10^(-34) xx 3 xx 10^(8))/( 5.0 xx 10^(-7)) = 2.47 eV `
K.E. = Total energy `E - phi = 2.45 - 0.928 = 1.547 eV `
K.E. = `( 1)/(2) mv^(2)`
`1.547 xx 1.6 xx 10^(-14) = ( 1)/( 2) xx 9 xx 10^(-31) xx v^(2)`
`v = sqrt(( 1.547 xx 1.6 xx 10^(-19) xx 2 )/( 9 xx 10^(-31))) 7.4 xx 10^(5) m//`SEC
20.

Find the values of A,B and C in the following table for the reaction X + Y to Z. The reaction is of first order w.r.t X and zero order w.r.t. Y. {:("Exp",[X](mol L^(-1)),[Y](mol L^(-1)),"Initial rate (mol L^(-1) s^(-1))),(1,0.1,0.1,2xx10^(-2)),(2,A,0.2,4 xx 10^(-2)),(3,0.4,0.4,B),(4,C,0.2,2 xx 10^(-2)):}

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`A = 0.2 MOL L^(-1), B = 8 xx 10^(-2) mol L^(-1) s^(-1), C = 0.1 mol L^(-1)`
`A = 0.4 mol L^(-1), B = 4 xx 10^(-2) mol L^(-1) s^(-1), C = 0.02 mol L^(-1)`
`A = 0.2 mol L^(-1), B = 2 xx 10^(-2) mol L^(-1) s^(-1), C = 0.4 mol L^(-1)`
`A = 0.4 mol L^(-1), B = 2 xx 10^(2) mol L^(-1) s^(-1), C = 0.4 mol L^(-1)`

Solution :Rate `= k [X][Y]^(0)`
Rate is INDEPENDENT of the conc. Of Y and it depends only on the conc.of X and it is the first ORDER reaction.
From exp. (1), `2 xx 10^(-2) = k (0.1)`
From exp, (2) `4 xx 10^(-2) = k(A)`
Dividing (ii) and (i) , `(4 xx 10^(-2))/(2 xx 10^(-2)) = (k(A))/(k(0.1)) = (A)/(0.1)`
`IMPLIES 2 xx 0.1 = A`
`implies A = 0.2 mol L^(-1)`
From exp. (3), `B = k(0.4)`
Dividing (iii) and (i), `(B)/(2 xx 10^(-2)) - (k(0.4))/(k(0.1)) = 4`
`implies B = 4 xx 2 xx 10^(2) = 8 xx 10^(-2) mol L^(-1) s^(-1)`
From exp. (4), `2 xx 10^(2) = k (C )`
dividing (iv) and (i), `(2 xx 10^(-2))/(2 xx 10^(-2)) = (k(C ))/(k(0.1)) = (C )/(0.1)`
`implies C = 0.1 mol L^(-1)`
21.

Find the values of the rate constant of a first order reaction having half life of 50 minutes.

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SOLUTION :Rate CONSTANT(k) = `(0.693)/t_(1//2) = 0.693/(50 "min") = 0.0139 min^(-1)`
22.

Find the value (x+y)/(2)(include sterio isomers)

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ANSWER :1.5
23.

Find the value of x in H_(x)[Mn(CO)_(5)]:

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2
`-1`
1
`-2`

SOLUTION :`25+x+10=36impliesx=+1`
24.

Find the value of m+n in the anionic species [Ti(CO)mp^(n-), if it follows E.A.N. rule and complex is octahedral ?

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SOLUTION :`m=6[TI(CO)_(6)]^(n-)`
22+n+12=36 `implies` n=2
25.

Find the value of log_(10)K for the reaction A

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ANSWER :10
26.

Find the value of expression |x-| for following compounds. where, x=total number of water insoluble salts. y=total number of salts, which can liberate non-olar acidic gas during their complete thermal decomposition. BaCO_(3),""PbSO_(4),""AgNO_(3),""CaC_(2)O_(4),""CsHCO_(3),""Na_(3)PO_(4),""CH_(3)COOAg,""Mg(OH)_(2),""Pb(NO_(3))_(2)

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Solution :`x=5(BaCO_(3),PbSO_(4),CaC_(2)O_(4),CH_(3)COOAg,Mg(OH)_(2))`
`y=5(BaCO_(3),PbSO_(4),CaC_(2)O_(4),CsHCO_(3),CH_(3)COOAg)`
27.

Find the value of AG^(@) at 25^(@)C for the following electrochemical cell. Cu|Cu^(2+)(1M)||Ag^(+)(1M)|Ag [Ec_(u)=+0.34V, E_(Ag)^(@)=+0.8V] F=96487C

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SOLUTION :`E_("CELL")^(@)=E_("cell")-E_("anode")=0.8-0.34=0.46V`
`DELTAG^(@)=-nFE_("cell")^(@)=-2xx96500xx0.46=-88780J`
28.

Find the total stereoisomes for : (a) [Cr(C_(2)O_(4))_(3)]^(3-)=x (b) [PtCl_(2)(en)_(2)]^(2+)=y (c ) [Cr(NH_(3))_(2)Cl_(2)(en)]^(+)=z Hence write the value of x+y+z

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SOLUTION :x=2,y=3,z=4
29.

Find the two third life (t_(2//3)) of a first order reaction in which k=5.48xx10^(-14)sec^(-1), (log3=0.4771,log2=0.3010)

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Solution :`t_(2//3)=(2.303)/(K)LOG""(a)/(a-2a//3)=(2.303)/(5.48xx10^(-14)s^(-1))log3=2xx10^(13)s.`
30.

Find the total pressure exerted by 1.6 g of methane and 2.2 g of CO_(2) contained in a four-litre flask at 27^(@)C.

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ANSWER :0.9236 ATM
31.

Find the total numberof isomers of C_(7)H_(14) (only 5-membered ring.)

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SOLUTION :
32.

Find the total number of stereoisomers of [M(gly)_(3)] [Where M is any metal capable of forming such complexes.]

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SOLUTION :`M(AB)_(3)` has TWO G.I. both of which are O.A.
33.

Find the total number of molecule / ions in which d orbitals is / are not in hybridisation PCl_(6)^(-), PCl_(4)^(+), IF_(4)^(-), IF_(5), XeO_(3), F_(2), I Cl_(2)^(+), SF_(2), SF_(6), As F_(4)^(+), SiF_(4)

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3
4
5
6

Answer :C
34.

Find the total number of monohalogenated products including stereoisomers for R.

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SOLUTION :`THEREFORE""8`
35.

Find the total number of stereoisomer for each compound :

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SOLUTION :(1) `2^(1)=2`
(2) `2^(2)=4`
(3) `2^(n-1)+2^((n//2-1))+2^(2//1)+2^((2//2-1)=2^(1)+2^(@)=2^(1)+1=3`
(4) 4
(5) `2^(3)rArr8`
36.

Find the total number of optically active compounds in [Zn(bm)(en)]Cl_(2).

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SOLUTION :
37.

Find the total numberof ions which form paramagnetic complex irrespective of nature of ligand in octahedral geometry. (C.N. = 6) Sc^(+3), Ti^(3=), Cr^(+3), Pt^(+4), Ni^(+2), Co^(+3), Fe^(+3)

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Solution :`CR^(3+),Ni^(2+),Fe^(3+),TI^(3+)`
38.

Find the total number of lone pair in compound Z which is formed as follows: CH_(3)CH_(2) CH_(2)Br overset(aq. NaOH) to X overset(Al_(2)O_(3)) to Y overset(Cl_(2)//H_(2)O) to Z

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SOLUTION :`CH_(3)CH_(2)CH_(2)Br overset(aq. KOH) to underset(X)(CH_(3)CH_(2)CH_(2)OH) overset(Al_(2)O_(3))underset("HEAT") to underset(Y)(CH_(3)CH=CH_(2)) overset(Cl_(2)//H_(2)O) to underset(Z)(CH_(3)CHOHCH_(2)Cl)`

Hence, the LONE pair of electron in Z is 5.
39.

Find the total number of ligands which act as pi-acceptor. O^(2), F^(-), CO, CH_(3)NC, CN^(-), CH_(3)O^(-), OH^(-), CH_(2)=CH_(2), NO^(+), PF_(3), AsF_(3) [If your answer is 2, write your answer is 2, write it as 0002.]

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Solution :CO,`CH_(3)NC,CN^(-),CH_(2)=CH_(2),NO^(+),PF_(3),AsF_(3)`.
40.

Find the total number of geometrical iosmers of [M(AB)(CD)(EF)]^(n+)

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SOLUTION :
41.

Find the total number of feasible products (including stereoisomers) in the following reaction. (No carboncation rearrangements is observed)

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ANSWER :4
42.

Find the total number of elements which have higher ionisation energy than their both adjacentelements (either in a period or in a group in the long from of periodic table). Be, B, N, P, Ga, S, Mg

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Solution :`Li LT Be gt B`
`C lt N gt O`
`Si lt P gt S`
`AL lt GA gt In`
`Na lt Mg gt Al`
43.

Find the total number of elements which have higher ionisation energy than their both adjacent elements (either in a period or in a group in the long from of periodic table). Be, B, N, P, Ga, S, Mg

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ANSWER :5
44.

Find the total number of Fe-Fe bonds in Fe_(3)(CO)_(12) if it follows EAN rule.

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SOLUTION :
45.

Find the total number of diamagnetic complexes. K_(3)[Fe(CN)_(6)],[Co(NH_(3))_(6)]Cl_(3), Na_(3)[Co(Ox)_(3)], [Ni(H_(2)O)_(6)]Cl_(2), K_(2)[Pt(CN)_(4)], [Zn(H_(2)O)_(6)](NO_(3))_(2), K_(2)[NiCl_(4)],[Pt(NH_(3))_(2)Cl_(2)], [Ni(CO)_(4)]

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SOLUTION :`[Co(NH_(3))_(6)]Cl_(3),Na_(3)[Co(OX)_(3)],K_(2)[Pt(CN)_(4)][Zn(H_(2)O)_(6)](NO_(3))_(2),[Pt(NH_(3))_(2)Cl_(2)],[Ni(CO)_(4)]` are diamagnetic.
46.

Find the total number of diastereomers of the complex M_(a_(2)b_(2)c_(2)) where M is the central metal atom/ion and a, b, c are monodentate achiral ligands.

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Solution :(AA) (BB) (cc)`cancel O.I .=1`
(AB)(ab)(cc) `cancel O.I.=1`
(ac) (bb)(cc) `cancel O.I.=1`
(aa)(bc)(bc) `cancel O.I.=1`
(ab)(ac)(bc) RIGHT O.A.=2
`:.` Diastereomers=5
47.

Find the total number of compounds or ions having O-O bond longer than that in free O_(2) molecule. (a) Na_(2)O_(2),""(b) KO_(2), (c ) [overset(v)Cr(O_(2))_(4)]^(3-),""(d) [overset(VI)CrO(O_(2))_(2)(H_(2)O)], (e ) [CrO_(5)(Py)],""(f) [overset(III)Cr(O_(2))(CN)_(5)]^(3-), (g) Na_(2)ZnO_(2)

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SOLUTION :Except `Na_(2)ZnO_(2)`, all have either `O_(2)^(-)` or `O_(2)^(2-)` which have longer bond length than`O_(2)`.
48.

Find the total number of complexes / species which are paramagnetic. (a) [Co(NH_(3))_(6)]^(3+),""(b) [Co(H_(2)O)_(6)]^(3+), (c ) [Cr(NH_(3))_(6)]^(2+),""(d) [CoF_(6)]^(3-), (e ) K_(3)[PtCl_(3)(C_(2)H_(4))],""(f) [Mn(NH_(3))_(6)]^(2+), (g) [Fe(NH_(3))_(6)]^(2+),""(h) NO_(2), (i) ClO_(2),""(j) [Pt(NH_(3))_(2)Cl_(2)

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Solution :There are six compounds which are paramagnetic
(c )`[CR(NH_(3))_(6)]^(2+),Cr^(2+),3d^(4),SP^(3)d^(2)` hybridisation, complex
(d) `[CoF_(6)]^(3-) Co^(3+),3d^(6),sp^(3)d^(2)` hy7bridisation, there will be FOUR unpaired electrons
(e )`K_(3)[PtCl_(3)(C_(2)H_(4))]` diamagnetic
(f) `[Mn(NH_(3))_(6)]^(2+) 3d^(5)`,5unpaired electrons, (paramagnetic).

(g) `[Fe(NH_(3))_(6)]^(2+)` paramagnetic (4 unpaired electrons)
49.

Find the total number of compounds/ions having linear shape. [Ag(CN)_(2)]^(-), HgCl_(2), SnCl_(2), NO_(2)^(+1), ClO_(2)^(+), AuCl_(2)^(-), Hg_(2)Cl_(2)

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SOLUTION :`[AG(CN)_(2)]^(-),NO_(2)^(+),CIO_(2)^(+),AuCl_(2)^(-),Hg_(2)Cl_(2)`
50.

Find the total number of compounds having equal all bond lengths equal : PCl_(5),PF_(5),SF_(4),XeF_(2), XeF_(4),XeF_(6),SF_(6),ClF_(3), BrF_(5),Ni(CO)_(4),IF_(7)

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SOLUTION :`SF_(6),XeF_(4)` and `Ni(CO)_(4)` having EQUAL bond LENGTH.