Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find out X and Y in the following reaction Xoverset(I_(2)//HgO)to" iodobenzene "overset(2Na)toY

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TOLUENE and ALKYL BENZENE
toluene and diphenyl
benzene and alkyl benzene
benzene and diphenyl

Answer :D
2.

Find out work done for the given cell Cr|Cr^(+3) || Fe^(+2)| Fe E_(Cr//Cr^(3+))^(@) = 0.74 V, E_(Fe^(2+)//Fe)^(@) = -0.44 V

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Solution :`E_("cell")^(@) = E_("cathode")^(@) - E_("ANODE")^(@)`
`=-0.44 V + 0.74 V = 0.30` V
[since cell reaction `2Cr + 3Fe^(2+) to 2Cr^(3+) + 3Fe`, n = 6 mol ELECTRON]
`W= -nFE^(@) =-6 xx 96500 xx 0.30 W = 173.7` KJ
3.

Find out which of the following is the strongest oxidizing agent.

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`CL^(-)`
`Mn^(2+)`
`MnO_(4)^(-)`
`Cr^(3+)`

Solution :Strongest oxidizing agent is one which is reduced most easily, i.e., which has highest reduction POTENTIAL VIZ. `MnO_(4)^(-)` (reduced to `Mn^(2+)`).
4.

Find out total number of representative elements in the given element: Cd, Nb, Ta, Te, Ra, Mo, Po, Pd, Tc

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SOLUTION :`TE,PO,RA`
5.

Find out the wrong statement about corey House reaction.

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The rate of reaction for alkane SYNTHESIS by corey House reaction SI `1^(@) R-X gt 2^(@) R-X gt 3^(@) R-X`
Thisis good process to obtain alkane with odd number of carbons atoms
It introduce alkyl PART in FORM of `R^(o+)`
It gives alkene as major PRODUCT with `3^(@) R-X`

Solution :It introduce alkyl part in form of `R^(Theta)`
6.

Find out the volume of Cl_(2) at STP produced by the action of 100cm^(3) of 0.2 N HCl on excess of MnO_(2).

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Solution :`MnO_(2)+underset(4xx36.5g)(4HCl)rarrMnCl_(2)+2H_(2)O+underset(22400cm^(3)" at STP")(Cl_(2))`
`"HCl PRESENT in "100cm^(3)" of 0.2 N HCl"=(0.2)/(1000)xx"100g eq.= 0.02g eq."xx"36.5 g = 0.73 g"`
7.

Find out the volume in mL of 0.1 N HCl solution required to react completely wth 1.0 g of a mixture of Na_(2)CO_(3) and NaHCO_(3)containing equimolar amounts of the two compounds .

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Solution :Let the amount of `Na_(2)CO_(3)` in 1 G of mixture be X g and sincethe `Na_(2)CO_(3) and NaHCO_(3)`are in equimolar amounts ,
`x/106 = (1-x)/84 , " where " {{:("mol . WT . Of "Na_(2)CO_(3)=106),(" mol .wt of "NaHCO_(3)=84):}}`
` :. "" x = 0.558 g `
Thus wt. of `na_(2)CO_(3) = 0.558 g `
and wt. of `NaHCO_(3) = 1 - 0.558 = 0.442 g `
Now ,
m.e of HCL = m.e of `Na_(2)CO_(3) + " m.e of " NaHCO_(3)`
m.e of HCl = eq. of `Na_(2)CO_(3) xx 1000 + " eq. of " NaHCO_(3) xx 1000 ""...(Eqn.3)`
If v is the volume of HCl in mL
then `0.1 xx v = (0.558)/53 xx 1000 + (0.442)/84 xx 1000 "" ...(Eqn. 4i)`
` :. "" v = 157 .9 mL `
8.

Find out the value of electrostatic potential eneryg of two electrons separated by 3.0Å in vacuum. Express your answer in joules and electron volt.

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ANSWER :4.8 EV
9.

Find out the total number of stereoisomers of the given following compound. Cl-CH=CH-overset(Cl)overset(|)underset(H)underset(|)C-CH=CH-Cl

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SOLUTION :
10.

Find out the total number of species having atleast one adjacent bond angles is le 90^(@) BrF_(5),XeO_(3),SiCl_(4),SOF_(4),SO_(3),PCl_(5),IO_(2)F_(2)^(Theta)

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11.

Find out the total number of stereocentre in the given compound. CH_(3)-CH=CH-underset(Br)underset(|)CH-underset(Cl)underset(|)CH-CH_(3)

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SOLUTION : STEREOCENTRES `=2+2=4`
12.

Find outthetotalnumberof isomers includingstereoisomers obtinedbydichlorination of propane .

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ANSWER :5
13.

Find out the total number of cyclic isomers of C_(4)H_(10) which areopticallyactive ?

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ANSWER :2
14.

Find out the total number of compound which have p_(pi)-d_(pi) types of back bonding BF_(3),B_(3)N_(3)H_(6),O(SiH_(3))_(2),(SiH_(3))NCS,Ocl_(2),SCl_(2),PH_(3),PF_(3)

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15.

find out the standard free energy change at60^(@)Cand at 1 atn if the N_(2)O_(4) is 50 % dissociated

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`-800 .0 kJ mol^(-1)`
`+ 800.0 kJ mol^(-1)`
`789.89 JK^(-1) mol^(-1)`
`+ 789.98 JK^(-1)mol ^(-1)`

Solution :`N_(2)O_(4)(g)Leftrightarrow2NO_(2)(g)`
` N_(2)O_(4)` is 50 %dissociated , the mole fraction of thesubstance is given by `x_(n2O4)= (1-05)/(1 + 0.5), x_(no2)= (2xx0.5)/(1+0.5)`
`P_(n2O4)=0.5/1.5xx 1 atm , p_(no2)1/1.5 XX 1atm`
the equilibrium CONSTANT ` K_(p)` is given by`k_(p) =(P_(no_(2)))^(2)/(P_(N_(2)O_(4)))=1.5/((1.5)^(2)(0.5))=1/0.75=1.33`
` Delta_(a)G^(Theta)=-RT in K_(p)`
`=- 8.314 Jk^(-1)mol^(-1)xx333 K xx 2.303xx 0.1239`
`=-789.89 JK^(-1) mol^(-1)`
16.

Find out the product of the following reactions. (i) CH_(3)CH(Cl)COOH underset((ii)H_(2)"O"//Delta)((i) NaNO_(2))(to)? [X] (i) CH_(3)CH_(2)-Br+NaNO_(2)overset("alcohol" //Delta)(to)[Y]

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Solution :(i) `underset((alpha-"Chloropropionic ACID"))(CH_(3)-OVERSET(Cl)overset(|)(CH)-COOH)+NaNO_(2)overset(H_(2)"O"//Delta)(to)underset(("Nitro ethane"))(CH_(3)-CH_(2)-underset((X))(NO_(2))+NaCl+CO_(2)`
(ii) `CH_(3)-underset(("Ethyl BROMIDE"))(CH_(2)-Br+NaNO_(2))overset("Alcohol"//Delta)(to) underset(("Nitro ethane")(Y))(CH_(3)-CH_(2)-NO_(2)+)NaBr`
17.

Find out the reaction in which obtained product give positive isocyanide test :-

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SOLUTION :
18.

Find out the period number of the inert gas atom in which the total number of d-electron is equal to the difference in the number of total p-and s-electrons

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Solution :First gas which contains d-electron is Kr.
`1S^(2)2s^(2)2p^(6)3S^(2)3p^(6)3d^(10)4s^(2)4p^(6)`
Total NUMBER of d-electron = 10
Total number of p-electrons = 6+6+6=18
Total number of s-electrons = 2+2+2+2=8
DIFFERENCE in total number of p-and s-electrons =18-8=10
So inert gas is `._(36)Kr`. Now since At. No. is 36 so, period no. is (4)
19.

Find out the percentage of the reactant molecules crossing over the energy barrier at 325K, given that DeltaH_(325)=0.12kcal, E_(a(b))=+0.02kcal.

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Solution :Given , `DeltaH=0.12xx10^(3)cal`,
`E_(a(B))=0.02xx10^(3)cal` (`E_(a)` can NEVER be negative)
`:. DeltaH=E_(a(f))-E_(a(b))`
`:.E_(a(f))=0.12xx10^(3)+0.02xx10^(3)cal`
`=0.14xx10^(3)cal`
`%` of molecule crossing over the BARRIER
`=100xxe^(-E_(a(f))//RT)`
`=100xxe^(-140//(2xx325))`
`=100xx0.8065=80.65%`
20.

Find out the oxidation number of S in (i) SO_(2)Cl_(2) and (ii) Na_(2)S_(2)O_(3)

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SOLUTION :(i) `overset(x)(S)overset(-2)(O_(2))overset(-1)(Cl_(2))""therefore""x+2(-2)+2(-1)=0 or x= +6`
(ii) `Na^(+).^(-)O-UNDERSET(O)underset(||)overset(S)overset(uarr)(S)-O^(-)Na^(+)`
Since there is a coordinate bond between the two S atoms, therefore, ACCEPTOR S atom has an O.N. of -2. The O.N. of the other S atom an be calculated as follows :
`underset(("for Na"^(+)))(2 XX (+1)) underset(("for O atoms"))(+3 xx (-2)) + x underset(("for coordinate S"))(+1 xx (-2)) or +2 - 6 + x - 2 = 0 or x = +6 `
Thus, the two S atoms in `Na_(2)S_(2)O_(3)` have oxidation numbers of -2 and +6.
21.

Find out the number of waves made by a Bohr electron in one complete revolution in its third orbit.

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Solution :`(NH)/(2PI) = MVR , (2pir)/(h//mv) = (2pir )/(LAMDA) = n`
3
22.

Find out the number of reagents that converts 1^(@) alcohol to aldehyde. K_(2)Cr_(2)O_(7)// dil. H_(2)SO_(4), KMnO_(4)//H^(+)//Delta, H_(3)C-overset(O)overset(||)(S)-CH_(3)(DMSO), ceric ammonium nitrate, NBS,(C_(5)H_(5)Noverset(+)(H))_(2)Cr_(2)O_(7)^(2-),""(C_(5)H_(5)NH)^(+)ClCrO_(3)^(-)),[(CH_(3))_(3)CO]_(3)Al in acetone.

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ANSWER :6
23.

Find out the number of products obtained by crossed Cannizzaro's reaction between (a) H-overset(O)overset(||)C-H+Ph-overset(O)overset(||)C-Hoverset(NaOH)underset(H_(2)O)rarr (b) Ph-overset(O)overset(||)C-H+(CH_(3))_(3)C-overset(O)overset(||)C-Hoverset(NaOH)underset(H_(2)O)rarr

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ANSWER :(a-2,b-4)
24.

Find out the number of atoms per unit cell in a face-centred cubic structure having only single atoms at its lattice points.

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SOLUTION :Contribution made by the atoms present at eight corners = 1
Contribution made by the atoms at the CENTRE of six FACES = `1/2 xx6 = 3`
TOTAL number of atoms PER unit cell =1+3=4
25.

Find out the number of 1-2 shifts during the conversion of

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SOLUTION :N//A
26.

Find out the most stable oxidised species.

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`CR^(3+)`
`MnO_(4)^(-)`
`Cr_(2)O_(7)^(2-)`
`Mn^(2+)`

Solution :`E_(o x)^(@)` is highest for `Cr/Cr^(3+)`. Hence, `Cr^(3+)` IONS will be most stable OXIDIZED species.
27.

Find out the most stable ion in its reduced form.

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`Cl^(-)`
`Cr^(3+)`
`Cr`
`Mn^(2+)`

SOLUTION :`E_(red)^(@)` is highest for `MnO_(4)^(-)//Mn^(2+)`. This shows that this reduction takes place most easiliy. Hence, `Mn^(2+)` will be most stable ion in the reduced FORM.
28.

Find out the molar conductivity of an aqueous solution of BaCl_(2) at infinite dilution when ionic conductances of Ba^(2+) and Cl^(-) ion are 127.30 S cm^(2)mol^(-1) and 76.34 S cm^(2)mol^(-1) respectively.

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SOLUTION :`wedge_(m)^(@)(BaCl_(2))=lamda_(BA^(2+))^(@)+2lamda_(CL^(-))^(@)=127.30+2(76.34)" S "cm^(2)mol^(-1)=279.99" S "cm^(2)mol^(-1)`
29.

Find out the molality of solution prepared by dissolving 2.89 g of NaCl in 0.159 litre of water. Density is 1.00 gm/mL.

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ANSWER :0.311 m
30.

Find out the maximum number of possible isomers of the octahedral complex [Co(C_(2)O_(4))_2(NH_3)_2]

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Solution :Cis and TRANS geometrical ISOMERS.
Cis-isomer can exist as PAIR of optical isomers . TOTAL no. of isomers = 3
31.

Find out the molality of solution formed by dissolving 29.22 g of NaCl in 2.00 kg of water.

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ANSWER :0.25 m
32.

Find out the maximum number of isomers (including steroisomers) that are possible on monochlorination of the given compound: CH_(3)-CH_(2)-underset(H)underset(|)overset(CH_(3))overset(|)(C)-CH_(2)-CH_(3)

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ANSWER :8
33.

Find out the longest wavelength of absorption line for hydrogen gas containing atoms in ground state.

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ANSWER :`121.6nm`
34.

Find out the incorrect statement among the following.

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ferric alum is commonly known as Mohr's salt.
Cast iron cannot be welded.
Heating of steel of high TEMPERATURE FOLLOWING by QUICK quenching in water is CALLED annealing.
Alnica is used for making UTENSILS and automobile parts.

Answer :A::C::D
35.

Find out the incorrect pair

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`Sc^(3+), Ti^(4+)`
`Ti^(3+). Ti^(2+)`
`Cr^(2+), Mn^(3+)`
`Cu^(+), Zn^(2+)`

Solution :`Ti^(3+). Ti^(2+)`have `d^(1)` and `d^(2)` configuration WHEREAS others have same configuration.
36.

Find out the incorrect order of the dipole moment among the following pair of compound

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`NH_(3) gt NF_(3)`
p-dichloro benzene gt o-dichloro benzene
`CH_(3)CL gt CH_(2)Cl_(2)`
`SiF_(4)LT SF_(4)`

Answer :A
37.

Find out the incorrect order of bond angles

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`NO_2^+`>`NO_2^`>`NO_2^-`
`CH_4 GT NH_3gt H_2O`
`H_2O gt H_2S gtH_2Se`
`NH_3lt PH_3lt AsH_3`

ANSWER :D
38.

Find out the incorrect pair.

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Tetragens-`ns^(2)NP^(2)`
Icosagens`-ns^(2)np^(1)`
Chalcogens-`ns^(2)np^(4)`
Halogens`-ns^(2)np^(6)`

Answer :D
39.

Findout theincorrectmatch.

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`electron -DUALNATURE
Rainbow-Discontinuousspectra
Atom -Linespectra
Particlenature - PHOTOELECTRICEFFECT

Answer :B
40.

Find out the example of phosphoprotein

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PLASMA membrane
Casein of milk
Haemoglobin
Mucin of saliva

Answer :B
41.

find out the entroupy change in surroundings when 1 mole of H_(2)O(l)is fromed under standard conditionsDelta_(f)H^(-)=286kJmol^(-1)

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` 959.7 JK^(-1) mol^(-1)`
` 286JK^(-1) mol^(-1)`
` -959.7 JK^(-1) mol^(-1)`
` -286JK^(-1) mol^(-1)`

Solution :`H_(2)(g)+1/2O_(2)(g)toH_(2)O(l)`
` Delta_(r)H^(Theta)=-286kJ mol^(-1)`
when 1 mole of ` H_(2)O(l)` is formed, 286 kJ of heat is released. This heat is ABSORBED by the surrounding .
`i.e.q_("SURR")= + 286 kJ mol ^(-1)`
`DeltaS=(q_(surr))/T=(286 kJ mol^(-1))/(298K)`
`=959.7 Jk^(-1)mol^(-1)`
42.

Find out the correct reaction

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final product in the above reaction NUMBER of moles of `X_2` consumed is 4
`F_3 C - CF_2 - CO- NH_2 overset(Br_2//bar(OH))to F_3 C - CF_3 - NH_2`

SOLUTION :
43.

Find out the correct pair

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Zn, Cu
HF, Zr
Ag, AU
Ti, Cu

Solution :Hf, Zr . This PAIR has same atomic radius whereas others have different atomic radius.
44.

Find out the correct match.a.First law of thermodynamics b.isothermal change c.state function d.adiabatic changei.DeltaU=W ii.q=-Wiii.q+W. iv.DeltaU=q+W

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a(iv),b(II),C(iii),d(iv)
a(ii),b(iii),c(iv),d(i)
a(iv),b(i),c(ii),d(iii)
a(I),b(iv),c(ii),d(iii)

ANSWER :A
45.

Find out the correct pair.

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ORTHO SILICATE- SORO silicate
Pyro silicate-Neso silicate
CHAIN silicate-Pyroxenes
Double chain silicate-Ring silicate

Answer :C
46.

Find out the compounds that will disproportionate in their aqueous solution. (I)ClO_(4)^(-)overst(+0.36V)rarr ClO_(3)^(-) overset(+0.33V)rarr ClO_(2) overset(+0.66V)rarr OC l^(-)overset(+0.40V)rarr(1)/(2)Cl_(2)overset(+1.36)rarr Cl^(-) (II)MnO_(4)^(-)overset(+0.56)rarrMnO_(4)^(2-)overset(+2.22V)rarrMnO_(2)overset(+0.95V)rarrMn^(3+)overset(+1.55)rarrMn^(2+)overset((-0.19)V)rarrMn

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ANSWER :A
47.

Find out the correct graph

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(## AAK_MCP_03_NEET_CHE_E03_021_A001 ##)'
(## AAK_MCP_03_NEET_CHE_E03_021_A002 ##)'
(## AAK_MCP_03_NEET_CHE_E03_021_A003 ##)'
(## AAK_MCP_03_NEET_CHE_E03_021_A004 ##)'

Answer :A
48.

Find out radioactive element?

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`He`
`RN`
`XE`
`AR`

SOLUTION :`Rn`
49.

Find out products of following reactions.

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ANSWER :A::B::C
50.

Find out products C and D in the following reaction CH_(3) -COCH_(3) + CH_(3) Mgl overset((i) " dry ethaet")underset((ii) H_(3) O^(+))(rarr)A overset(conc.H_(2)SO_(4)" ")(rarr)B overset((i) O_(3))underset((ii) H_(3)O^(+))(rarr)C+D

Answer»

`CH_(3)-CH_(2)-CHOand H-CHO`
`CH_(3)-CH_(2)-COOHand H-COOH`
`(CH_(3))_(2)CO and H-CHO`
`(CH_(3))_(2)CO and H-COOH`

ANSWER :C