Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The conversionof 1^(0)amine to 3^(0)amine . Theprocess involved maybe called .

Answer»

reduction
alkylation
OXIDATION
HYDROGENATION

ANSWER :B
2.

The conversion of 2,3-dibromobutane to 2-butene with zinc and alcohol is :

Answer»

REDOX reaction
`alpha`-elimination
`BETA`-elimination
both `alpha`-elimination and redox reaction

Answer :C
3.

The conversion can be effected by using the reagent

Answer»

`H_(2)O_(3)`
`O_(3)`

ANSWER :D
4.

The continuum in an atomic spectrum is due to

Answer»

INSTABILITY in EXCITED state
interaction of ION with an atom
uncertainty principle
ionisation of atom.

Answer :D
5.

The contribution of particle at the edge centre to a particular unit cell is

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`1/2`
`1/4`
1
`1/8`

ANSWER :B
6.

The continuous etherification process will give _________.

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only simpleethers
only MIXED ETHERS
only LOWERETHERS
only HIGHER ethers

ANSWER :A
7.

The contribution of particle at the edge centre to a particular unit cell is,

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`(1)/(2)`
`(1)/(4)`
1
`(1)/(8)`

Solution : Each particle at EDGE CENTRE is surrounded by FOUR unit cells thus its contribution to each unit cell is `(1)/(4)`
8.

Name the monomers of Nylon-6,6.

Answer»

BENZOIC acid and ETHYLAMINE
Phthalic acid and HEXAMETHYLENE DIAMINE
Adipic acid and hexamethylene diamine
Phenol and adipic acid

Answer :C
9.

The constant boiling mixture of two miscible liquids of a definite mole fraction is called ………………. .

Answer»

SOLUTION :AZEOTROPE
10.

The constant 'a' in van der Waals' equation is maximum in

Answer»

HYDROGEN
Helium
Oxygen
AMMONIA

ANSWER :D
11.

The consituent of the powerful explosive RDX is formed during the nitration of

Answer»

toluene
phenol
glycerol
urotropine

Answer :D
12.

The consitutent particles in carborundum

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atoms
molecules
`+ve IONS`
`+ve` ions in a SEA of ELECTRONS

ANSWER :A
13.

The consequences of global warming may be

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increase in AVERAGE temperature of the earth
MELTING of Himalayan glaciers
increased BIOCHEMICAL oxygen demand
eutrophication

Solution :GLOBAL warming may RESULT in increase in average temperature of earth causing melting of Himalayan glaciers.
14.

The connect kinetic rate equation for the addition-elimination mechanism of nucleophilic aromatic substitution

Answer»

RATE = k [ARYL halide][nucleophile]
rate = k [aryl halide]
rate = k [aryl halide]`["nucleophile"]^2`
rate = k [nucleophile]

SOLUTION :
15.

The conjugate base of serotonin (used as tranquilisers) is given as follows: How many basic groups present in following compound?

Answer»


ANSWER :3,3 basic groups are `OVERSET(..)/(N)H_(2);-NH-;O^(-)`
16.

The connect difference between first and second-order reactions is that

Answer»

a first - ORDER reaction can be catalyzed, a second-order reaction cannot be catalyzed
the half-life of a first-order reaction does not depend on `[A]_(0)`, the half-life of a second-order reaction does depend on `[A]_(0)`
the RATE of a first-order reaction does not depend on reactant concentrations, the rate of a second-order reaction does depend on reactant concentrations
the rate of a first-order reaction does depend on reactant concentrations, the rate of a second-order reaction does not depend on reactant concentrations

Answer :B
17.

The conjugate base of NH_(2)^(-) is

Answer»

`NH_(3)`
`NH^(2-)`
`NH_(4)^(+)`
`N_(3)^(-)`

Solution :`NH_(2)^(-) HARR NH^(-2) + H^(+)`
Conjugate acid, base pair.
18.

The conjugate base of OH^- ion is :

Answer»

`H_2O`
`O^(2-)
`H_3O^+`
`O^-`

ANSWER :B
19.

The conjugate base of HSO_(3)^(-) is

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`H_(2)SO_(3)`
`SO_(2)`
`SO_(3)^(2-)`
`H_(2)S`

SOLUTION :The conjugate base of `HSO_(3)^(-)` is `SO_(3)^(2-)`
`underset("ACID")(HSO_(3)^(-)) hArr underset("conjugate base")(SO_(3)^(2-))+H^(+)`
20.

The conjugate base of NH_(2)^- is

Answer»

`NH^-`
`NH_3`
`NH_3^+`
`NH^2-`

ANSWER :D
21.

The conjugate base of HBr is

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`BR^(-)`
`H^(+)`
`Br`
`H_(2)Br_(3)`

ANSWER :A
22.

The conjugate base ofH_3PO_4 IS :

Answer»

`H_3PO_4`
`P_2O_5`
`PO_4`
`HPO_4^(2-)`

ANSWER :D
23.

The conjugate base of H_2SO_4 in the following reaction is: H_2SO_4 + H_2O harr H_3O^+ + HSO_3^-4

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`H_2O`
`HSO_4^-`
`H_3O^+`
`SO_4^-2`

ANSWER :B
24.

The conjugate base of H_3BO_3 is :

Answer»

`B(OH)_4^-`
`H_2BO_3^-`
HBO_3^(2-)
none

Answer :A
25.

The conjugate base of H_3O^+is _____.

Answer»


ANSWER :`H_2O`
26.

The conjugate base of H_(2)PO_(4)^(-) is

Answer»

`H_(3)PO_(4)`
`P_(2)O_(5)`
`PO_(4)^(3-)`
`HPO_(4)^(2-)`

SOLUTION :`underset("Conjugate acid")(H_(2)PO_(4)^(-)) rarr H^(+) + underset("Conjugate base")(HPO_(4)^(2-))`
27.

The conjugatebaseof (CH_(3))_(2)NH_(2)^(+) is

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`(CH_(3))_(2)`
`(CH_(3))_(2)N^(+)`
`(CH_(3))_(3)N^(+)`
`(CH_(3))_(2)N^(-)`

Solution :`(CH_(3))_(2) NH + H^(+)to (CH_(3))_(2) NH_(2)^(+)` conjugatebase CONJUGATEACID.
28.

The conjugate base of (CH_(3))_(3)NH^(+) is :

Answer»

`(CH_(3))_(3)N`
`(CH_(3))_(3)NH_(2)^(+)`
`(CH_(3))_(3)NH`
`(CH_(3))_(3)N^(+)`.

Solution :`(CH_(3))_(3)NH^(+)overset(-H^(+))RARR(CH_(3))_(3)N`
29.

The conjugate base of (CH_(3))_(2)NH_(2)^(+) is

Answer»

`CH_(3))_(3)` N
`(CH_(3))_(2)NH`
`(CH_(3))_(2)N^(-)`
`(CH_(3))_(2)N^(+)`

SOLUTION :`UNDERSET("ACID")((CH_(3))_(2))NH_(2)=underset("Conjugate BASE")((CH_(3))_(2)NH)+H^(+)`
30.

The conjugate base of CH_(3)O^(-) is

Answer»

`H_(2)O`
`CH_(3)O^(-)`
`O^(2-)`
`OH^(-)`

ANSWER :B
31.

The conjugate base in the following reaction H_(2)SO_(4)+H_(2)O rarr H_(3)O^(+) + HSO_(4)^(-)

Answer»

`H_(2)O`
`HSO_(4)^(-)`
`H_(3)O^(+)`
`SO_(2)`

Solution :
32.

The conjugate base of [Al(H_(2)O)_(3) (OH)_(3) is

Answer»

`[A(H_(2)O)_(3)(OH)_(2)]^(+)`
`[Al(H_(2)O)_(3)(OH)_(2)O]`
`(Al(H_(2)O)_(3).(OH)_(3)]`
 `[Al(H_(2)O)_(2)(OH)_(4)]^(-)`

ANSWER :D
33.

The conjugate base of [Al (H_2O)_3(OH)_3] is :

Answer»

`[Al(H_2O)_3 (OH)_2]^+`
`[Al(H_2O)_3 (OH)_2O]^-`
`[Al(H_2O)_3 (OH)_3]^-`
`[Al(H_2O)_2 (OH)_4]^-`

Answer :D
34.

The conjugate acid of S_(2)O_(8)^(2-) is

Answer»

`H_(2)S_(2)O_(8)`
`H_(2)SO_(4)`
`HSO_(4)^(-)`
`HS_(2)O_(8)^(-)`

Solution :`underset("conjugate acid")(HS_(2)O_(8)^(-)) hArr underset("conjugate base")(H^(+) + S_(2)O_(8)^(--))`.
35.

The conjugate acid of NH_(2)^(-) is

Answer»

`NH_(3)`
`NH_(4)^(+)`
`NH_(2)OH`
`N_(2)H_(4)`

Solution :CONJUGATE ACID is OBTAINED from the base by gain of `H^(+)`.
36.

The conjugate acid of NH_(2)^(-) is :

Answer»

`NH_(3)`
`NH_(2)OH`
`NH_(4)^(+)`
`N_(2)H_(4)`

ANSWER :A
37.

The conjugate acid of NH_2^- IS :

Answer»

`NH_3`
`NH_2OH`
`NH_4^+`
`N_2H_2`

ANSWER :A
38.

The conjugate acid of NH_2 is

Answer»

`NH_3`
`NH_2 OH`
`NH_4^+`
`N_2H_4`

ANSWER :A
39.

The conjugate acid of HPO_(4)^(2-) is

Answer»

`H_(2)PO_(4)^(-)`
`PO_(4)^(3-)`
`H_(3)PO_(4)`
`H_(3)PO_(3)`

Solution :Conjugate acid is OBTAINED from the base by GAIN of `H^(+)`.
40.

The conjugate acid of HPO_(3)^(2-) is

Answer»

`H_(3)PO_(4)`
`H_(3)PO_(3)`
`H_(2)PO_(3)^(-)`
`PO_(4)^(3-)`

SOLUTION :`underset("CONJUGATE acid")(H_(2)PO_(3)^(-) HARR H^(+) + HPO_(3)^(2-)` ACTION.
41.

The conjugate acid of HCO_3^- is _____.

Answer»


ANSWER :`H_2CO_3`
42.

The conjugate acid of H_(2)PO_(4)^(-) is

Answer»

`H_(3)PO_(4)`
`H_(2)PO_(4)^(-)`
`PO_(4)^(3-)`
`H_(3)O^(+)`

SOLUTION :`underset("Conjugate acid")(H_(3)PO_(4)) HARR H^(+) + H_(2)PO_(4)^(-)`.
43.

The conjugate acid of CO_3^(2-)

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`H_2O`
`H_2CO_3`
`OH^-`
`HCO_3^-`

ANSWER :D
44.

The conjugate acid of H^- ion is :

Answer»

`H_3O^+`
`H_2`
`OH^-`
`H_2O`

ANSWER :B
45.

The configuration of the given compound is

Answer»

E
R
S
Z

Answer :B
46.

The conformations of n-butane, commonly known as eclipsed, gauche and anti-conformations can be interconverted by

Answer»

rotation AROUND C-H bond of a methyl group
rotation around C-H bond of a METHYLENE group
rotation around Cl-C2 linkage
RATATION around C2 - C3 linkage.

Solution :Rotation around CENTRAL C-C (C2-C3), results in different conformations of n-butane.
47.

The configuration of the following is ……

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1S, 2S
1S, 2R
1R, 2S
1R, 2R

Solution :
CHANGE R to S since H
i.e., atom of lowest PRIORITY is on horizontal axis.
48.

The configuration of eight compounds, a through h are shown below, using various kind of stereo representations. To answer the question given below. Write (a through h ) indicating your choice.

Answer»


SOLUTION :A-d,H, B-d, C-f,h , D-h
49.

the configuration of an element 'X' is 4s^1 3d^10. The wrong statement regarding the element 'X' is

Answer»

it forms COMPLEXES
it exhibits variable valency
it forms paramagnetic IONS only
It can FORM COLOURED salts

Answer :C
50.

The conductivity of strong electrolyte is ……….. .

Answer»

INCREASE on dilutin slightly
decrease on dilution
does not change with dilution
DEPEND UPON density of ELECTROLYTE itself.

Answer :A