Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The compounds A and B in the reaction sequence A overset( " phenol ") larrCH_(3) COCloveserset(CH_(3) COONa) to B

Answer»

`CH_(3)CO–O–COCH_(3), C_(6)H_(5)CH_(2)OH`
`CH_(3) CO–O–COCH_(3) , C_(6)H_(5) OCOCH_(3 )`
`CH_(3)COCH_(3) , C_(6)H_(5)OCOCH_(3)`
`CH_(3) -underset(O) underset(||) C- O - C_(6) H_(7)`
`CH_(3) - underset(O ) underset(||)C- O-C underset(O) underset(||)-CH`,

Solution :
2.

The compounds A and B are mixed in equimolar proportion to form the products, A+BleftrightarrowC+DAt equilibrium, one third of A and B are consumed. The equilibrium constant for the reaction is

Answer»

0.5
4
2.5
0.25

Solution :`A+BleftrightarrowCV+D`
Initial state1100
Atequilibrium`1-(1)/(3)``1-(1)/(3)``(1)/(3)``(1)/(3)`
`K_(C)=([C][D])/([A][B])=((1)/(3)XX(1)/(3))/((2)/(3)xx(2)/(3))=(1)/(4)`=0.25
3.

The compounds 1,2,3,4 given below are allowed in undergo electrophilic substitution by bromonium ions assuming only monobromo substitution the substitutes products are A,B,C,D respectively. The compound B is :

Answer»




both (a) and (B)

SOLUTION :
4.

The compounds A and B are formed in the sequence of the reaction CH_(3)CH_(2)CH_(2)OH overset(PCl_(3))rarr A underset("KOH")overset("alc.")rarr B In the above reactionB is

Answer»

Propylene
Propane
Propyne
Propanol

Answer :A
5.

The compounds 1,2,3,4 given below are allowed in undergo electrophilic substitution by bromonium ions assuming only monobromo substitution the substitutes products are A,B,C,D respectively. The compound D is:

Answer»





SOLUTION :
6.

The compounds 1,2,3,4 given below are allowed in undergo electrophilic substitution by bromonium ions assuming only monobromo substitution the substitutes products are A,B,C,D respectively. The compound C is:

Answer»





SOLUTION :
7.

The compounds 1,2,3,4 given below are allowed in undergo electrophilic substitution by bromonium ions assuming only monobromo substitution the substitutes products are A,B,C,D respectively. The diamonds A is:

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both (a) and (B)

SOLUTION :
8.

The compound ZnFe_(2)O_(4) is

Answer»

A NORMAL SPINEL COMPOUND
Interstitial compound
Covalent compound
Co-ordination compound

Solution :The compound `ZnFe_(2)O_(4)` is a normal spinel compound.
9.

The compound Y in the above sequence is

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2-Methyl 1-2-phenyl-1-propanol
2-Phenyl-2-propanol
Acetophenone
2-Methyl-1-phenyl-2-propanol

Answer :C
10.

the compound Y can not be prepared by using which of the reagents:

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Solution :For being FUNCTIONAL isomers, functional group should not MATCH.
(phenol and ALIPHATIC ALCOHOL are considered as different functional groups).
11.

The compound X(C_5H_8) reacts with ammoniacal AgNO_3 to give a white precipitate and reacts with excess of KMnO_4 to give acid, (CH_3)_2CH-COOH. Therefore, X is:

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`CH_2=CH-CH=CH-CH_3`
`CH_3(CH_2)_2C-=CH`
`(CH_3)_2CHC-=CH`
`(CH_3)_2C=C=CH_2`

ANSWER :D
12.

The compound (X) with M.F. C_(4)H_(11)N on treatment with HNO_(2) gives a tertiary alcohol with M.F.C_(4)H_(10)O. The compound (X) will give

Answer»

CARBYLAMINE reaction
Hofmann mustard oil reaction
Diazonium salt as intermediate with `HNO_(2)`
GIVES 2-methyl-2-nitropropane on oxidation with `KMnO_(4)`

Solution :Since the COMPOUND (X) with M.F. `C_(6)H_(11)N` on treatment with `HNO_(2)`. Give a tertiary alcohol, therefore, (X) must be a `1^(@)` amine andas such it must give carbylamine reaction. Hofmann mustard oil reaction underoges oxlation with `KMnO_(4)` to give 2-methyl-2-nitropropane and must form diazonium salt as an unstable intermediate during its reaction with `HNO_(2)`. Thus, all statements are correct.
13.

The compound 'X' undergoing the following reaction is

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ANSWER :C
14.

The compound X produces methane when treated with water. The compound X is

Answer»

calcium carbide
ALUMINIUM carbide
calcium PHOSPHIDE
aluminium nitride

SOLUTION :`Al_4 C_3 + 12 H_2 O to 3 CH_4 + 4 AL (OH)_(3)`
15.

The compound X on treatment with acidified K_2Cr_2O_7 gives compound Y which reacts with I_2 and Na_2CO_3 to form tri-iodomethane. The compound X is :

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`CH_3OH`
`CH_3COCH_3`
`CH_3CHO`
`CH_3CHOHCH_3`

ANSWER :D
16.

The compound X on reaction with HgSO_4+H_2SO_4 gives Y which one oxidation gives acetic acid. X is

Answer»

`C_2H_2`
`C_2H_4`
`C_3H_4`
`C_4H_6`

Solution :`underset"Ethyne"(CH-=CH)+H_2O underset(H_2SO_4)overset(HgSO_4)to underset"VINYL ALCOHOL"(CH_2=CH-OH)overset(KMnO_4)to CH_3CHO overset"OXIDATION"to underset"Acetic ACID"(CH_3COOH)`
17.

The compound X on oxidation gives a mixture of acetic acid and formic acid, while Y on oxidation forms only propionic acid. X and Y are

Answer»

`CH_3 - underset(OH)underset(|)(CH) - CH_3, CH_3 - CO - CH_3`
`CH_3 - CH_2 - CH_2 - CHO , CH_3 - CO - CH_3`
`CH_3 - CO- CH_3, CH_3 -CH_2 - CHO`
`CH_3 - CO - CH_3 , CH_3 - O - CH_2 - CH_3`

Answer :C
18.

The compound X on heating gives a colourless gas. The residue is dissolved in water to obtain Y Excess CO_2 is bubbled through aqueous solution of Y, Z is formed. Z on gentle heating gives back X. The compound X is:

Answer»

`CaCO_3`
`Na_2CO_3`
`CaSO_4 . 2H_2O`
`K_2CO_3`

ANSWER :A
19.

The compound (X) is

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`CH_(3)COOH`
`BrCH_(2)-COOH`
`(CH_(3)CO)_(2)O`
`CHO-COOH`

Answer :C
20.

The compound (X) is :

Answer»

`(CH_(3)CO)_(2)O`
`BrCH_(2)-COOH `
`CH_(3)COOH`
OHC-COOH

ANSWER :A
21.

The compound X, in the reaction is

Answer»

`Xoverset(CH_(3)MgI)toYoverset("HYDROLYSIS")toMg(OH)I+CH_(3)COOH`
`CH_(3)CHO`
`CO_(2)`
`(CH_(3))_(2)CO`

Solution :`CO_(2)` ADDS to Grignard reagent to yield acids.
22.

The compound (X) is

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`CH_(3)COOH`
`BrCH_(2)-COOH`
`(CH_(3)CO)_(2)O`
`CHO-COOH`.

Solution :It is Perkin's REACTION. Hence (X) is ACETIC anhydride `[(CH_(3)CO)_(2)O]`.
23.

The compound (X) has molecular formula C_(4)H_(7)Cl . Find out the number ofits cyclic isomers (structural and geometrical only excluding optical isomers).

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SOLUTION :`X = C_(4)H_(7)Cl` DEGREE of unsaturation `=5-8/2 =1`
24.

The compound X (C_(4)H_(11)N) on treatement with nitrous acid gives a tertiary alcohol (C_(4)H_(10)O). The compound X must also respond to

Answer»

Mustard oil reaction
Libermann nitroso reaction
Beckmann rearrangement
Carbylamine reaction.

Solution :X must be `1^(@)` AMINE as it PRODUCES alcohol by reaction with `HNO_(2)`. The probable structure of X is TERTIARY butyl amine
`{:(""CH_(3)""CH_(3)),("|""|"),(CH_(3)-C-NH_(2) overset(HNO_(2))(rarr) CH_(3)-C-OH),("|""|"),(""CH_(3)""CH_(3)),(" "(X) 1^(@)" Amine"3^(@)" Alcohol"):}`
X being `1^(@)` amine should also RESPOND to mustard oil reaction and carbyl amine reaction.
25.

The compound X (C_9H_7CIO_2) is optically active.It mainly exists in enolic form.It racemises due to enolisation its structure is :

Answer»




SOLUTION :
26.

The compound X having -OH functional group, quickly reacts with Conc. HCl and anhydrousZnCl_(2) What is X?

Answer»

3-methyl-2-butanol
3-nethyl - 1-butanol
1-butanol
2-methyl-2-butanol

Solution : 2-methyl-2-butanol
27.

The compound X and Y in below reaction can be Ph-NH*NH_(2)+ (X) + (Y) overset(-H_(2)O)(to)

Answer»

`CH_(3)-CH_(2)-underset(OVERSET(||)(O))(C)-CH_(3) + CH_(3)-underset(overset(||)(O))C-Ph`
`Ph-underset(overset(||)(O))(C)-CH_(3) + CH_(3)CHO`
`CH_(2)=O + CH_(3)CHO`
`CH_(2)=O + CH_(3)-underset(overset(||)(O))(C)-CH_(3)`

Answer :D
28.

The compound with two lone pairs of electrons on the central atom is (are)

Answer»

`BrF_(5)`
`ClF_(3)`
`XeF_(4)`
`SF_(4)`

Solution :`BrF_(5)` has one lone PAIR. `CIF_(3)` has TWO lone pairs, `XeF_(4)` has two lone pairs and `SF_(4)` has only one lone pair. THUS, OPTIONS (b) and (c) are CORRECT.
29.

The compound X and Y are

Answer»




SOLUTION :
30.

The compound with the maximum dipole moment among the following is :

Answer»

p-dichlorobenzene
m-dichlorobenzene
o-dichlorobenzene
Carbon tetrachloride

Answer :C
31.

The compound with molecular formula C_(8)H_(10) which will give only two isomers on electrophilic substitution with Cl_(2)//FeCl_(3) or with HNO_(3)//H_(2)SO_(4) is

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NONE of these
1,4-dimethyl BENZENE
1,2-dimethyl benzene
ETHYLBENZENE

ANSWER :C
32.

The compound with no dipole moment is

Answer»

METHYL chloride
carbon tetrachloride
methylene chloride
chloroform

ANSWER :B
33.

The compound with negative heat of formation are known as

Answer»

ENDOTHERMIC COMPOUND
EXOTHERMIC compound
Heat of FORMATION compound
None of the above

Solution :`DeltaH=-ve` for exothermic compound.
34.

The compound with molecular formula C_8H_10 which will give two isomers on electrophilic substitution with Cl_2//FeCl_3 or with HNO_3//H_2SO_4 is

Answer»

p-dimethyl benzene
m-dimethyl benzene
o-dimethyl benzene
Ethyl benzene

Answer :C
35.

The compound with molecular formula C_(4)H_(10)O does not reacts with sodium metal but with excess HI it gives one alkyl halide compound. Which is the compound ?

Answer»

METHOXY methane
Methoxy propane
Ethoxy ethane
2-Butanol

Solution :`underset("(Ethoxy ethane)")(underset("DIETHYL ETHER")(C_(2)H_(5)-OC_(2)H_(5)+ 2HI)) to 2C_(2)H_(5)I+ H_(2)O`
36.

The compound with highest B.P. is

Answer»

n- pentylchloride
isopently CHLORIDE
n - pentylbromide
isopentylbromide

Solution :GREATER the surface AREA HIGHER will be the B.P
37.

The compound with highest boiling point is

Answer»

`CH_4`
`CH_3OH`
`CH_3Cl`
`CH_3Br`

Solution :Alcohols have HIGHER boiling points than nonpolar hydrocarbon and polar HALOALKANE of comparable molecular masses, because alcohol molecules are ASSOCIATED thiough intermolecular hydrogen bonding. More the number of alkyl groups attached to the POSITIVELY charged CARBON, more the dispersal of positive charge and therefore, the greater is the stability of the carbonium ion. `CH_3^(+) lt R_2CH^(+) lt R_3C^+`
38.

The compound with highest boiling point is :

Answer»

`CH_4`
`CH_3OH`
`CH_3CI`
`CH_3Br`

ANSWER :B
39.

The compound with formula C_4H_(10)O yields a compound C_4H_8O on oxidation. The compound C_4H_(10)O is :

Answer»

An aldehyde
An alcohol
A ketone
An anhydride

Answer :B
40.

The compound with alpha - hydrogen is _______

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HCHO
`C_(6)H_(5)CHO`
`C_(6)H_(5)COC_(6)H_(5)`
`CH_(3)COCH_(3)`

ANSWER :D
41.

The compound with formula C_4H_10O yields a compound C_4H_8O on oxidation, the compound C_4H_10O is

Answer»

an ALDEHYDE
an alcohol
a KETONE
an anhydride

ANSWER :B
42.

The compound widely used in making reference electrode is:

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`ZnCl_2`
`CuSO_4`
`Hg_2Cl_2`
`HgCl_2`

ANSWER :C
43.

The compound whose 0.1 M solution is basic is

Answer»

Ammonium acetate
Ammonium chloride
Ammonium sulphate
Sodium acetate

Solution :(a) is a most neutral solution DUE to both cationic and anionic HYDROLYSIS `(K_(a) = K_(b) = 1.8 xx 10^(-5))`,
(b) Is acidic solution due to cationic hydrolysis,
(C) Is acidic solution due to cationic hydrolysis,
(d) Is basic solution due to anionic hydrolysis.
44.

The compound which will not reach with Hinsberg's reagent is

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SOLUTION :`3^@` AMINES do not REACT with hinsberg's REAGENT
45.

The compound which will not exist is

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`XeF_2`
`XeF_4`
`XeF_6`
`XeF_4`

ANSWER :D
46.

The compound which undergoes intramolecular dehydration with P_(2)O_(5) is ______

Answer»

ACETIC acid
formic acid
propionic acid
butyric acid

Answer :B
47.

The compound which will give negative iodoform test is

Answer»

`CH_(3)CHO`
`CH_(3)CH_(2)OH`
ISOPROPYL alcohol
Benzyl alcohol

Solution :`{:(CH_(3)CHO overset(NaOH//I_(2))to CHI_(3)),(CH_(3)CH_(2)OH overset(NaOH//I_(2))to CHI_(3)),(CH_(3)-underset(OH)underset(|)CH-CH_(3)overset(NaOH//I_(2))to CHI_(3)):}}` Yellow ppt.
`C_(6)H_(5)-CH_(2)-OH overset(NaOH//I_(2))to ` No yellow ppt.
48.

The compound which retard the actaion of oxygen on food are called

Answer»

antioxidants
oxidants
chemotherapeutic
cheaning action

Answer :A
49.

The compound which reacts with Fehling solution is

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`C_(6)H_(5)COOH`
`HCOOH`
`C_(6)H_(5)CHO`
`CH_(2)ClCH_(3)`

ANSWER :B
50.

The compound which reacts with HBr obeying Markovnikov's rule is :

Answer»

`CH_(2) = CH_(2)`


ANSWER :D