Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The compound(A) C_(4)H_(11)Nwhichis opticallyactive,dissolvedin conc. HClandreleasednitrogen with HNO_(2)Whatis the compound (A) ?

Answer»

`CH_(3)CH_(2)CH_(2)CH_(2)NH_(2)`
`CH_(3)CHNH_(2)CH_(2)CH_(3)`
`C_(2)H_(5)NH_(2)H_(5)`
`CH_(3)NHCH(CH_(3))_(2)`

Answer :B
Discussion
2.

The Compound (A) and (B) in the equation given above are

Answer»

`CH_(3)COOH, CH_(3)CH_(3)`
`DCH_(2)-COOD, CH_(4)`
`DCH_(2)-COOH, CH_(2)D_(2)`
`CH_(3)-COOH, CH_(3)D`

ANSWER :C
Discussion
3.

The compound A and B are mixed in equimolar proportionto from the products, A+BhArr C+D. At equlibrium, one third of A and B are consumed. The equlibrium constant for the reaction is

Answer»

`0.5`
`4.0`
`2.5`
`0.25`

SOLUTION :`K=([C][D])/([A][B])=(1/3xx1/3)/(2/3xx2/3)=1/4=0.25`
So, `K=0.25`
Discussion
4.

The compound (A)

Answer»

a.
b.
c.
d.`No reaction`

SOLUTION :`3^(@) (RNO_(2))` GROUP does not REACT with `HNO_(2) (NaNO_(2)+HCl rarrHNO_(2)+NaCl)`, since it does not contain `alpha-H` atoms. So the answer is `(d)`.
Discussion
5.

The compound 1,2-butadiene has :

Answer»

Only SP-HYBRIDIZED CARBON atoms
Only `sp^2`-hybridized carbon atoms
Both sp and `sp^2`-hybridized carbon atoms
sp,`sp^2` and `sp^3` hybridized carbon atoms

Solution :`underset"1,2-butadiene"(OVERSET(sp^2)CH_2=overset(sp)C=overset(sp^2)CH-overset(sp^3)(CH_3))`
Discussion
6.

The compound 2-Methyl-1,3 - butadiene has :

Answer»

onlysp hybridised CARBON ATOMS
only `SP^2` HYBRIDIZED carbon atoms
both sp and `sp^2` hybridised carbon atoms
`sp^2 and sp^3` hybridized carbon atoms.

Answer :D
Discussion
7.

The compound 1-(N-ethyl -N-methyl) propanamine forms non-superimposable mirror images. But this compound does not show optical acitivity because of

Answer»

absence of a chiral N atom
presence of chiral N atom
presence of lone pair on N atom
of RAPID FLIPPING one form inot the other

Solution :
It does not SHOW optical activity because of rapid flipping of one form into the other.
Discussion
8.

The compostion formulae of gypsum is

Answer»

`(CaSO_(4))_(2).2H_(2)O`
`2CaSO_(4)`
`CaSO_(4).2H_(2)O`
`2CaSO_(4).H_2O`

Answer :C
Discussion
9.

The composition of vapour over a binary ideal solution is determined by the composition of the liquid. If X_(A) and Y_(A) are the mole fractions of A in the liquid and vapour, respectively, find the value of X_(A) for which Y_(A)-X_(A) has a maximum. What is the value of the pressure at this composition in terms of P_(A)^(@) and P_(B)^(@).

Answer»


SOLUTION :`P_("benzenen")^(@)=X_(A)PA^(@)+(1-X_(A))P_(B)^(@)`
`(1)/(P_(T))=(Y_(A))/(P_(B)^(0))+((1-Y_(A)))/(P_(B)^(0))`
calculate `(X_(A)-Y_(A)) &` maximise it
`X_(A)=(sqrt(P_(A)^(0)P_(B)^(0))-P_(B)^(0))/((P_(A)^(0)-P_(B)^(0)))`
& `P_(T)=sqrt(P_(A)^(0)P_(B)^(0))`
`X_(A)=((sqrt(P_(A)^(0)P_(B)^(0))-P_(B)^(0)))/((P_(A)^(0)-P_(B)^(0))),P=sqrt(P_(A)^(0)P_(B)^(0))`
Discussion
10.

The composition of the equilibrium mixture for the equilibrium Cl_(2) hArr 2Cl at 1470 K may be determined by the rate of diffusion of the mixture through a pinhole. It is found that at 1470 K, the mixture diffuse 1.16 times as fast as krypton (83.8) diffuses under the same conditions. Find the degree of dissociation of Cl_(2) at equilibrium.

Answer»

Solution :For the EQUILIBRIUM,
`{:(,Cl_(2),hArr,2Cl,,),("Initial moles : ",1,,0,,),("Moles at eqb. ",1-x,,2x,,"(x is the DEGREE of dissociation)"):}`
Molecular weight of the MIXTURE of `Cl_(2)` and Cl at eqb., i.e., `M_("mix")` is calculated as
`M_("mix") = ((1-x) 71 + (2x)35.5)/((1-x) + 2x) = (71)/(1+x)`
Now we have,
`(r_("mix"))/(r_(Kr)) = sqrt((M_(Kr))/(M_("mix"))) = sqrt((83.8)/(71(1+x))) = 1.16`
`THEREFORE x = 0.14`
Discussion
11.

The composition of the equilibrium mixture Cl_2iff 2Cl,which is attained at 1200^@C , is determined by measuring the rate of effusion through a pinhole. It is observed that at 1.80 mmHg pressure, the mixture effuses 1.16 times as fast as krypton effuses under the same conditions. Calculate the fraction of chlorine molecules dissociated into atoms. (At. wt. of Kr = 84)

Answer»


ANSWER :0.14
Discussion
12.

The composition of the equilibrium mixture (Cl_(2) hArr 2Cl), which is attained at 1200^(@)C, is determined by measuring the rate effusion through a pinhole. It is observed that at 1.80 mm Hg pressure, the mixture effuses 1.16 time as fast as Krypton effuses under the same conditions. Calculate the fraction of chlorine molecules dissociated into atoms (Atmic wt. Kr=84).

Answer»

Solution :`(r_("MIX"))/(r_("Kr"))=sqrt((M_("Kr"))/(M_("mix")))`
or `1.16 =sqrt((84)/(M))`
`(because` TIME of diffusion for both is same)
`THEREFORE M =62.425`
`Cl_(2) hArr 2Cl`
For 1 0
`(1-alpha) 2alpha`
TOTAL mole in mixutre `=1-alpha+2alpha=1+alpha`
`therefore 71xx(1-alpha)+2alphaxx35.5=(1+alpha)xx62.425`
`therefore alpha =0.137`
or 13.7%
Discussion
13.

The composition of sample of wustite is Fe_(0.93).O_(1.00). Which of the following statement is incorrect related to this compound?

Answer»

The PERCENTAGE of FE(III) is APPROXIMATELY 15%
The ratio of Fe(III) to Fe(II) ion is 0.177
The percentage of Fe(II) ion is 11.5%
All are CORRECT.

ANSWER :D
Discussion
14.

The composition of rust is

Answer»

`Fe_2O_3 . xH_2O`
`Fe_2O_3 . 2H_2O`
`Fe_2O_3. 6H_2O`
`Fe_2O_3`

ANSWER :A
Discussion
15.

The composition of mica is :

Answer»

`NaAlSiO_4. 3H_2O`
`K_2O.3 Al_2O_3. 6SiO_2. 2H_2O`
`K_2HAl(SiO_4)_3`
`NaK. SiO_4. 10H_2O`

ANSWER :B
Discussion
16.

The composition of 'Golden spangles' is

Answer»

`PbCrO_(4)`
`PbI_(2)`
`As_(2)S_(3)`
`BaCrO_(4)`

SOLUTION :`PbI_(2)` is yellow and is CALLED golden spangles
Discussion
17.

The composition of golden spangles is:

Answer»

`PbCrO_(4)`
`Pbl_(2)`
`As_(2)S_(3)`
`BaCrO_(4)`

Solution :`Pbl_(2)` is yellow (known as golden SPANGLES).
Discussion
18.

The compositionof 'coppermatte' is

Answer»

` Cu_2S+FES`
`Cu_2 S + Cu_2O `
`Cu_2S + FEO `
`Cu_2O + FeS `

SOLUTION : ` Cu_ 2 S +FeS `
Discussion
19.

The composition of carnallite is _____.

Answer»

SOLUTION :`MgCl_2. KCL. 6 H_2O`
Discussion
20.

The composition of a Vapour over a binary ideal solution is determined by the compostion of the liquid . If X_(A) and Y_(A) are the mole fractions of A in the liquid and Vapourrespectively, findthe value of X_(A) for which Y_(A)-X_(A) has maximum . What is the value of the pressure at this composition in terms of P_(A)^(0) and P_(B)^(0)

Answer»

`X_(A)=(P-P_(B)^(0))/(P_(A)^(0)-P_(B)^(0)),P=SQRT(P_(A)^(0)-P_(B)^(0))`
`(sqrt(P_(A)^(0)P_(B)^(0)-P_(B)^(0)))/(P_(A)^(0)-P_(B)^(0)),P=sqrt(P_(A)^(0).P_(B)^(0))`
`X_(A)=(1)/((P_(A)^(0)-P_(B)^(0)))-(1)/([(P_(A)^(0))/(P_(B)^(0))-])'P=sqrt(P_(A)^(0).P_(B)^(0))`
`X_(A)=(P_(a)^(0))/(P_(A)^(0)+P_(B)^(0)),P=P_(A)^(0)X_(A)+P_(B)^(0)X_(B)`

ANSWER :A
Discussion
21.

The composition of a sample of wustite is Fe_(0.93) O_(1.00) . What percentage of iron is present in the form of Fe (III)?

Answer»

Solution : Let the MOLES of Fe in FEO and `Fe_2O_3`be `n_1`, and `n_2`RESPECTIVELY. THUS,
moles of Fe/moles of O
`= (n_1 +n_2)/(n_1 + (3n_2)/(2)) = 0.93`
15.05%
Discussion
22.

The composition of a sample of wurtzite is Fe_(0.93)O_(1.00) what % of Iron present in theform of Fe^(3+)?

Answer»

`16.05%`
`15.05%`
`18.05%`
`17.05%`

SOLUTION :Hint : Let the number of `FE^(2+)` IONS in the crystal be X
The number of `Fe^(3+)` ions in the crystal be y
Total number of `Fe^(2+) and Fe^(3+)` ions is `x+y`. Given that `x+y=0.93`
The total charge `=0x(2+)+(0.93-x)(+3)-2=0`
`2x+2.97-3x-2=0x=0.79`
`"Percentage of "Fe^(3+)=(((0.93-0.79))/(0.93))100=15.05%`
Discussion
23.

The component which forms a dative bond with ammonia

Answer»

`C Cl_(4)`
`BCl_(3)`
`MgCl_(2)`
`NaCl`

ANSWER :B
Discussion
24.

The component that is present in largest quantity is called solvent.

Answer»


ANSWER :TRUE
Discussion
25.

The component present in larger quantity in the solution is called.

Answer»

SOLUTION :SOLVENT
Discussion
26.

The component present in greater proportion in water gas is :

Answer»

`H_2`
`CO`
`CO_2`
`N_2`

ANSWER :A
Discussion
27.

The compoiund (A0 is xylene. On sulphonation, it gives onlyone product (B) which onalkaine fusion followed by acidification yields (C), a phenol. On treatmentwith chlorform and alkali, (C) givesC_(9)H_(1) O_(2)(D). Idenifuy the various organic compounds(A) to (D).

Answer»

Solution :`(A)` is xylene, it can be at `o,m`, and `p`. But it gives only ONE SUBSTITUDE PRODUCT, so `(A)` is `p-` xylene. `(OMP = 231)`.
Discussion
28.

The component of blood responsible for blood clotting is :

Answer»

Fibrinogen
GLOBULINS
Albumins
BLOOD PLATELETS.

ANSWER :A
Discussion
29.

The component of a living cell affected by the pollutant SO_2 is

Answer»

CELL wall
All cell MEMBRANE system
Plasmodesmata
Nucleus

Answer :B
Discussion
30.

The component having low melting point can be separated in an impure metal by ________

Answer»

WASHING with water
FROTH flotation
LIQUATION
magnetic separation

Solution :Melting POINT of metal very much lower than impurities .
Discussion
31.

The complex(es) which is /are bluein colour

Answer»

`Fe_(4)[FE(CN)_(6)]_(3)`
`Zn_(2)[Fe(CN)_(6)]`
`Cu_(2)[Fe(CN)_(6)]`
`Fe_(3)[Fe(CN)_(6)]_(2)`

Solution :(a) `Fe_(4)[Fe(CN)_(6)]_(3)`-Ferric FERROCYANIDE-(Prussian blue)
(b) `Zn_(2)[Fe(CN)_(6)]`,-Zinc ferrocyanide-(Blueish white PPT)
c) `Cu_(2)[Fe(CN)_(6)]`- Copper ferrocyanide -(Chocolate brown ppt)
d) `Fe_(3)[Fe(CN)_(6)]_(2)`- Ferroferric CYANIDE- (Tumbull.s blue)
Discussion
32.

The complexes [Pt(NH_(3))_(4)][PtCl_(6)]" and "[Pt(NH_(3))_(4)Cl_(2)][PtCl_(4)] are :

Answer»

LINKAGE ISOMERS
OPTICAL isomers
Co-ordination isomers
ionization isomers

Answer :C
Discussion
33.

The complexes [Pt(NH_(3))_(4)][PtCl_(6)]and [Pt(NH_(3))_(4)Cl_(2)] [PtCl_(4)]are:-

Answer»

LINKAGE isomers
Optical isomers
Co-ordination isomers
Ionisation isomers

Answer :C
Discussion
34.

The complex(es) which is/are blue in colour:

Answer»

`Fe_(4)[(CN)_(6)]_(3)`
`Zn_(2)[Fe(CN)_(6)]`
`Cu_(2)[Fe(CN)_(6)]`
`Fe_(3)[Fe(CN)_(6)]_(2)`

Answer :A::D
Discussion
35.

The complexes having different CO bond length is/are :

Answer»

`Mn_(2)(CO)_(10)`
`Co_(2)(CO)_(8)`
`Fe_(2)(CO)_(9)`
`Fe(CO)_(5)`

SOLUTION :(a) `Mn^(2)(CO)_(10)` has no bridge bond, HENCE all C-O bond length are EQUAL.
(b)
Discussion
36.

The complexes formed by Cu^(2+) ion are more stable than those formed byCd^(2+) ion because _________.

Answer»

the value of the stability constant for `Cd^(2+)` complexes is greater than that of
the charge density on `CU^(2+)` ION is greater than that on `Cd^(2+)` ion.
the ionic radius of `Cu^(2+)` ion is more than that of `Cd^(2+)` ion.
`Cu^(2+)` ion FORMS chelate compounds.

Answer :B
Discussion
37.

The complexes [Co(NH_(3))_(6)]]Cr(CN)_(6)] and [Cr(NH_(3))_(6)][Co(CN)_(6)] are the example of which type of isomerism ?

Answer»

LINKAGE isomerism
Ionisation isomerism
Optical isomerism
Coordination isomerism

Answer :A::C::D
Discussion
38.

The complexes given below show and

Answer»

OPTICAL isomerism
Co-ordination isomerism
Geometrical isomerism
Bridged isomerism

Answer :C
Discussion
39.

The complexes [Co(NH_3)_6][Cr(CN)_6]and [Cr(NH_3)_6][Co(CN)_6]are the example of which type of isomerism ?

Answer»

Geometrical
Linkage
Ionization
Coordination

Answer :D
Discussion
40.

The complexes [Co(NH_(3))_(6)][Cr(CN)_(6)] and [Cr(NH_(3))_(6)] [Co(CN)_(6)] are the examples of which type of isomerism?

Answer»

Linkage isomerism
IONISATION isomerism
Coordinationisomerism
GEOMETRICAL isomerism

ANSWER :C
Discussion
41.

The complexes [Co (NH_(3))_(6)][Cr(CN)_(6)] and [Cr(NH_(3))_(6)][Co(CN)_(6)]are the example of which type of isomerism?

Answer»

GEOMETRICAL ISOMERISM
LINKAGE isomerism
Ionization isomerism
Coordination isomerism

Answer :C
Discussion
42.

The compexes [Co(NH_(3))_(6)][Cr(C_(2)O_(4))_(3)] and [Cr(NH_(3))_(6)][Co(C_(2)O_(4))_(3)]

Answer»

linkage
geometrical
coordination
ionisation

Answer :C
Discussion
43.

The complex with a maximum number of stereoisomers is:

Answer»

`[PtCl_(3)(C_(2)H_(4))]^(-)`
`[CuBr_(2)Cl_(2)]^(2-)`
`[CO(C_(2)O_(4))_3]^(3-)`
`[Cr(NH_(3))_(2)(en)_(2)]^(3+)`

ANSWER :D
Discussion
44.

The complex which has the highest magnetic moment among the following is

Answer»

`[CoF_(6)]^(3-)`
`[CO(NH_(3))_(6)]^(3+)`
`[NI(NH_(3))_(4)]^(2+)`
`[Ni(CN)_(4)]^(2-)`

SOLUTION :No. of unpaired electrons are 4 in (a), 0 in (b), (c ), (d) and (e). Hence, `[CoF_(6)]^(3-)` has highest magnetic moment.
Discussion
45.

The complex which has no 'd' electrons in the central atom is (Atomic number, Cr= 24, Mn = 25, Fe = 26, Co = 27)

Answer»

`[MnO_(4)]^(-)`
 `[Co(NH_(3))_(6)]^(3+)`
`[Fe(CN)_(6)]^(3-)`
`(Cr(H_(2)O)_(6)]^(3+)`

Solution : Oxidation number of Mn in `[MnO_(4)]^(-)`" is +7 which is achieved by the loss of all `3d^(5)` and `4s^(2)` ELECTRONS
HENCE, (A) is the correct ANSWER.
Discussion
46.

The complex which exhibits geometrical as well as optical isomerism is :

Answer»

`[Co(gly)_(3)]`
`[PT(gly)_(2)]`
`[Co(en)_(3)]Cl_(3)`
`K_(3)[Co(Ox)_(3)]`

Solution :`[Co(gly)_(3)]` exhibits GEOMETRICAL as well as optical isomerism.
Discussion
47.

The complex which exhibits cis-trans isomerism as well as can be resolved into d and ? forms:

Answer»

`[Be(ACAC)_2]`
`[Ir(H_2O)_3(NH_3)_3]^(3+)`
`[CR(en)_3]^(3+)`
`[Rh(H_2O)_2(en)_2]^(3+)`

Answer :D
Discussion
48.

The complex used as an anticancer agent is __________.

Answer»

MER - `[CO(NH_3)_3Cl_3]`
CIS - `[PtCl_2(NH_3)_2]`
cis - `K_2[PT Cl_2Br_2]`
`Na_2CoCl_4`

Answer :B
Discussion
49.

The complex that shows optical activity is :

Answer»

TRANS-`[CoCl_(2)(en)_(2)]^(+)`
cis-`[CoCl_(2)(en)_(2)]^(+)`
trans-`[PtCl_(2)(NH_(3))_(2)]`
`[CoCl_(2)(NH_(3))_(2)(en)^(+)`

Solution : Non-superimposable MIRROR image
Discussion
50.

The complex that shows optical acitivity is

Answer»

`trans-[CoCl_(2)(en)_(2)]^(+)`
`CIS-[CoSl_(2)(en)_(2)]^(+)`
`trans-[PtCl_(2)(NH_(3))_(2)]`
`[CoCl_(2)(NH_(3))_(2)(en)]^(+)`

Answer :B
Discussion