The composition of the equilibrium mixture (Cl_(2) hArr 2Cl), which is attained at 1200^(@)C, is determined by measuring the rate effusion through a pinhole. It is observed that at 1.80 mm Hg pressure, the mixture effuses 1.16 time as fast as Krypton effuses under the same conditions. Calculate the fraction of chlorine molecules dissociated into atoms (Atmic wt. Kr=84).

The composition of the equilibrium mixture (Cl_(2) hArr 2Cl), which is

1.	The composition of the equilibrium mixture (Cl_(2) hArr 2Cl), which is attained at 1200^(@)C, is determined by measuring the rate effusion through a pinhole. It is observed that at 1.80 mm Hg pressure, the mixture effuses 1.16 time as fast as Krypton effuses under the same conditions. Calculate the fraction of chlorine molecules dissociated into atoms (Atmic wt. Kr=84).
Answer» Solution :`(r_("MIX"))/(r_("Kr"))=sqrt((M_("Kr"))/(M_("mix")))` or `1.16 =sqrt((84)/(M))` `(because` TIME of diffusion for both is same) `THEREFORE M =62.425` `Cl_(2) hArr 2Cl` For 1 0 `(1-alpha) 2alpha` TOTAL mole in mixutre `=1-alpha+2alpha=1+alpha` `therefore 71xx(1-alpha)+2alphaxx35.5=(1+alpha)xx62.425` `therefore alpha =0.137` or 13.7%