Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Non- stoichiometric metal deficiency is show in the salts of

Answer»

all metals
alkali metals only
alkaline EARTH metals only
transition metals only

Solution :Metal deficiency DEFECT is shown by transition metals because they POSSES variable VALENCY.
Discussion
2.

Non-stoichiometric hydrides are

Answer»

hydrides of all d-block elements
deficients in hydrogen
the hydrides having hydrogen ATOM in interstitial sites
both (B) and (c)

ANSWER :D
Discussion
3.

Non-stoichiometric cuprous oxide, Cu_2O can be prepared in laboratory. In this oxide, copper to oxygen ratio is slightly less than 2:1. Can you account for the fact that this substance is a p-type semiconductor ?

Answer»

Solution :In `Cu_2O`,the number of`Cu^(+)` IONS have been replaced by `Cu^(2+)` ions. As a result, there is a CATIONIC vacancy in the crystal structure.
The electrical neutrality is maintained by presence of `Cu^(2+)` ions that replace `Cu^(+)` ions as a result the hole is created.
Thus, the conduction takes place by the presence of hole and HENCE it is p-type semiconductor.
Discussion
4.

Non-stoichiometric cuprous oxide, Cu_(2)O can be prepared in laboratory. In this oxide, copper to oxygen ratio is slightly less than 2 : 1. Can you account for the fact that this substance is a p-type semiconductor ?

Answer»

Solution :As the RATIO is less than `2: 1`, it INDICATES that some `CU^(+)` ions have been replaced by `Cu^(2+)` ions. For every two `Cu^(+)` ions displaced from the lattice site, one `Cu^(2+)` ion will be replaced to maintain ELECTRICAL neutrality. Thus, for every `Cu^(2+)` in the lattice, one HOLE will be created. These positive holes will be responsible for conduction of electricity. Hence, it is a p-type conductor.
Discussion
5.

Non-stoichiometric cuprous oxide, Cu_(2)O can be prepared in laboratory. In this oxide, copper to oxygen ratio is slightly less than 2 : 1. Can you account for the fact that this substance is a p-type semi-conductor ?

Answer»

Solution :SINCE the ratio of Cu: O in `Cu_(2)O` is less than 2: 1, THEREFORE, `Cu_(2)O` is non-stoichiometric crystal. This means that some Cut ions have been replaced by `Cu^(2+)` ions. To MAINTAIN electrical neutrality, every two `Cu^(2+)` ions will be replaced by one `Cu^(2+)`ION thereby creating a hole. Since the conduction will be due to the presence of these positive holes, it is a p-type semiconductor.
Discussion
6.

Non-stoichiometric compound Fe_(x)O (where 0.84ltxlt0.96) is formed due to metal deficiency defects in the crystal structure of FeO. The electrical neutrality of the crystal of Fe_(x)O is maintained because when one Fe^(2+) ion leaves the crystal-

Answer»

one oxide ion in the form of `O_(2)(g)` LEAVES the crystal
one `Fe^(2+)` ion and one `Fe^(3+)` ion GET reduced
two `Fe^(2+)` IONS and two `Fe^(3+)` ions get reduced
two `Fe^(2+)` ions OXIDISE to two `Fe^(3+)` ions

Answer :D
Discussion
7.

Non-stoichiometric compounds are formed by

Answer»

 ALKALI METALS
 transition elements
oble gases
more than one of the above SAID elements

Answer :B
Discussion
8.

Non stoichiometric compounds are formed by :

Answer»

ALKALI metals
Transition elements
Noble gases
More than ONE of the above SAID elements

Answer :B
Discussion
9.

Non - sticking frying pans are coated with teflon which is polymer of

Answer»

Ethylene
Styrene
Tetrafluoro ethyulene
CHLORO- FLUOROMETHANE

Answer :C
Discussion
10.

Non-Stick cookwares generally have a coating of a polymer, whose monomer is

Answer»

`CH_(2)=CH_(2)`
`CH_(2)=CHCN`
`CH_(2)=CHCI`
`CF_(2)=CF_(2)`

Solution :`nCF_(2) = CF_(2) to + CF_(2) - CF_(2)+_(n)` Teflonis usedfor non-stick cookwares.
Discussion
11.

Non-sticking frying pans are coated with which polymer?

Answer»

Ethylene
styrene
Tetrafluoro ethylene
Chloro FLUORO methane

Answer :C
Discussion
12.

Non stick cook wares generally have a coating of a polymer, whose monomer is

Answer»

ethane
prop-2-enenitrile
chloroethene
1,1,2,2-tetrafluoroethane

Solution :1,1,2,2-tetrafluoroethane
Discussion
13.

Non-reducing sugar is

Answer»

MALTOSE
SUCROSE
lactose
none of these.

ANSWER :B
Discussion
14.

Non reducing sugar end with suffix

Answer»

oside
ose
one
al

Answer :A
Discussion
15.

Non reacting gases have a tendency to mix with each other. This property is known is :

Answer»

Diffusion
Fusion
Mixig
None

Answer :A
Discussion
16.

Non-polar molecule among the following is

Answer»

`SF_4`
`BF_3.NH_3`
`PF_3Cl_2`
`XeF_4`

ANSWER :D
Discussion
17.

Non- polar molecule is:

Answer»

`BCl_3`
`H_2O`
`NCl_3`
`PCl_3`

ANSWER :A
Discussion
18.

Non-oxide ceramics can be

Answer»

`B_(4)C`
`SIC`
`Si_(3)N_(4)`
All of these

Solution :The carbides, nitrides or oxynitrides are GENERALLY called non-oxide ceramics. They have high proportion of covalent bond. They are exclusively from SYNTHETIC raw materials.
Discussion
19.

Non-metals combine with oxygen to form usually

Answer»

BASIC oxides
neutral oxides
acidic oxides
amphoteric oxides

SOLUTION :Non-metals FORMS only acidic oxides `C+O_(2) to CO_(2)`
Discussion
20.

Non - lanthanoid atom is

Answer»

LA
Lu
Pr
Pm

Solution :La(LANTHANUM) is NON LANTHANOID ATOM.
Discussion
21.

Non - ionogenic surfactants are 

Answer»


`C_(17)H_(35)CO ONa`
`C_(n)H_(2n + 1) (OCH_2CH_b)_x OH`
 

SOLUTION :`C_nH_(2n + 1)(OCH_2CH_6)_x OH`- octyl glycol ether, `alpha`- octyl glyceryl ether and octyl glucoside
Discussion
22.

Non-ideal solutions exhibit either positive or negative deviations from Raoult's law. What arethese deviations and why are they caused ? Explain with one example for each type.

Answer»

Solution : POSITIVE deviations : In this type of solutions, the total vapour pressure is more than that expectedfrom Raoult.s law, `DELTA V_( mix)` and `Delta H_( mix)`are always positive.
Examples : acetone + benzene, ETHYL ALCOHOL + chloroform.
Negative deviations : In this type of solutions, total pressure for any mole fraction is less than that according to Raoult.s law. For such solutions, `Delta V_(mix)` and `DeltaH_(mix)`are negative.
Examples : benzene + chloroform, water + sulphuric acid.
Discussion
23.

Non-ideal solutions exhibit either positive or negative deviation from Raoult's law. What are these deviations and why are they caused? Explain with one example for each type.

Answer»

Solution :`=+ve` DEVATION : Ethyl ALCOHOL and CYCLOHEXANE
-ve DEVIATION : Water and nitric acid
Discussion
24.

Explain the following terms with suitable examples. Non-ionic detergents.

Answer»


ANSWER :T
Discussion
25.

Non-ionic detergent dissolve in water by form ____

Answer»

SOLUTION :HYDROGEN BOND
Discussion
26.

Non - electrolyte colloidal surfactants is

Answer»

`C_(12)H_(35) COONa`
`C_(17)H_(35)COONa`
`C_(n)H_(2n+1) ( OCH_(2)CH_(2))_(X)OH`
All

ANSWER :C
Discussion
27.

Non-combustible hydride is

Answer»

 `NH_(3)`
`PH_(3)`
`AsH_(3)`
`SbH_(3)`

ANSWER :A
Discussion
28.

Non- combustible hydride is:

Answer»

`PH_3`
`AsH_3`
`SbH_3`
`NH_3`

ANSWER :D
Discussion
29.

Non-directional orbital is:

Answer»

3s
4f
4d
4p

Answer :A
Discussion
30.

Non-aromatic compound among the given compounds is

Answer»




ANSWER :A
Discussion
31.

Noble gases were considered inert before 1962. Prior to this, Bartlett and Lohmann had previously used the highly ionization energy of O_(2) is 1165 " kJ mol"^(-1), which isalmost the same as the value of IE_(1) for Xe (1170 " kJ mol"^(-1)) . Experiments showed that when deep red PtE_(6) vapours were mixed with an equal volume of Xe, the gases combined immediately at room temperature to produce a yellow solid. Soon after this, it was found that Xe and F react directly to give Xe-fluorides. Choose the correct answer : The hybridisation state of Xe in XeOF_(4) is :

Answer»

`sp^(3)`
`sp^(3)d`
`DSP^(2)`
`sp^(3) d^(2)`

SOLUTION :Xe atom in `XeOF_(4) " is " sp^(3)d^(2)` hybridised.
Discussion
32.

Noble gases were considered inert before 1962. Prior to this, Bartlett and Lohmann had previously used the highly ionization energy of O_(2) is 1165 " kJ mol"^(-1), which isalmost the same as the value of IE_(1) for Xe (1170 " kJ mol"^(-1)) . Experiments showed that when deep red PtE_(6) vapours were mixed with an equal volume of Xe, the gases combined immediately at room temperature to produce a yellow solid. Soon after this, it was found that Xe and F react directly to give Xe-fluorides. Choose the correct answer : In what molar ratio must Xe and F_(2) combine to give XeF_(4) ?

Answer»

`2 : 1`
`1 : 2`
`1 : 5`
`1 : 20 `

Solution :It is the correct RATIO.
Discussion
33.

Noble gases were considered inert before 1962. Prior to this, Bartlett and Lohmann had previously used the highly ionization energy of O_(2) is 1165 " kJ mol"^(-1), which isalmost the same as the value of IE_(1) for Xe (1170 " kJ mol"^(-1)) . Experiments showed that when deep red PtE_(6) vapours were mixed with an equal volume of Xe, the gases combined immediately at room temperature to produce a yellow solid. Soon after this, it was found that Xe and F react directly to give Xe-fluorides. Choose the correct answer : What was the yellow solid obtained by them ?

Answer»

`[XeF_(2)]^(+) [PtF_(6)]^(-)`
`[XeF]^(+) [PtF_(6)]^(-)`
`Xe^(+) [PtF_(6)]^(-)`
`[PtF_(4)][XeF_(7)]`

Answer :C
Discussion
34.

Noble gases with the highest ionisation energy and greater solubility in water are respectively

Answer»

He and AR
XE and Rn
Xe and He
He and Xe

Answer :D
Discussion
35.

Noble gases possess:

Answer»

HIGHLY IONISATION potential
Xzero ELECTRON affinity
High ELECTRICAL conductance
All

Answer :D
Discussion
36.

Noble gases have very low boiling points. Why?

Answer»

SOLUTION :The boiling points of noble gases are very low since their atoms are held together by weak VAN der Waals FORCES of attraction.
Discussion
37.

Noble gases have very low boiling points. Why ?

Answer»

Solution :Noble gases being monoatomic have no INTERATOMIC forces except WEAK dispersion forces and therefore, they are LIQUEFIED at very LOW temperatures. Hence, they have low boiling points.
Discussion
38.

Noble gases have____M.P. and B.P.

Answer»

SOLUTION :very LOW
Discussion
39.

Noble gases have very low boiling point. Why ?

Answer»

Solution :DUE to WEAK DISPERSION force between their atoms.
Discussion
40.

Noble gases have very high ionisation enthalpy. Why ?

Answer»

Solution :Due to stable ELECTRONIC configuration `(NS^(2) np^(6))`.
Discussion
41.

Noble gases have larger atomic size than the preceeding halogens because

Answer»

They are gases
They have low REACTIVITY
Vanderwaals RADIUS is considered in them
They are INSOLUBLE in WATER

ANSWER :C
Discussion
42.

Noble gases have large positive values of electron gain enthalpy. Why ?

Answer»

SOLUTION :Since noble gases have stable - ELECTRONIC configurations, they have no tendency to accept the ELECTRON. Therefore, they have HIGH `+ve` electron gain enthalpy.
Discussion
43.

Noble gases have

Answer»

HIGH IONISATION ENTHALPY and more negative electron GAIN enthalpy.
low ionisation enthalpy and more negative electron gain enthalpy.
high ionisation enthalpy and more positive electron gain enthalpy.
low ionisation enthalpy and more positive electron gain enthalpy.

Solution : high ionisation enthalpy and more positive electron gain enthalpy.
Discussion
44.

Noble gases exists only in monoatomic state. This is due to

Answer»

Non availability of UNPAIRED electrons
high IONIZATION energy
LARGE size
zero electron affinity

Answer :A
Discussion
45.

Noble gases do not occur in:

Answer»

Nature
Ores
Atmosphere
Sea water

Answer :D
Discussion
46.

Noble gases do not react with other elements because:

Answer»

They are monoatomic
They are not FOUND in abundance
The SIZE of their ATOMS are very small
They have COMPLETELY paired up and STABLE electron shells.

Answer :D
Discussion
47.

Noble gases are used in discharge tubes to give different colours. The gas in Beacon lights for pilots used is?

Answer»

Ar
Ne
Xe
Kr

Answer :B
Discussion
48.

Noble gases can be separated by :

Answer»


ANSWER :C
Discussion
49.

Noble gases are used in discharge tubes to give different colours. Reddish-orange glow is due to

Answer»

Ar
Ne
Xe
KR

Solution :Noble gases are used in discharge tubes to GIVE DIFFERENT COLOURS. Reddish orange glow is due to Ne.
Discussion
50.

Noble gases are sparingly soluble in water, owing to

Answer»

dipole-dipole interactions
dipole-induced dipole interactions
hydrogen bonding
induced dipole-instantaneous dipole interactions.

Solution :WATER is a permanent dipole and it induces a dipole in the NEIGHBORING ATOMS of noble GAS. Because of this weak interaction, the noble gases are SPARINGLY soluble.
Discussion