This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Nuclear reactions accompained with emission of neutron (s)are |
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Answer» `""_(13)^(27)Al+_(2)^(4)He to _(15)^(30)P` |
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| 2. |
Nuclear hydroxy derivatives are called _____ and side chain substituted hydroxy derivatives are called _____. |
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Answer» PHENOLS, phenols |
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| 3. |
Nuclear isomerism is exhibited by- |
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Answer» MOLECULES H only |
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| 4. |
Nuclear fusion produces: |
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Answer» Argon |
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| 5. |
Nuclear energy is the result of conversion of : |
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Answer» NEUTRONS to protons |
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| 6. |
Nuclear energy is based on the conversion of: |
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Answer» PROTONS into neutrons |
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| 7. |
Nuclear charge actually experienced by an electron is termed as effective nuclear charge. The effective nuclear charge Z^(**) actuall ydepends on type of shell and orbital in which electron is actually present. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is s gt p gt d gt f (for the same value of n) The phenomenon in which penultimate shell electrons act as screen or sheild in between nucleus and valence shell electrons and thereby reducing nuclear charge is known as shielding effect. the penultimate shell electrons repel the valence shell electron to keep them loosely held with nucleus. it is thus evident that more is the shielding effect, lesser is the effective nuclear charge and lesser is the ionization energy. Q. Which of the following is not concerned to effective nuclear charge? |
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Answer» HIGHER ionization potential of carbon than boron |
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| 8. |
Nuclear charge actually experienced by an electron is termed as effective nuclear charge. The effective nuclear charge Z^(**) actuall ydepends on type of shell and orbital in which electron is actually present. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is s gt p gt d gt f (for the same value of n) The phenomenon in which penultimate shell electrons act as screen or sheild in between nucleus and valence shell electrons and thereby reducing nuclear charge is known as shielding effect. the penultimate shell electrons repel the valence shell electron to keep them loosely held with nucleus. it is thus evident that more is the shielding effect, lesser is the effective nuclear charge and lesser is the ionization energy. Q. Ionzation enegy is not influenced by: |
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Answer» Size of atom |
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| 9. |
Nuclear charge actually experienced by an electron is termed as effective nuclear charge. The effective nuclear charge Z^(**) actuall ydepends on type of shell and orbital in which electron is actually present. The relative extent to which the various orbitals penetrate the electron clouds of other orbitals is s gt p gt d gt f (for the same value of n) The phenomenon in which penultimate shell electrons act as screen or sheild in between nucleus and valence shell electrons and thereby reducing nuclear charge is known as shielding effect. the penultimate shell electrons repel the valence shell electron to keep them loosely held with nucleus. it is thus evident that more is the shielding effect, lesser is the effective nuclear charge and lesser is the ionization energy. Q. Which of the following valence electron experience maximum effective nuclear charge? |
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Answer» `4S^(1)` |
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| 10. |
Nucelophilic aliphatic substitution reaction is given by those compounds which have nucleophiic groups as leaving. Less is the basicity of the leaving group. More is its leaving power. Leaving group in the form of nucleophile (charged of neutral) Leaving power of which groups is maximum ? Which one of the following compounds may NOT given SN rection ? |
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Answer» `R-overset(o+)N-=N` |
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| 11. |
Nucelophilic aliphatic substitution reaction is given by those compounds which have nucleophiic groups as leaving. Less is the basicity of the leaving group. More is its leaving power. Leaving group in the form of nucleophile (charged of neutral) Leaving power of which grops is maximum ? Leaving power of which group is maximum ? |
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Answer» `-O-UNDERSET(O) underset(||)overset(O) overset(||)S-CF_(3)` |
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| 12. |
ntoOrbit no , zto Atomic no implies r_(n.z)to Radiusv_(n.z)to Velocity T_(n.z)to Time period of Revolution implies K_(n.z)to kinetic energy of the electron {:("Column-I","Column-II"),("(for single electron species)","(Ratio)"),((A)r_(2,1):r_(1,2),(P)"9:1"),((B)V_(1,3):V_(3,1),(Q)"8:1"),((C )T_(1,2):T_(2,1),(R)"16:1"),((D)K_(1,2):K_(2,1),(S) "1:32"):} |
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Answer» |
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| 14. |
Now carbohydrates are regarded as : |
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Answer» AROMATIC compounds |
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| 15. |
Now a days, how quantity of electricity Q can be measured in electrolytic cell ? |
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Answer» Solution :* Now we have CONSTANT CURRENT (I) sources available and the quantity of electricity Q passed is GIVEN by : `Q=It` Where, I=current in AMPERE t=time in second for PASSES of current. Q=current in Coulomb. |
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| 16. |
Now a days , the reagentused in Hinsberg method is _________ |
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Answer» p-tolueensulphonyl chloride |
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| 17. |
Novolac, the linear polymer used in paints is |
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Answer» copolymer of buta-1, 3-diene and styrene |
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| 18. |
Novolac,the linear polymer used in paintsis |
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Answer» copolymer of 1,3-butadieneand styrene |
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| 19. |
Novolac on heating with formaldehyde undergoes ___________ to form an infusible solid mass called ____________ . |
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Answer» a. POLYMERISATION , MELAMINE |
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| 20. |
Novolac is of which type polymer ? |
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Answer» LINEAR Novolac is linear polymer, it can be SHOWN as below :
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| 21. |
Novolac is |
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Answer» CROSS linked polymer |
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| 22. |
Novalgin is well known |
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Answer» antipyretic |
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| 24. |
Note the following balanced chemical equation 2CO+O_(2)implies 2CO_(2) Which one of the following statement is significant in relation to the above chemical equation ? |
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Answer» ONE can add to a VESSEL oly 2 mol of co for each mol of `O_(2)` added |
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| 26. |
Note : Hints for Q. No. 10 are given on next Page |
Answer» SOLUTION :
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| 27. |
Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H^(-) is : |
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Answer» 3 |
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| 28. |
Normally FeCl_(3).6H_(2)O consists of |
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Answer» TRANS `[FE(H_(2)O)_(2)Cl_(2)]CL.4H_(2)O` |
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| 29. |
Normally hydrogen is placed in |
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Answer» IA |
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| 30. |
A solution is defined as a : |
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Answer» NUMBER of eq/litre of SOLUTION |
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| 31. |
Normality of pure sulphuric acid is: |
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Answer» 4 N |
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| 32. |
Normality of 1 % H_(2)SO_(4) solution is nearly |
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Answer» `2.5` |
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| 33. |
Normality (N) of a solution is equal to |
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Answer» `("No. of moles of solute")/("Volume of SOLUTION in litre")` |
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| 34. |
Normal melting point and boiling point of rhombic sulphur are 387.5 K and 717.6 K respectively. When sulphur is heated in a test tube to 455 K and the test tube in verted, the content which pour out is |
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Answer» PLASTIC sulphur |
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| 35. |
Normal freezing point of a solvent is 5^(@)C A 0.5 nilal solution of urea in the this solvent causes freezing point depression of two degrees. Calculate the molal depression constant. |
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Answer» `K_(f)=(DeltaT_(f))/m=(2K)/(0.5m)=4KM^(-1)` |
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| 36. |
Normal freezing point of a solvent is 15^(@)C. A 0.5 molal solution of urea in the above solvent causes a freezing point depression of two degrees. Calculate the molal depression constant. |
| Answer» SOLUTION :`"4 K m"^(-1)` | |
| 37. |
Normal freezing of a solvent is 5^(@)C. A 0.5 molal solution of urea in this solvent causes a freezing point depression of two degree. Calculate molal depression constant. (K_(f)) |
| Answer» Solution :`K_(F)=(DeltaT_(f))/m=(2K)/(0.5m)=4KM^(-1)` | |
| 38. |
Normal boiling of water is 373 K (at 760 mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be |
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Answer» 250 K `log.(P_(2))/(P_(1))=(Delta H_(V))/(2.303R)[(T_(2)-T_(1))/(T_(1)xxT_(2))]` `log.(760)/(23)=(40656)/(2.303xx8.314)[(373-T_(1))/(373T_(1))]` This gives `T_(1)=294.4 K`. |
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| 39. |
Normal aluminium electrode coupled with normal hydrogen electrode gives an emf of 1.66V. So the standard electrode potential of aluminium is |
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Answer» `-1.66V` |
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| 40. |
Normal aluminium electrodecoupled with normal hydrogen electrode gives an e.m.f. of 1.66 volts. So the standard electrode potential of aluminium is:- |
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Answer» `-1.66V` `=O-E_(Al^(3+)//Al)^(o)` or `E_(Al^(3+)//Al)=-1.66V` |
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| 41. |
Normal aluminium electrode coupled with normal hydrogen electrode gives an emf of 1.66 volts . So the standard electrode potential of aluminium is |
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Answer» `-1.66` V |
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| 42. |
Normal alkanes can undergo sulphonation if they contain: |
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Answer» 4 CARBON atoms |
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| 43. |
Normal aluminum coupled with normal hydrogen electrode gives an emf of 1.66 V. The standard electrode potential of aluminium is : |
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Answer» `-1.66V` |
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| 44. |
Norethindrone is which type of drugs? |
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Answer» ANTIFERTILITY |
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| 45. |
Norethindrone is an example of synthetic progesterone derivative which is most widely used as |
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Answer» Antiseptics |
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| 46. |
Norethindrone is an example of |
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Answer» SYNTHETIC testosterone |
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| 48. |
Non-stoichiometry is shown 1) due to variable valency of transition metals 2) due to defect in solid structure 3) reducing nature Correct statemet (s) is /are |
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Answer» 1,2 |
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