Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

It has been estimated that the total energy ratiated by sun is 3.8 xx 10^(26) j per second. The source of energy of stars is a thermonuclear reaction called nuclear fusion. Fusion reactions are not controlled. It is presumed that the energy of stars is due to two processes called proton-proton cycle and carbon-nitrogen cycle and carbon-nitrogen cycle. Fusion cannot take place at ordinary temperature. Thus, hydrogen bomb uses a small fission bomb, which on explosin causes the temperature to rise very high, about 10^(7) K. We have yet to see how a hydrogen bomb can be used for peaceful life-sustaining purpose. Energy released in the process of fusion is due to mass defect. It is also called Q-value Q = Delta mc^(2),Delta M = mass defect The binding energy per nucleon of ._(1)^(2)H and ._(2)^(4)He are 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is:

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13.9 MeV
26.9 MeV
23.6 MeV
19.2 MeV

Answer :C
2.

"Kg m"^(-1)s^(-2) is the unit of………………….. .

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SOLUTION :PRESSURE
3.

Isotropy.

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Solution :The ABILITY of amorphous SOLIDS to EXHIBIT identical physical properties even though measured in DIFFERENT directions is called isotropy.
4.

KF has NaCl structure. What is the distance between K^(+) and F^(-) in KF, if its density is 2.48 g cm^(-3) ?

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Solution :For NACL type structure, Z=4, M = 39 +19=58.0g `mol^(-1)`, d=2.48 g `cm^(-3)`
`a^3=(Z xx M)/(N_A xx d)=(4 xx 58.0)/(6.023 xx 10^(23) xx 2.48) = 15.53 xx 10^(-23) cm^3`:
`a = 5.375 xx 10^(-8)` cm= 537.5 pm
For NaCl type structure, a = `2 xx "interionic distance"`.
`:.` Distance between K and `F^(-)` ions = `(537.5)/(2)` = 268.75 pm
5.

Isotopes of oxygen with mass number less than 16 undergo beta^+emission. Assuming an equimolar mixture of ""^14Oand ""^15O,find the ratio of the nuclides at the end of one hour. Given that t_(1//2) (""^14O) = 71 s and t_(1//2) (""^15O) = 124 s . At what time will the above said ratio be equal to 0.25?

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SOLUTION :`3.29 XX 10^(-7) , 332 s`
6.

KF has NaCl structure. The edge length of its unit cell has been found to be 537.6 pm. The distance between K^(+) and F^(-) in KF is :

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537.6pm
268.8pm
1075.2pm
cannot be calculated

Solution :In KF, edge LENGTH is equal to `2(r_(K^(+))+r_(F^(-)))` so that,
`r_(K^(+))+r_(F^(-))= ( 537)/( 2) = 268.8`PM
7.

Isotopes of oxygen with mass number less than 16 undergobeta^+ emission. Assumingan equimolar mixture of ""^14Oand ""^15O , find the ratio of the nuclides at the end of one hour. t_(1//2) for ""^14O= 71 s, t_(1//2) for ""^15O=124 s.At what time will the ratio of ""^14Onuclei to ""^15Onuclei be equal to 0.25?

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SOLUTION :`3.02 XX 10^(-7) , 332 s `
8.

K_(f) for water is "1.86 K kg mol"^(-1). If your automobiles radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C?

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27 g
72 g
93 g
39 g

Solution :`M_(2)=(1000K_(F)w_(2))/(w_(1)DeltaT_(f))`
`therefore""62=(1000xx1.86xxw_(2))/(1000xx2.8)"or"w_(2)=93.3g`
9.

Isotopes were discovered by

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Aston
Soddy
Thomson
Mullikan

Answer :B
10.

K_(f) for water is 1.86^(@)C*m^(-1). What is the molality of a solutionn which freezes at -0.192^(@)C? Assuming no change in the solute by raising the temperature, at what temperature will the solution boil ? (K_(b) for H_(2)O=0.515^(@)C*m^(-1))

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SOLUTION :MOLALITY `=(DeltaT_(f))/(K_(f))`
`=(0.192)/(1.86)=0.103m`
Again `DeltaT_(B)=K_(b).m` …………(Eqn. 8)
`=0.515xx0.103=0.0532^(@)C`
Assuming the b.p. of pure water to be `100^(@)C` the b.p. of the solution will be `100.0532^(@)C`
11.

Isotopes of same elemeents have the same number of

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Protons
Neutrons
Deutrons
None

Solution :Isotopes of same ELEMENTS have the same NUMBER of protons but DIFFERENT number of neutrons.
12.

KF has ccp structure . Calculate the radius of unit cell if the side of the cube or edge length is 400 pm . How many F ions and octahedral voids are there in this unit cell ?

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SOLUTION :For ccp lattice
`r=(sqrt2a)/(4) or r=(1.414xx"400 pm")/(4) or r=141.4" pm"`
There are `4F^(-)` IONS and 4 octahedral VOIDS.
13.

Isotopes are the atoms of same element, they have same atomic number but different mass numbers. Isotopes have different number of neutrons in their nucleus . If an element exists in two isotopes having atomic masses 'a' and 'b' in the ratio m:n, then average atomic mass will be (mxxa+nxxb)/(m+n) Different isotopes of same element have same position in the periodic table. the elemens which have single isotope are called monoisotropic elements. Greater is the percentage composition of an isotope, more will be its abundance in nature. .^(12)C and .^(14)C isotopes are found at 98% and 2% respectively in any sample. then, the number of .^(14)C atoms in 12g of the sample will be:

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1.5 mole atoms
`1.032xx10^(22)` atoms
`2.06xx10^(21)` atoms
2G atoms

Answer :B
14.

K_(f) for water is 1.86 K kg mol^(-1). If your automobile radiator holds 1.0 kg of water, how may grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to - 2.8^(@)C

Answer»

72 g
93 g
39 g
27 g

Solution :`Delta T_(F)= i XX k_(f)xx m`
`2.8=1xx1.86xx(x)/(62xx1)`
`x=(2.8xx62)/(1.86)=93 GM`
15.

Isotopes are the atoms of same element, they have same atomic number but different mass numbers. Isotopes have different number of neutrons in their nucleus . If an element exists in two isotopes having atomic masses 'a' and 'b' in the ratio m:n, then average atomic mass will be (mxxa+nxxb)/(m+n) Different isotopes of same element have same position in the periodic table. the elemens which have single isotope are called monoisotropic elements. Greater is the percentage composition of an isotope, more will be its abundance in nature. The ratio of mass of .^(12)C atom to that of an atom of element X(whose atomicity is four) is 1:9. the molecular mass of element X is:

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480 G `"mol"^(-1)`
`432g "mol"^(-1)`
`36 g "mol"^(-1)`
`84g "mol"^(-1)`

ANSWER :B
16.

Isotopes are the atoms of same element, they have same atomic number but different mass numbers. Isotopes have different number of neutrons in their nucleus . If an element exists in two isotopes having atomic masses 'a' and 'b' in the ratio m:n, then average atomic mass will be (mxxa+nxxb)/(m+n) Different isotopes of same element have same position in the periodic table. the elemens which have single isotope are called monoisotropic elements. Greater is the percentage composition of an isotope, more will be its abundance in nature. Which of the following isotopes is/are used to decide the scale of atomic mass?

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`._(6)^(12)C`
`._(6)^(14)C`
`_(8)^(16)O`
`._(7)^(14)N`

Answer :A::C::D
17.

K_(f) for water is 1.86 K kg "mol"^(-1). If your automobile radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(6)) must you add to get the freezing point of the solution lowered to - 2.8^(@)C ?

Answer»

93 G
39 g
27 g
72 g

Answer :A
18.

Isotopes are the atoms of same element, they have same atomic number but different mass numbers. Isotopes have different number of neutrons in their nucleus . If an element exists in two isotopes having atomic masses 'a' and 'b' in the ratio m:n, then average atomic mass will be (mxxa+nxxb)/(m+n) Different isotopes of same element have same position in the periodic table. the elemens which have single isotope are called monoisotropic elements. Greater is the percentage composition of an isotope, more will be its abundance in nature. The isotopes of chlorine with mass number 35 and 37 exist in the ratio of. . . .. Its average atomic mass is 35.5.

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`1:1`
`2:1`
`3:1`
`3:2`

ANSWER :C
19.

KF crystallizes in fce structure like sodium chloride. calculate the distance between K^(+) and F^(-) in KF. ("given : density of KF is 2.48 g cm"^(-3))

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Solution :`"DENSITY of KF"="2.48 g cm"^(-3)`
`RHO=(nM)/(a^(3)N_(A))`
N = 4 (For Fcc)
`rho=(4xx58)/(a^(3)xx6.023xx10^(23))`
`2.48=(4xx58)/(a^(3)xx6.023xx10^(23))`
`a^(3)=(4xx58)/(2.48xx6.023xx10^(23))`
`a^(3)=(232)/(14.93xx10^(23))`
`a^(3)=15.54xx10^(-23)`
`a="537.5 pm"`
`d=(a)/(sqrt2)"(For fcc)"`
`d=(537.5)/(1.414)`
`d=380.12" pm"`
20.

Isotope of which noble gas is isotonic (same number of neutrons) with Tritium?

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Ne
He
Kr
Rn

Answer :B
21.

K_f(+10)/K_tis known as :

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Ratio of equilibrium constants
TEMPERATURE coefficient
Difference in temperature of REVERSIBLE reactions
None of the above

Answer :D
22.

Ketoximes are oxidised into 2^(@)-nitroalkane by using

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`kMnO_(4)`
`K_(2)Cr_(2)O_(7) + dil.H_(2)SO_(4)`
trifluoroperoxy acetic ACID
PYRIDINIUM chlorochromate

Answer :C
23.

Isotope of uranium used in atomic bomb is

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`._(92)^(237)U`
`._(92)^(238)U`
`._(92)^(239)U`
`._(92)^(235)U`

ANSWER :B
24.

Ketoxime on oxidation by trifluoroperoxy acetic acid gives

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`1^(@)` - NITROPARAFFINS
`2^(@)` - nttroparaffins
`3^(@)` - nitroparaffins
`1 ^(@)` - amines

Answer :B
25.

Isotonic solutions must have the same………..

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SOLTE
density
elevation in boilling point
depression in freezing point

SOLUTION :istonic SOLUTIONS have same MOLAR CONCENTRATION and therefore, same colligative properties. Options (c,d) are both correct.
26.

Ketoximeon reductiongives

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`1^(0)` AMINES
`2^(0)` amines
`3^(0)` amines
all of these

ANSWER :A
27.

Ketonic form of acetone contains,

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`8 - sigma " bond and " 2 - pi ` bonds
`9-sigma " bonds and " 1 - pi` bond
`7 - sigma" bonds and " 3 - pi` bonds
`4- sigma " bonds and " 5-pi` bonds

ANSWER :B
28.

Isotonic solutions must have the same …………… .

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solute
density
elevation in BOILING POINT
depression in freezing point

Solution :ISOTONIC solutions have same MOLAR CONCENTRATION and hence same elevation in boiling point and same depression in freezing point.
29.

Isotonic solutions must have the same …….

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Solute
Density
Elevation in boiling POINT
DEPRESSION in FREEZING point

Answer :C::D
30.

Ketones react with X to give ketal X. is

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glycerol.
glycol.
ethyl alcohol
methanol.

Answer :B
31.

Isotonic solutions have

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same BOILING POINT
same VAPOUR pressure
same MELTING point
same OSMOTIC pressure.

Answer :D
32.

Isotonic solutions have :

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same BOILING point
same VAPOUR pressure
same melting point
same OSMOTIC pressure

SOLUTION :Same osmotic pressure SOLUTIONS are called isotonic solutions.
33.

Ketones react with Mg-HG over water gives

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Pinacolone
Pinacols
Alcohols
None of these

Solution :Two molecules of ketones undergo reduction in the presence of `Mg//Hg` to form pinacol.

`OVERSET(HOH)rarr underset(("pinacol"))underset(2,3-"dimethylbutane-2,3-diol")(CH_(3)-overset(" "CH_(3))overset(|)underset(OH)underset(|)(C)-overset(" "CH_(3))overset(|)underset(OH)underset(|)(C)-CH_(3)+Mg(OH)_(2))`
34.

Ketones (R-overset(O)overset("||")C-R') can be obtained in one step by(where R and R' are alkyl groups)

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hydrolysis of ESTERS
oxidation of primary ALCOHOLS
oxidation of secondary alcohols
reaction of ALKYL halides with alcohols.

Answer :C
35.

Isotonic solutions are those which have the:

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Same OSMOTIC PRESSURE
Same molarity
Same density
Same normality

Answer :A
36.

ketones [R-undersetOunderset"||"C-R_1 , where R=R_1 = alkyl groups ] can be obtained in one step by

Answer»

oxidation of primary alcohols
hydrolysis of esters
oxidation of TERTIARY alcohols
reaction of acid HALIDES with alcohols

Solution :By oxidation of tertiary ALCOHOL with stronger oxidising agents, ketones MAY be formed ALONG with carboxylic acid
37.

Isotonic solutions are the solutions having the same

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SURFACE tension
vapour pressure
osmotic pressure
viscosity

Answer :C
38.

Ketones (R-underset(O)underset(||)(C )-R_(1)) where R=R_(1)= alkyl group. It can be obtained in one step by

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HYDROLYSIS of esters
Oxidation of PRIMARY alcohol
Oxidation of secondary alcohol
Reaction of ACID HALIDE with alcohols

Answer :C
39.

Ketones R- overset(O) overset(||)(C) - R' where R = R' alkyl group can be obtained in one step by

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oxidation of `1^(@)` ALCOHOL
HYDROLYSIS of ester
hydrolysis of acid anhydride
oxidation of `2^(@)` alcohol

ANSWER :D
40.

Isotonic solutions have same

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DENSITY
Molar CONCENTATION
Normality
None of these

ANSWER :B
41.

Ketones on reduction with ........... amalgam and water form pinacols.

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SOLUTION :MAGNESIUM
42.

Isotonic solutions.

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SOLUTION :The SOLUTIONS having the same OSMOTIC pressure at a given temperatureare called ISOTONIC solution.
43.

Ketones on reaction with NH_2CONHNH_2 form well defined crystalline compounds called:

Answer»

Hydrazones
Schiff's base
Oximes
Semicarbazones

Answer :D
44.

Isotonic solutions are solutions having the same

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SURFACE tension
Vapour pressure
Osmotic pressure
Viscosity

Answer :C
45.

Isothermally and reversibly, one mole of argon expands from 2 m^3 to 20 m^3 and produces 831.4 J of work. The temperature at which expansion takes place is __________ .(R=8.314 JK^-1 mol^-1)

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4342 K
43.42 K
434.2 K
316.42 K

Answer :B
46.

Isothermally at 27^(@) C, 1 mole of van der Waals gas expands reversibly from 2L to 20 L work done if a=1.42 xx 10^(12) dynes cm^(4)//"mole" and b=30 cc/mole

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`5.677 XX 10^(3)` kJ
`2.3 xx 10^(7)` kJ
`9.2 xx 10^(3)` kJ
`7.689 xx 10^(3)` kJ

Answer :A
47.

Ketones do not undergo oxidation easily due to _____.

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SOLUTION :STRONG carbon-carbon BOND
48.

Isothemal compresslbility (K) of a gas is defined as K=(1)/(V) ((dV)/(dP))_(nT). lsothermal compressibility of an ideal gas at 1.0 atmis:

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`0.1" ATM"^(-1)`
`0.01" atm"^(-1)`
`1.0" atm"^(-1)`
`0.01" atm"^(-1)`

ANSWER :C
49.

Ketones cannot be prepared in one step from

Answer»

ALCOHOLS
ALKENES
ALKYNES
ESTERS

ANSWER :D
50.

Isostructural group of molecules are

Answer»

`NH_(3) , NF_(3) , BF_(3)`
`NO_(3) , NO_(2) , SF_(4)`
`XeO_(4), NH_(4)^(+) , CH_(4)`
`CH_(3)^(-) , NH_(3) , NF_(3)`

ANSWER :C::D