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K_(f) for water is "1.86 K kg mol"^(-1). If your automobiles radiator holds 1.0 kg of water, how many grams of ethylene glycol (C_(2)H_(6)O_(2)) must you add to get the freezing point of the solution lowered to -2.8^(@)C? |
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Answer» 27 g `therefore""62=(1000xx1.86xxw_(2))/(1000xx2.8)"or"w_(2)=93.3g` |
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