Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Elements with their electronic configuration are given below: Answer the following questions:

Answer»

I
III
II
V

Answer :C
2.

Elements with electronic configuration ns^1 are known as

Answer»

INERT gases
Alkali metals
Transuranic elements
Halogons

Answer :B
3.

Elements which posses the characteristics of metals as well as non-metals are called ……………… .

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SOLUTION :METALLOIDS
4.

Elements used as semiconductor are purified by

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VAN Arkel method
Mond process
Distillation
Zone REFINING

ANSWER :D
5.

Elements of which of the following sets has the strongest tendency to form anions?

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N, O and F
Ga, In and Te
Na, MG and Al
V, CR and Mn

Answer :D
6.

Elements O,S,Se and Te are usually known as:

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Metals
Rare EARTH metals
Coinage metals
Chalcogens

Answer :D
7.

Elements of which of the following group of periodic table do not formhydrides

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GROUP 7,8,9
group 13
GROUPS 15,16,17
group 14

ANSWER :A
8.

Elements of which groups are called d-block elements?

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1 to 2
3 to 12
13 to 18
13 to 17

Answer :B
9.

Elements of which block generally show maximum variation in valency?

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p-block elements
s-block elements
d-block elements
d and s-block elements

Answer :C
10.

Elements of the zero group possess the configuration :

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`ns^2np^1`
`ns^2np^5`
`ns^2np^6`
`ns^2np^6nd^2`

ANSWER :C
11.

Elements of IA group give flame colour due to :

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LOW IP
Low M.P
Softness
One ELECTRON in OUTERMOST shell

Answer :A
12.

Elements of group IVB are:

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STRONGLY electropositive
Strongly electronegative
Weakly electronegative
Neither STRONG nor WEAK electronegative

Answer :D
13.

Elements of group 16 show lower value of first ionization enthalpy compared to group 15, why ?

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SOLUTION :Element of group 15 have STABLE half-filled p-orbitals, hencelarge amount of energy is required to REMOVE ELECTRONS as compared to group 16, which has an incomplete p SUBSHELL.
14.

Elements of group 16 generally show lower value of first ionization enthalpy compared to the corresponding elements of group 15. Why ?

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Solution :This is because of the following two reasons : (i) DUE to extra stability of the exactly half-filled electronic CONFIGURATION of p-orbitals of group 15 elements, they require larger amount of ENERGY to remove an electron as compred to those of group 16 elements.
(ii) After REMOVAL of an electron, the group 16 elements yield SPECIES which have more stable exactly half-filled electronic comfiguration of p-orbitals while this is not so in case of group 15 elements.
15.

Elements of group-16 generally show lower value of first ionisation enthalpy compared to the corresponding periods of group-15. Why ?

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Solution :Due to extra stable half-filled p-orbitals electronic CONFIGURATIONS of Group-15 ELEMENTS, larger AMOUNT of energy is required to REMOVE electrons COMPARED to Group-16 elements.
16.

Group - 16 elements have lower ionisation enthalpy values compared to those group - 15 elements in the corresponding periods. Give reason.

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SOLUTION :This is because of the FOLLOWING two reasons :
(i) DUE to extra stability of the exactly HALF - filled P - orbitals electronic configuration of group - 15 elements, they require larger amount of energy to remove and electron as compared to group - 16 elements.
(ii) After removal of an electron, the group - 16 elements yields SPECIES which have more stable exactly half - filled p - orbitals electronic configuration while this is not so in case of group - 15 elements.
17.

Elements of group-15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is

Answer»

`Bi_(2)O_(5)`
`BiF_(5)`
`BiCl_(5)`
`Bi_(2)S_(5)`

Solution :`F_2` being the STRONGEST oxidisng agent, OXIDISES Bi to its HIGHEST O.S. of +5 in `BiF_5`.
18.

Elements of group 15 showing allotropic forms are:

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<P>N, SB, Bi
N, P, As, Sb
As, Sb. Bi
P, As, Bi

Answer :B
19.

Elements of group 15are:

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s-block elements
p-block elements
d-block elements
None

Answer :B
20.

Elements of group-15 form compounds in (+5) oxidation state. However, bismuth forms only one well characterised compound in (+5) oxidation state. The compound is...........

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`Bi_(2)O_(5)`
`BiF_(5)`
`BiCl_(5)`
`Bi_(2)S_(5)`

SOLUTION :`BiF_5` is formed DUE to high electronegativity of fluorine and small size.
21.

Elements of group -15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is

Answer»

`Bi_(2)O_(5)`
`BiF_(5)`
`BiCl_(5)`
`Bi_(2)S_(5)`

SOLUTION :`F_(2)` being the strongest oxidising AGENT, oxidises Bi to its highest O.S. of +5 in `BiF_(5)`.
22.

Elements of group - 15 compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is

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`Bi_(2)O_(5)`
`BiF_(5)`
`BiCl_(5)`
`Bi_(2)S_(5)`

Solution :Stability of + 5 oxidation STATE decreases top to bottem and +3 oxidation state increases top to bottom due to INERT pair EFFECT. Meanwhile compound having +5 oxidation state of Bi is `BiF_(5)`. It is due to smaller SIZE and high electronegativity of fluorine.
23.

Elements of group - 15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is

Answer»

`Bi_(2)O_(5)`
`BiF_(5)`
`BiCl_(5)`
`Bi_(2)S_(5)`

Answer :B
24.

Elements of group 15 form compounds in +5 oxidatin state. However, bismuth forms only one well characterisedcompound in +5 oxidation state. The compound is

Answer»

`Bi_(2)O_(5)`
`BiF_(3)`
`BiCl_(5)`
`Bi_(2)S_(5)`

SOLUTION :The stability of +5 oxidation state decreases down the group due to inert pair effect. The only well CHARACTERISED Bi(V) COMPOUND is `BiF_(5)` as fluorine being most electronegative element is able to unpair NS ELECTRONS.
25.

Elements of group 13 mainly form covalent compounds because

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Size of IONS is small
Sum of THREE ionisation ENERGIES is very high
Electronegativity values are high
All of these

Answer :D
26.

Elements of group 13 mainly form covalent compounds because _________

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small size
electro NEGATIVITY VALUES are HIGH
ionizatio ENERGY is very high
both (a) and ( c )

Answer :D
27.

Elements of group 10 is called pseudo-inert group. Comment.

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Solution :Presence of 18 ELECTRONS in the OUTER most SHELL is called pseudo-octet or pseudo-inert configu-ration. PALLADIUM, a member of GROUP 10 has such configuration.
28.

Elements of group 13 form oxides of the general formula :

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`M_4O_5`
MO
`M_2O_3`
`M_2O_4`

ANSWER :C
29.

Elements of group 1 react violently with water and the solution becomes:

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Acidic
Basic
Neutral
Amphoteric

Answer :B
30.

Elements of d-group are called

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TRANSITION ELEMENTS
Transuranic elements
Metals
Metalloids

Answer :A
31.

Elements in which 4f orbitals are progressively filled are called as

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TRANSITION elements
Lanthanides
ACTINIDES
INERT gases

Answer :B
32.

Elements in the groups 13 to .18 in the periodic table constitute the ‘p’ block elements. Name the most important oxo acid of nitrogen

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SOLUTION :NITRIC ACID `(HNO_3)`
33.

Elements in the groups 13 to .18 in the' periodic table constitute the ‘p’ block elements. In general, noble gases are least reactive. Why?

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SOLUTION :Noble gases have STABLE, octet configuration (except for He). HELIUM ALSO has a very stable electronic configuration .of `1 s^2`.So noble gases are chemically unreactive.
34.

Elements having different nuclear charge but the same mass number are called

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Isotopes
Isobars
Isomers
Isotones

Answer :B
35.

......elements does not possess allotropes.

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N
Bi
P
As

Answer :A
36.

Elements belonging group 16 are called …………….. .

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SOLUTION :CHALGOGENS
37.

Elements A, B, C, D belong to the same group. The basic character of their oxides will be in which order if the atomic number of A, B, C, D are (Z – x) , (Z + 2x + 2), Z and (Z + x) respectively:

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`A LT B lt C lt D`
`A GT B gt C gt D`
`B gt D gt C gt A`
`B gt C gt D gt A`

ANSWER :C
38.

{:("Element","Electronegative value"),(W,2.7),(X,2.1),(Y,0.8),(Z,3.4):} Incorrect statement reagarding given information is:

Answer»

WZ does not CONDUCT electricity in SOLID and FUSED state
YZ CONDUCTS electricity in solid and fused state
XZ conducts electricity only in solution state
WX conducts electricity only in fused state

Answer :D
39.

Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanismby imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constant with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow H_(2)+Br_(2)to2HBr Mechaism : Br_(2)hArr2Br (fast) H_(2)+brtoHBr+H(slow) H+BrtoHBR (Fast) Order of the reaction is

Answer»

0<BR>0.1
1.5
0.2

Solution :`K_(C)=([Br]^(2))/([Br_(2)])implies[B_(r)]=SQRT(K_(c).[Br_(2)]),r=K_(2).[H_(2)][B_(r)],r=K_(2).[H_(2)](K_(C))^(1/2).[Br_(2)]^(1/2),r=K.[H_(2)]^(1)[Br_(2)]^(1/2)`
40.

Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanismby imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constant with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow The milk beacteria growth follows which order of reaction

Answer»

0
1
2
3

Solution :BACTERIAL growth FOLLOWS 1st ORDER KINETICS
41.

Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanismby imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constat with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow Then find the incorrect one

Answer»

ORDER of reaction =1
`r=k[O_(3)]^(2)[O_(2)]^(-1)`
Order with RESPECT to `O_(3)=2`
Order with respect to `O_(2)=1`

Solution :`r=K[O_(3)]^(2)[O_(2)]^(-1)`
42.

Element X is strongly electropositive and element Y is strongly electronegative. Both are univalent. The comound formed would be

Answer»

`X^(-)-Y`
`X-Y^(+)`
`X^(+)Y^(-)`
`X-Y`

ANSWER :C
43.

Elements with the general electronic configuration (n-1)d^(3)ns^(2) belong to which group in the modern periodic table ?

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Solution :In case ofd-blockelements group numberis equal to the sum ofns- and `(n-1)d` electrons. ELEMENTS WITHTHE electronic configuration `(n-1)d^(3)ns^2` belong to group 5 or VB group
44.

Element with the lowest atomicity

Answer»

TE
S
SE
O

ANSWER :D
45.

Element with pseudooctet configuration in its outermost shell

Answer»

Copper
Palladium
God
Platinum

Answer :B
46.

Element with higher catenation capacity is

Answer»

S
SE
TE
PO

ANSWER :A
47.

Element with atomic number 56 belongs to which block?

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<P>s
p
d
F

ANSWER :A
48.

Element with atomic number belongs to the period.........and the group ........

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`4^(TH),12^(th)`
`4^(th),11^(th)`
`5^(th),12^(th)`
`5^(th),11^(th)`

SOLUTION :Electronic configuration : `[KR]4D^(10)5s^(1)`, period `=5^(th)`, group `=10+1=11^(th)`
49.

Element with atomic number 56 belongs to which block ?

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s
p
d
f

Answer :D
50.

Element with atomic number 49 belongs to the period ……..and the group ……….. .

Answer»

`4^(TH), 12^(th)`
`4^(th), 11^(th)`
`5^(th), 12^(th)`
`5^(th), 13^(th)`

Answer :D