This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Elements with their electronic configuration are given below: Answer the following questions: |
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Answer» I |
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| 2. |
Elements with electronic configuration ns^1 are known as |
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Answer» INERT gases |
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| 3. |
Elements which posses the characteristics of metals as well as non-metals are called ……………… . |
| Answer» SOLUTION :METALLOIDS | |
| 4. |
Elements used as semiconductor are purified by |
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Answer» VAN Arkel method |
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| 5. |
Elements of which of the following sets has the strongest tendency to form anions? |
| Answer» Answer :D | |
| 6. |
Elements O,S,Se and Te are usually known as: |
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Answer» Metals |
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| 7. |
Elements of which of the following group of periodic table do not formhydrides |
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Answer» GROUP 7,8,9 |
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| 8. |
Elements of which groups are called d-block elements? |
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Answer» 1 to 2 |
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| 9. |
Elements of which block generally show maximum variation in valency? |
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Answer» p-block elements |
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| 10. |
Elements of the zero group possess the configuration : |
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Answer» `ns^2np^1` |
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| 11. |
Elements of IA group give flame colour due to : |
| Answer» Answer :A | |
| 12. |
Elements of group IVB are: |
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Answer» STRONGLY electropositive |
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| 13. |
Elements of group 16 show lower value of first ionization enthalpy compared to group 15, why ? |
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Answer» |
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| 14. |
Elements of group 16 generally show lower value of first ionization enthalpy compared to the corresponding elements of group 15. Why ? |
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Answer» Solution :This is because of the following two reasons : (i) DUE to extra stability of the exactly half-filled electronic CONFIGURATION of p-orbitals of group 15 elements, they require larger amount of ENERGY to remove an electron as compred to those of group 16 elements. (ii) After REMOVAL of an electron, the group 16 elements yield SPECIES which have more stable exactly half-filled electronic comfiguration of p-orbitals while this is not so in case of group 15 elements. |
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| 15. |
Elements of group-16 generally show lower value of first ionisation enthalpy compared to the corresponding periods of group-15. Why ? |
| Answer» Solution :Due to extra stable half-filled p-orbitals electronic CONFIGURATIONS of Group-15 ELEMENTS, larger AMOUNT of energy is required to REMOVE electrons COMPARED to Group-16 elements. | |
| 16. |
Group - 16 elements have lower ionisation enthalpy values compared to those group - 15 elements in the corresponding periods. Give reason. |
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Answer» SOLUTION :This is because of the FOLLOWING two reasons : (i) DUE to extra stability of the exactly HALF - filled P - orbitals electronic configuration of group - 15 elements, they require larger amount of energy to remove and electron as compared to group - 16 elements. (ii) After removal of an electron, the group - 16 elements yields SPECIES which have more stable exactly half - filled p - orbitals electronic configuration while this is not so in case of group - 15 elements. |
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| 17. |
Elements of group-15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is |
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Answer» `Bi_(2)O_(5)` |
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| 18. |
Elements of group 15 showing allotropic forms are: |
| Answer» Answer :B | |
| 19. |
Elements of group 15are: |
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Answer» s-block elements |
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| 20. |
Elements of group-15 form compounds in (+5) oxidation state. However, bismuth forms only one well characterised compound in (+5) oxidation state. The compound is........... |
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Answer» `Bi_(2)O_(5)` |
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| 21. |
Elements of group -15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is |
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Answer» `Bi_(2)O_(5)` |
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| 22. |
Elements of group - 15 compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is |
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Answer» `Bi_(2)O_(5)` |
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| 23. |
Elements of group - 15 form compounds in +5 oxidation state. However, bismuth forms only one well characterised compound in +5 oxidation state. The compound is |
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Answer» `Bi_(2)O_(5)` |
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| 24. |
Elements of group 15 form compounds in +5 oxidatin state. However, bismuth forms only one well characterisedcompound in +5 oxidation state. The compound is |
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Answer» `Bi_(2)O_(5)` |
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| 25. |
Elements of group 13 mainly form covalent compounds because |
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Answer» Size of IONS is small |
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| 26. |
Elements of group 13 mainly form covalent compounds because _________ |
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Answer» small size |
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| 27. |
Elements of group 10 is called pseudo-inert group. Comment. |
| Answer» Solution :Presence of 18 ELECTRONS in the OUTER most SHELL is called pseudo-octet or pseudo-inert configu-ration. PALLADIUM, a member of GROUP 10 has such configuration. | |
| 28. |
Elements of group 13 form oxides of the general formula : |
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Answer» `M_4O_5` |
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| 29. |
Elements of group 1 react violently with water and the solution becomes: |
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Answer» Acidic |
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| 30. |
Elements of d-group are called |
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Answer» TRANSITION ELEMENTS |
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| 31. |
Elements in which 4f orbitals are progressively filled are called as |
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Answer» TRANSITION elements |
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| 32. |
Elements in the groups 13 to .18 in the periodic table constitute the ‘p’ block elements. Name the most important oxo acid of nitrogen |
| Answer» SOLUTION :NITRIC ACID `(HNO_3)` | |
| 33. |
Elements in the groups 13 to .18 in the' periodic table constitute the ‘p’ block elements. In general, noble gases are least reactive. Why? |
| Answer» SOLUTION :Noble gases have STABLE, octet configuration (except for He). HELIUM ALSO has a very stable electronic configuration .of `1 s^2`.So noble gases are chemically unreactive. | |
| 34. |
Elements having different nuclear charge but the same mass number are called |
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Answer» Isotopes |
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| 35. |
......elements does not possess allotropes. |
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Answer» N |
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| 36. |
Elements belonging group 16 are called …………….. . |
| Answer» SOLUTION :CHALGOGENS | |
| 37. |
Elements A, B, C, D belong to the same group. The basic character of their oxides will be in which order if the atomic number of A, B, C, D are (Z – x) , (Z + 2x + 2), Z and (Z + x) respectively: |
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Answer» `A LT B lt C lt D` |
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| 38. |
{:("Element","Electronegative value"),(W,2.7),(X,2.1),(Y,0.8),(Z,3.4):} Incorrect statement reagarding given information is: |
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Answer» WZ does not CONDUCT electricity in SOLID and FUSED state |
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| 39. |
Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanismby imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constant with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow H_(2)+Br_(2)to2HBr Mechaism : Br_(2)hArr2Br (fast) H_(2)+brtoHBr+H(slow) H+BrtoHBR (Fast) Order of the reaction is |
| Answer» Solution :`K_(C)=([Br]^(2))/([Br_(2)])implies[B_(r)]=SQRT(K_(c).[Br_(2)]),r=K_(2).[H_(2)][B_(r)],r=K_(2).[H_(2)](K_(C))^(1/2).[Br_(2)]^(1/2),r=K.[H_(2)]^(1)[Br_(2)]^(1/2)` | |
| 40. |
Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanismby imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constant with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow The milk beacteria growth follows which order of reaction |
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Answer» 0 |
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| 41. |
Elementary unimolecular reaction have first order rate laws, elementary bimolecular reaction have second order rate laws. A rate law is often derived from a proposed mechanismby imposiing the steady state approximation by assuming that there in pre equilibrium A proposal mechanism must be constat with the experimental rate law. The decomposition of O_(3) obeys the mechanism given below, Step 1: O_(3)hArrO_(2)+(O)- fast Step 2: O_(3)+(O)toO_(2)+O_(2)- slow Then find the incorrect one |
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Answer» ORDER of reaction =1 |
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| 42. |
Element X is strongly electropositive and element Y is strongly electronegative. Both are univalent. The comound formed would be |
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Answer» `X^(-)-Y` |
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| 43. |
Elements with the general electronic configuration (n-1)d^(3)ns^(2) belong to which group in the modern periodic table ? |
| Answer» Solution :In case ofd-blockelements group numberis equal to the sum ofns- and `(n-1)d` electrons. ELEMENTS WITHTHE electronic configuration `(n-1)d^(3)ns^2` belong to group 5 or VB group | |
| 45. |
Element with pseudooctet configuration in its outermost shell |
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Answer» Copper |
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| 48. |
Element with atomic number belongs to the period.........and the group ........ |
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Answer» `4^(TH),12^(th)` |
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| 49. |
Element with atomic number 56 belongs to which block ? |
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Answer» s |
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