Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Do you know produce certain amines? What are they called and what is the fucntion of these amines?

Answer»

Solution :Plants produce MANY biologically active AINES called alkaloids. Plants synthesize alkaloids to protect them from being EATEN by insect and other ANIMALS.
Discussion
2.

Draw the structures of [Co(NH_(3))_(6)]^(3+), [Ni(CN)_(4)]^(2-) and [Ni(CO)_(4)]. Write shapes of the complexes and hybridisation of atomic orbitals of the transition metal in each case.

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SOLUTION :
Discussion
3.

Draw the structures of [Co(NH_(3))_(6)]^(3+) [Ni(CN)_(4)]^(2-) and [Ni(CO)_(4)] Write the hybridization of atomic orbitals of the transition metal in each case.

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SOLUTION :Hybridization of `Co^(+3)` is `DSP^(2)` shape is octahedral

Discussion
4.

Draw the structures of all the eight structural isomers that have the molecular formula C_(5)H_(11)Br. Name each isomer according to IUPAC system and classify them as primary, secondary or tertiary bromides.

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Solution :

The structural ISOMERS can be both CHAIN as well as POSITION isomers.
Discussion
5.

Do you agree with the statement that in hep and ccp structures, there is no difference in the arrangement of atoms? Explain.

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SOLUTION :The statement is not CORRECT.
`{:("HCP" ,"CCP"),("AB AB AB......","ABC ABC ABC......"):}`
Discussion
6.

Draw the structures of all the eight structural isomers that have the molecular formula C_(5)H_(11)Br . Name each isomer according to IUPAC system and classify them as primary, secondary and tertiary bromide.

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SOLUTION :EIGHT isomers having molecular formula are LISTED below. Their IUPAC names are given against them.
`1^(@) ` for primary
`2^(@) ` for secondary
`3^(@) ` for tertiary
`CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)Br"1-Bromopentane " (1^(@))`
`CH_(3)CH_(2)CH_(2)CH(Br) CH_(3) "2-Bromopentane " (2^(@))`
`CH_(3)CH_(2)CH(Br)CH_(2)CH_(3) "3-Bromopentane " (2^(@))`
`(CH_(3))_(2)CHCH_(2)CH_(2)Br "1-Bromo -3-methylbutane " (1^(@))`
`(CH_(3))_(2)CHCHBrCH_(3) "2-Bromo-3-methylbutane " (2^(@))`
`(CH_(3))_(2)CBrCH_(2)CH_(3) "2-Bromo -2-methylbutane " (3^(@))`
`CH_(3)CH_(2)CH(CH_(3))CH_(2)Br "1-Bromo -2- methylbutane " (1^(@))`
`(CH_(3))_(3)C CH_(2)Br "1-Bromo -2, 2-dimethylpropane " (1^(@))`
Discussion
7.

Draw the structures of all the eight structural isomers that have the molecular formula C_(5)H_(11)Br. Name each isomer according to IUPAC system and classify them as primary, secondary or tertiary bromide.

Answer»

Solution :The POSSIBLE structural ISOMERS of `C_(5)H_(11)Br` and their respective IUPAC names are as follows :
Discussion
8.

Do we call metal carbonyls as organometallics ? Why or why not ?

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SOLUTION :YES, metal carbonyls are CALLED organometallics because C ATOM of CO is linked to the metal atom. In fact, the metal-carbon bonds have both `sigma` and `pi` character.
Discussion
9.

Dotransitionelements formcomplexco-ordinatecompounds ?

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Solution :(i)Transitionelementhave atendencyto formcoordinationcompoundswitha speciesthat has anabilityto donatean electronpair toforma CO- ordinatecovalentbond.
(ii)Transitionmetallonsare smallhighlychargedadn theyhavevacantlow energyorbitalstoacceptan electronpairdonatedby othergroups. Due totheseproperties transitionmetalsformlargenumber of complexes.
(iii)Examples `[FE (CN)_(6)]^(4-) , [ Co (NH_(3))_(6)] ^(3+) . etc`
Discussion
10.

Do the vital functions of the body such as digeston get affected during fever ? Explain your answer.

Answer»

Solution :YES VITAL FUNCTIONS of the body are affected during fever. This is because biological reactions taking place in our body are CATALYSED by enzymes. These enzymes show maximum activity in the temperature range `298-310K.` During fever, when temperature rise above 310 K, enzymatic activity becomes less.
Discussion
11.

Do the vital functions of the body such as digestion get affected during fever ? Explain your answer.

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Solution :VITAL functions of the BODY such as digestion are CARRIED by the enzymes and the enzymatic ACTIVITY takes PLACE in the temperature range of 298 310 K. Under the conditions of fever, the body temperature is outside this range, therefore, the vital functions get affected.
Discussion
12.

Do the non - metallic character exhibited by the halogens have any relation to ionization enthalpy?

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SOLUTION :HIGHER is the ionization enthalpy higher the NON - METALLIC CHARACTER .
Discussion
13.

Do the following conversions in not more than two steps. (i) Benzoic acid to Benzalolehyde (ii) Propanone to propene.

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SOLUTION :(i) `C_(6)COOHoverset(SOCI_2)to C_(6)COCIoverset("POL"-BaSO_4)underset(H_2)to C_(6)H_(5)CHO`.
(ii) `CH_(3)COCH_(3)overset(NaBH_4)toCH_(3)underset(OH)underset(|)CHCH_(3)overset("Conc.H_2SO_4)toCH_(3)CH=CH_(2)`.
Discussion
14.

Do the following conversions: (i) Methyl bromide to acetone. (ii) Benzyl chloride to 2-phenylacetic acid.

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Solution :(i) Methyl bromide to acetone:
`CH_(3)Br +Mg underset("ether")overset("Dry")(to)CH_(3)MgBr+CH_(3)CHOoverset(H_(3)O^(+))(to)CH_(3)-underset(CH_(3))underset(|)(CH)-Ohunderset(573K)overset(Cu)(to)CH_(3)COCH_(3)`
(II) Benzyl chloride to 2-pheyl ACETIC acid:
`C_(6)H_(5)CH_(2)Cl+KCNtoC_(6)H_(5)CH_(2)CNoverset(H_(3)O^(+))(to)C_(6)H_(5)CH_(2)COOH`
Discussion
15.

Do the following conversions in not more than two steps: a. Propene to Acetone b. Propanoic acid to 2-hydroxypropanoic acid.

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SOLUTION :Propene to Acetone: <BR> `underset("Propene")(CH_(3)CH)=CH_(2)underset(H^(+))overset(H_(2)O)(to)CH_(3)-overset(OH)overset(+)(CH)-CH_(3)underset(CrO_(3))overset([O])(to)CH_(3)-underset("Acetone")overset(O)overset(||)(C)-CH_(3)`
b. Propanoic ACID to 2-hyroxypropanoic acid:
`underset("Propanoic acid")(CH_(3)CH_(2)COOH)overset(Br_(2)//"Red"P)(to)overset(Br)overset(|)(CH_(3)COOH)overset(Aq.KOH)(to)underset(3-"HYDROXY propanoic acid")(CH_(3)-overset(OH)overset(|)(CH)-COOH)`
Discussion
16.

Do the following conversions : (i) Toluene to benzyl alcohol (ii) Ethanol to but - 2 - yne (iii) Ethanol to propane nitrile (iv) Propane to propan-1-ol (v) Ethyl chloride to propanoic acid.

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Solution :(i)
(ii) `underset("Ethanol")(C_(2)H_(5)-OH) OVERSET(P//I_(2), triangle)to C_(2)H_(5)I underset(Delta)overset(KOH(alc))to CH_(2)=CH_(2) overset(Br_(2), CCl_4)to underset(Br)underset(|)(CH_(2))-underset(Br)underset(CH_(2))`
(iii) `underset("Ethanol")(C_(2)H_(5)-OH) overset(P//I_(2), triangle)to C_(2)H_(5)-I underset(H_(2)O)overset(KCN, OH^(-))to underset("Propane nitrile")(C_(2)H_(5)-CN)`
(IV) `underset("Propane")(CH_(3)CH=CH_(2)) overset("HBr/Perioxide")to CH_(3)CH_(2) CH_(2) Br overset("Aq KOH")to underset("Propan-1-ol")(CH_(3)CH_(2)CH_(2)OH)`
(v) `underset("Ethyl CHLORIDE") (C_(2)H_(5)-Cl) overset(KCN, E_(1)OH, H_(2)O)to C_(2)H_(5)-CN overset(H^(+), H_(2)O)to underset("Propanoic acid") (CH_(3)CH_(2)OOH)`
Discussion
17.

Do the following conversions : (i) Methyl bromide to acetone (ii) Benzyl chloride to 2-phenylacetic acid.

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Solution :(i) `CH_(3) Br + Mg overset "Dry Ether"rightarrow CH_(3)MGBR`
(ii) `C_(6)H_(5) CH_(2)CI + KCN overset"-KCI"C_(6)H_(5)CH_(2)CH`
`C_(6)H_(5)CH_(2)CH + 2H_(2)O overset"H^(+)`"rightarrow underset("2-phenylacetic ACID")(C_(6)H_(5)CH_(2)CHOO+NH_(4)^(+))`
Discussion
18.

Do the following conversion is not more than two steps (i) Benzoic acid to benzaldehyde (ii) Ethylbenzene to benzoic acid.

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SOLUTION :N//A
Discussion
19.

Do classification of polymers based on source.

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Solution :There are three sub categories based on source classification.
(a) Natural polymers : These polymers are found in plants and ANIMALS. EXAMPLES are proteins, CELLULOSE, starch, some resins and rubber.
(b) Semi-synthetic polymers : Cellulose derivatives as cellulose acetate (rayon) and cellulose nitrate, etc. are the usual examples of this sub category.
(c) Synthetic polymers : A variety of synthetic polymers as plastic (polythene), synthetic fibres (nylon-6,6) and synthetic rubbers (Buna-S) are examples of man-made polymers extensively USED in daily LIFE as well as in industry.
Discussion
20.

DNA undergoes .................but ....................usually does not.

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SOLUTION :REPLICATION , RNA
Discussion
21.

DNA multiplication is called ……… .

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TRANSCRIPTION
TRANSFORMATION
TRANSDUCTION
replication

Answer :D
Discussion
22.

DNA molecule consists of units of:

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Base-sugar
Base-sugar-phosphate
Base-phosphate
None of these

Answer :B
Discussion
23.

DNA has deoxyribose and base and third compound is :

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PHOSPHATE group
Ribose
Adenine
Thymine

Answer :A
Discussion
24.

DNA finger printing is useful for A) Identifying the criminals B) Determining the paternity of individual C) Identifying the dead bodies

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A,B
A,C
B,C
A,B,C

Answer :D
Discussion
25.

DNA dictates synthesis of :

Answer»

PROTEINS
Lipids
Carbohydrates
Glucose

Answer :A
Discussion
26.

DNA contains the sugar

Answer»

Deoxyribose
Ribose
D- fructose
D- glucose

Answer :A
Discussion
27.

DNA and RNA contain four bases each. Which of the following bases is not present in RNA ?

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Adeine
Uracil
THYMINE
Cytosine

Solution :Thymine is not PRESENT in RNA.
Discussion
28.

DNA consist of

Answer»

`BETA` D-RIBOSE SUGAR
`beta`-D 2-deoxyribose sugar
`ALPHA`-D ribose sugar
`alpha`-D-deoxyribose sugar

Answer :B
Discussion
29.

DNA and RNA contain four bases each. Which of the following bases is not present in RNA?

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ADENINE
Uracil
Thymine
CYTOSINE

ANSWER :C
Discussion
30.

DNA and RNA contain four bases each. Which of the following bases in not present in RNA ?

Answer»

Adenine
Uracil
THYMINE
Cytosine

Solution :Thymine
Thymine is PRESENT in DNA
Discussion
31.

DNA and RNA contain four bases each. Which of the following bases in not present in RNA?

Answer»

Adenine
Uracil
Thymine
Cytosine

Solution :Thymine is not present in RNA. RNA contains uracil in PLACE of thymine.
Discussion
32.

DNA and RNA are chiral molecules due to the presence of

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CHIRAL bases
Phosphate ESTER unit
D-sugar component
L-sugar component

Answer :C
Discussion
33.

DMG gives a rosy red crystalline ppt with

Answer»

`ZN^(2+)`
`NI^(2+)`
`CU^(2+)`
`MN^(2+)`

Answer :B
Discussion
34.

DMG is x-valen and y-dentate ligand. Taking x and y as numbers, find (x+y)

Answer»


SOLUTION :UNIVALENT BIDENTATE LIGAND .
Discussion
35.

dm^(3) of water contains 90 g of glucose. The mole fraction of glucose in the solution is

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0.33
0.66
0.5/56.05
0.5/55.55

Solution :`"Moles of WATER"="MASS"/"MOLAR mass"=1000/18=55.56`
Moles of GLUCOSE `="Mass"/"Molar mass"=90/180=0.5`
Mole fraction of glucose `= 0.5/(0.5 + 55.56)=0.5/56.06`
Discussion
36.

Divalent Manganese is more stable due to

Answer»

`3D^(4)` CONFIGURATION
`3d^2` configuration
`3d^(5)` configuration
`3d^(3)` configuration

Solution :`3d^(5)` configuration
Discussion
37.

Orthophosphoric acid has the formula:

Answer»

`H_2S_2O_6`
`H_2SO_5`
`H_2S_2O_8`
`H_2S_2O_5`

ANSWER :A
Discussion
38.

Disymmetrical object is one which image

Answer»

Superimposable on its MIRROR IMAGE
NON-superimposable on its mirror image
OPTICALLY INACTIVE
Achiral

Solution :Non superimposable on its mirror image.
Discussion
39.

Disulphuric acid is

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`H_(2)S_(2)O_(6)`
`H_(2)S_(2)O_(7)`
`H_(2)S_(2)O_(8)`
`H_(2)S_(2)O_(5)`

ANSWER :B
Discussion
40.

Distribution of molecules with velocity is represented by the curve. Point A in the curve shifts to the higher value of velocity if

Answer»

T is increased
V is increased
P is increased
All of the above

Answer :D
Discussion
41.

Distingusih between 1^(@), 2^(@), and 3^(@) amines by HNO_(2) acid test.

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Solution :`1^(@)` gives `N_(2)` GAS. `2^(@)` gives yellow oily compound. `3^(@)`FORM water soluble SALTS.
`CH_(3)CH_(2)NH_(2) + HNO_(2) rightarrow C_(2)H_(5)OH + N_(2)+ H_(2)O`
`R_(2)NH+ HNO_(2) rightarrow R_(2)N-N=O+H_(2)O`
`(CH_(3)CH_(2))_(3)N+HNO_(2) rightarrow [(CH_(3)CH_(2))_(3) NH]NO_(2)^(-)` soluble in water.
Discussion
42.

What is difference between calcination and roasting ?

Answer»

Solution :Calcination : Calcination is a process of heating the concentrated ore below its melting POINT with limited supply of AIR , or in the absence of air.
ROASTING : the concentrated ore is oxidised with limited OXYGEN . HOWEVER the sulphide ore is oxidised with excess oxygen by roasting process.
Discussion
43.

Distinguishing reagent between silver and lead salt is

Answer»

`H_(2)S` gas
HOT dilute HCL solution
`NH_(4)Cl("SOLID")+NH_(4)OH` solution
`NH_(4)Cl("solid")+(NH_(4))_(2)CO_(3)` solution

Solution :Both Pb and AG form white ppt. of their chlorides. But `PbCl_(2)` is soluble in hot water while `AgCl` does not dissolve in hot water.
Discussion
44.

Distinguishing reagent between silver and lead salts is

Answer»

`H_(2)S` gas
Dil. HCl solution
`NH_(4)Cl"("Solid") +NH_(4)OH` solution
`NH_(4)Cl("solid")+(NH_4)_(2)CO_(3)` solution

Solution :Both Pb and HG FORM white PPT. of their chlorides, but `PbCl_(2)` is solouble in hot water while `Hg_(2)Cl_(2)` does not dissolve in hot water.
Discussion
45.

Distinguish tetrahedral and octahedral voids.

Answer»

SOLUTION :
Discussion
46.

Distinguish glucose from fructose.

Answer»

SOLUTION :
Discussion
47.

Distinguish clearly between the meanings of E_(cell)=0 and E_(cell)^@=0

Answer»

Solution :`E_(cell)=0` means that the CONCENTRATION RATIO is the Nernst equation for the cell REDUCES the `E_(cell)^@` value to zero while `E_(cell)^@=0` INDICATES a concentration cell.
Discussion
48.

Distinguish between1- Propanol and 2-Methyl-2-Methyl-2-propanol by suitable chemical test.

Answer»


Solution :Lucas reagent: Cloudiness APPEARS immidiately with `2`-methyl-`2`-propanol `(3^(@) "alcohol")` while `1`- propanol `(1^(@) "alcohol")` will not REACT with Lucss reagent appreciably at ROOM temp.
Discussion
49.

Distinguish chemically between the following: i. (a) Cyclohexane, (b) Cyclohexane, (c) Benzene ii. (a) Benzene, (b ) Naphthalene iii. (a) Anthrance and (b ) Phenanthrene.

Answer»

Solution :i. Add `Br_(2)//CCl_(4)` to each of the three LIQUIDS. <BR>
Discussion
50.

Distinguish between thermosetting and thermoplastic polymers with examples.

Answer»

Solution :THERMOSETTING POLYMERS of not BECOME soft on heating. Example: Bakelite
THERMOPLASTIC polymers are those plastics which become soft heating and can be remouled agin and again. Example: POLYTHENE
Discussion