This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
ntif all the ions present at one of the rectangular planes are removed from a nacl structure. Predict its new formulan |
| Answer» ntif all the ions present at one of the rectangular planes are removed from a nacl structure. Predict its new formulan | |
| 2. |
In the reaction CH3−CH3|CH−CH2O−CH2−CH3+heatedHI→.......... Which of the following compounds will be formed? |
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Answer» In the reaction CH3−CH3|CH−CH2O−CH2−CH3+heatedHI→.......... Which of the following compounds will be formed? |
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| 3. |
Aqueous solution of Na2S2O3 on reaction with Cl2 gives |
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Answer» Aqueous solution of Na2S2O3 on reaction with Cl2 gives |
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| 4. |
15. The correct order of lattice energy of the following ionic compounds is 1 NaCl>MgCl2>CaO>Al2O3 2NaCl>CaO>MgCl2>Al2O3 3 Al2O3>CaO>MgCl2>NaCl 4Al2O3>MgCl2>CaO>NaCl |
| Answer» 15. The correct order of lattice energy of the following ionic compounds is 1 NaCl>MgCl2>CaO>Al2O3 2NaCl>CaO>MgCl2>Al2O3 3 Al2O3>CaO>MgCl2>NaCl 4Al2O3>MgCl2>CaO>NaCl | |
| 5. |
30. Silver has a density of g/cm^3 the number of silver atoms on a surface of area 10^{-22} meter^2 can be expressed in scientific notation |
| Answer» 30. Silver has a density of g/cm^3 the number of silver atoms on a surface of area 10^{-22} meter^2 can be expressed in scientific notation | |
| 6. |
Question 29.Show the dilute aqueous solution of hydrochloric acid (a) H3O++Cl−(b) H3O++OH−(c) Cl−+OH−(d) unionised HCl |
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Answer» Question 29. Show the dilute aqueous solution of hydrochloric acid (a) H3O++Cl− (b) H3O++OH− (c) Cl−+OH− (d) unionised HCl |
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| 7. |
Turnbull’s blue is |
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Answer» Turnbull’s blue is |
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| 8. |
Justify the electronic configurations of d-block and f-block elements.*for d-block explain why the s orbital has a possibility of having 0 electrons in case of ns0-2 and (n-1)d1-10 as according to Aufbau principal/n+l rule, the lower subshells are filled first**Same for the f-block elements, why can d subshell have 0-1 electrons as in (n-2)f1-14 (n-1)d1-10 ns0-2, and also clarify the same concept of s orbital having a chance of having 0 electrons at the minimum* |
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Answer» Justify the electronic configurations of d-block and f-block elements. *for d-block explain why the s orbital has a possibility of having 0 electrons in case of ns0-2 and (n-1)d1-10 as according to Aufbau principal/n+l rule, the lower subshells are filled first* *Same for the f-block elements, why can d subshell have 0-1 electrons as in (n-2)f1-14 (n-1)d1-10 ns0-2, and also clarify the same concept of s orbital having a chance of having 0 electrons at the minimum* |
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| 9. |
When H2O2 is oxidised by a suitable oxidant, the product is |
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Answer» When H2O2 is oxidised by a suitable oxidant, the product is |
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| 10. |
The equilibrium constant for the reaction,N2+2O2⇌2NO2 is 100. The equilibrium constant for the reactions:(a) 2NO2⇌N2+2O2 is K1(b) NO2⇌12N2+O2 is K2Find the value of K1×K2. |
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Answer» The equilibrium constant for the reaction, |
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| 11. |
How do Pd, Pt and Ni provide hydrogen to the reaction? Where do they get the hydrogens from? |
| Answer» How do Pd, Pt and Ni provide hydrogen to the reaction? Where do they get the hydrogens from? | |
| 12. |
The process that yields 99.99% pure aluminium is: |
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Answer» The process that yields 99.99% pure aluminium is: |
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| 13. |
The hybrid states of C in diamond and graphite are respectively: |
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Answer» The hybrid states of C in diamond and graphite are respectively: |
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| 14. |
Na2C2HCl−−→ (excess) NaNH2−−−−−−−−−−→(excess) CH3I H2−−−−−−−→Pd−BaSO4 i. O3−−−−−−−→ii. Zn−H2O Final product can be obtained by: |
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Answer» Na2C2HCl−−→ (excess) NaNH2−−−−−−−−−−→(excess) CH3I H2−−−−−−−→Pd−BaSO4 i. O3−−−−−−−→ii. Zn−H2O Final product can be obtained by: |
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| 15. |
Ethylene reacts with Br2 to give 1,2−dibromoethane. The anti addition takes place due to the formation of which intermediate? |
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Answer» Ethylene reacts with Br2 to give 1,2−dibromoethane. The anti addition takes place due to the formation of which intermediate? |
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| 16. |
The IUPAC name of ethylidene chloride is: |
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Answer» The IUPAC name of ethylidene chloride is: |
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| 17. |
11.Products formed when unsaturated hydrocarbon reacts in the presence of Li liq NH3 |
| Answer» 11.Products formed when unsaturated hydrocarbon reacts in the presence of Li liq NH3 | |
| 18. |
The oxidation state of Fe in FeSO4.(NH4)2SO4.6H2O is |
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Answer» The oxidation state of Fe in FeSO4.(NH4)2SO4.6H2O is |
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| 19. |
what is erect image ? |
| Answer» what is erect image ? | |
| 20. |
For a gas sample with N∘ number of molecules, function N(V) is given by :N(V)=dNdV=(3N∘V3∘)V2 for 0<V<V∘and N(V)=0 for V>V∘where dN is the number of molecules in the speed range V to V+dV. If the rms speed of the molecules is √nV0.Then the value of n is |
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Answer» For a gas sample with N∘ number of molecules, function N(V) is given by : N(V)=dNdV=(3N∘V3∘)V2 for 0<V<V∘and N(V)=0 for V>V∘where dN is the number of molecules in the speed range V to V+dV. If the rms speed of the molecules is √nV0.Then the value of n is |
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| 21. |
The correct order of lattice energy order is: |
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Answer» The correct order of lattice energy order is: |
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| 22. |
Among the following species, which has the maximum hydration energy? |
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Answer» Among the following species, which has the maximum hydration energy? |
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| 23. |
What will be the product of these Bayer-Villiger Oxidations ? 1) CH3-CO-CO-CH3 2) Ph-CH2-CO-CH3 |
| Answer» What will be the product of these Bayer-Villiger Oxidations ? 1) CH3-CO-CO-CH3 2) Ph-CH2-CO-CH3 | |
| 24. |
12. total numbers of electrons present in D2o |
| Answer» 12. total numbers of electrons present in D2o | |
| 25. |
Give the structures of A, B and C in the following reactions : (i) C6H5NO2Sn+HCl−−−−−→A NaNO2+HCl−−−−−−−−→273K BH2O−−→C (ii) CH3CNH2O/H+−−−−−→ ANH3−−−→Δ BBr2+KOH−−−−−−−→C |
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Answer» Give the structures of A, B and C in the following reactions : (i) C6H5NO2Sn+HCl−−−−−→A NaNO2+HCl−−−−−−−−→273K BH2O−−→C (ii) CH3CNH2O/H+−−−−−→ ANH3−−−→Δ BBr2+KOH−−−−−−−→C |
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| 26. |
Themajor organic product formed in the following reaction is: |
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Answer» The |
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| 27. |
meaning of " SUPERCONDUCTIVITY AROUND 125 K HAS ALREADY BEEN ACHIEVED AND EFFORTS ARE ON TO IMPROVE " |
| Answer» meaning of " SUPERCONDUCTIVITY AROUND 125 K HAS ALREADY BEEN ACHIEVED AND EFFORTS ARE ON TO IMPROVE " | |
| 28. |
ntConsider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively .The equivalent thermal conductivity of slab is ?n ntExplain in detailn |
| Answer» ntConsider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively .The equivalent thermal conductivity of slab is ?n ntExplain in detailn | |
| 29. |
Product (A) of the reaction is: |
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Answer» Product (A) of the reaction is: |
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| 30. |
Mixture X=0.02 mol of [Co(NH3)5SO4]Br and 0.02 mol of [Co(NH3)5Br]SO4 was prepared in 2 litre of solution.1 litre of mixture X+ excess AgNO3→Y1 litre of mixture X + excess BaCl2→ZNumber of moles of Y and Z are |
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Answer» Mixture X=0.02 mol of [Co(NH3)5SO4]Br and 0.02 mol of [Co(NH3)5Br]SO4 was prepared in 2 litre of solution. |
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| 31. |
Why should magnesium ribbon be cleaned before burning? |
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Answer» Why should magnesium ribbon be cleaned before burning? |
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| 32. |
In order to decrease the density of a gas which of the following changes must be done |
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Answer» In order to decrease the density of a gas which of the following changes must be done |
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| 33. |
33. Calculate the difference in the work done when one mole of Al4C3(s) reacts with water in a closed vessel at 27° C against atmospheric pressure and that in an open vessel under the same condition. [Al4C3 + H2O CH4 + Al(OH)3] |
| Answer» 33. Calculate the difference in the work done when one mole of Al4C3(s) reacts with water in a closed vessel at 27° C against atmospheric pressure and that in an open vessel under the same condition. [Al4C3 + H2O CH4 + Al(OH)3] | |
| 34. |
What is chain isomerism? |
| Answer» What is chain isomerism? | |
| 35. |
What sorts ofinformations can you draw from the following reaction ? |
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Answer» What sorts of
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| 36. |
How many sigma and pi bonds will form when one s-orbital undergo head-on overlapping with one p-orbital? |
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Answer» How many sigma and pi bonds will form when one s-orbital undergo head-on overlapping with one p-orbital? |
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| 37. |
Role of depressants in froth floatation method |
| Answer» Role of depressants in froth floatation method | |
| 38. |
Howmuch electricity is required in coulomb for the oxidation of(i) 1 mol of H2Oto O2.(ii) 1 mol of FeO to Fe2O3. |
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Answer» How (i) (ii) |
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| 39. |
For a molecule of benzene, n=2.76×1019 cm−3 and mean free path λ=2.2×10−10 m. Calculate diameter of benzene molecule. |
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Answer» For a molecule of benzene, n=2.76×1019 cm−3 and mean free path λ=2.2×10−10 m. Calculate diameter of benzene molecule. |
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| 40. |
29. How many gm of NaOH is needed to completely neutralise 25.2 g HNO2 ? a. 22.4 g b. 26.4 g c. 44.8 g d. 50.4 g |
| Answer» 29. How many gm of NaOH is needed to completely neutralise 25.2 g HNO2 ? a. 22.4 g b. 26.4 g c. 44.8 g d. 50.4 g | |
| 41. |
Which of the following leads to carbon -carbon double bond? |
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Answer» Which of the following leads to carbon -carbon double bond?
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| 42. |
24. Why the O-nitrophenol as the major product of the reaction of dil.HNO3 with alcohol in elactrophilic aromatic substitution |
| Answer» 24. Why the O-nitrophenol as the major product of the reaction of dil.HNO3 with alcohol in elactrophilic aromatic substitution | |
| 43. |
Conductivity (unit Siemen's ) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is |
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Answer» Conductivity (unit Siemen's ) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is |
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| 44. |
Which of the following does not decolourise iodine? (1) Na2SO3(2) Na2S2O3(3) NaCl(4)NaOH |
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Answer» Which of the following does not decolourise iodine? (1) Na2SO3 (2) Na2S2O3 (3) NaCl (4)NaOH |
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| 45. |
Two solid spheres are made of copper. The radius of second sphere is 3 times that of the first. The quantities of heat required to raise temperature of each sphere by 2 K are in the ratio of |
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Answer» Two solid spheres are made of copper. The radius of second sphere is 3 times that of the first. The quantities of heat required to raise temperature of each sphere by 2 K are in the ratio of |
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| 46. |
15. Two solutions A and B form ideal solutions. At 300K, the vapour pressure of the solution containing 1 mole of A and 3 mole of B ie 550mmHg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increase by 10mmHg. The vapour pressure of A and B in their pure state (in mmHg) respectively are (1)400,600 (2) 500,500 (3) 200,400 (4) 300,600 |
| Answer» 15. Two solutions A and B form ideal solutions. At 300K, the vapour pressure of the solution containing 1 mole of A and 3 mole of B ie 550mmHg. At the same temperature, if one more mole of B is added to this solution, the vapour pressure of the solution increase by 10mmHg. The vapour pressure of A and B in their pure state (in mmHg) respectively are (1)400,600 (2) 500,500 (3) 200,400 (4) 300,600 | |
| 47. |
50. Isnt double displacement: AgNO3 + NaCl a reversible reaction? |
| Answer» 50. Isnt double displacement: AgNO3 + NaCl a reversible reaction? | |
| 48. |
47.Number of soluble salts among the following are AgCl, PbCl2, NaNO3, Ca(OH)2 |
| Answer» 47.Number of soluble salts among the following are AgCl, PbCl2, NaNO3, Ca(OH)2 | |
| 49. |
Which species contain only π−bond among the following? |
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Answer» Which species contain only π−bond among the following? |
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| 50. |
The equilibrium constant of a given cell reaction at 298 K will be Mg ( s ) + Cu^2 + ( aq ) Mg^2+ ( aq ) + Cu ( s ) ( Given : E = 2.7 V ) (a)10^72.1 (b) 10^82.5 (c) 10^55.6 (d) 10^91.5 |
| Answer» The equilibrium constant of a given cell reaction at 298 K will be Mg ( s ) + Cu^2 + ( aq ) Mg^2+ ( aq ) + Cu ( s ) ( Given : E = 2.7 V ) (a)10^72.1 (b) 10^82.5 (c) 10^55.6 (d) 10^91.5 | |