Na2C2HCl−−→ (excess) NaNH2−−−−−−−−−−→(exce – InterviewSolution

1.	Na2C2HCl−−→ (excess) NaNH2−−−−−−−−−−→(excess) CH3I H2−−−−−−−→Pd−BaSO4 i. O3−−−−−−−→ii. Zn−H2O Final product can be obtained by:
Answer» $N a_{2} C_{2} H C l - - \to (excess) N a N H_{2} - --------- \to (excess) C H_{3} I H_{2} - ------ \to P d - B a S O_{4} i . O_{3} - ------ \to i i . Z n - H_{2} O$ Final product can be obtained by:

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