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The equilibrium constant of a given cell reaction at 298 K will be Mg ( s ) + Cu^2 + ( aq ) Mg^2+ ( aq ) + Cu ( s ) ( Given : E = 2.7 V ) (a)10^72.1 (b) 10^82.5 (c) 10^55.6 (d) 10^91.5 |
| Answer» The equilibrium constant of a given cell reaction at 298 K will be Mg ( s ) + Cu^2 + ( aq ) Mg^2+ ( aq ) + Cu ( s ) ( Given : E = 2.7 V ) (a)10^72.1 (b) 10^82.5 (c) 10^55.6 (d) 10^91.5 | |