Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Why does table salt, NaCl sometimes appear yellow in colour?

Answer»

Why does table salt, NaCl sometimes appear yellow in colour?

2.

how mg and F will form the most stable ionic bond

Answer» how mg and F will form the most stable ionic bond
3.

Why alternating current used for measuring resistance of an electrolytic solution?

Answer»

Why alternating current used for measuring resistance of an electrolytic solution?

4.

(a) Give reasons for the following : (i) Mn3+ is a good oxidising agent. (ii) EoM2+/M values are not regular for first row transition metals (3d series). (iii) Although 'F' is more electronegative than 'O', the highest Mn fluoride is MnF4, whereas the highest oxide is Mn2O7. (b) Complete the following equations : (i) 2CrO2−4+2H+⟶ (ii) KMnO4heat−−→

Answer» (a) Give reasons for the following :
(i) Mn3+ is a good oxidising agent.
(ii) EoM2+/M values are not regular for first row transition metals (3d series).
(iii) Although 'F' is more electronegative than 'O', the highest Mn fluoride is MnF4, whereas the highest oxide is Mn2O7.
(b) Complete the following equations :
(i) 2CrO24+2H+
(ii) KMnO4heat
5.

In the case of autocatalysis,

Answer»

In the case of autocatalysis,


6.

The ligand that splits the d orbital to a higher extent are known as

Answer»

The ligand that splits the d orbital to a higher extent are known as


7.

Given that: S∘H2=131 JK−1mol−1S∘Cl2=223 JK−1mol−1and S∘HCl=187 JK−1mol−1 The standard entropy change in formation of 1 mole of HCl(g) from H2(g) and Cl2(g) will be: (Given, reaction for formation of HCl : H2+Cl2→2HCl)

Answer»

Given that:
SH2=131 JK1mol1SCl2=223 JK1mol1and SHCl=187 JK1mol1
The standard entropy change in formation of 1 mole of HCl(g) from H2(g) and Cl2(g) will be:
(Given, reaction for formation of HCl : H2+Cl22HCl)

8.

Which isomer of CrCl3.6H2O is dark green in colour and forms one mole of AgCl with excess of AgNO3 solution -

Answer»

Which isomer of CrCl3.6H2O is dark green in colour and forms one mole of AgCl with excess of AgNO3 solution -

9.

If the dipole moment of CH3F is 1.847 D, the dipole moment of CD3F will be

Answer»

If the dipole moment of CH3F is 1.847 D, the dipole moment of CD3F will be


10.

In an isothermal reversible expansion, if the volume of 96 gm of oxygen at 27∘C is increased from 70 litres to 140 litres, then the work done by the gas will be

Answer»

In an isothermal reversible expansion, if the volume of 96 gm of oxygen at 27C is increased from 70 litres to 140 litres, then the work done by the gas will be


11.

Which of the following forms, with an excess of CN−, a complex having co-ordination number 2

Answer» Which of the following forms, with an excess of CN, a complex having co-ordination number 2
12.

Which of the following gives CH4 on hydrolysis?

Answer»

Which of the following gives CH4 on hydrolysis?


13.

The structure of diborane contains:

Answer»

The structure of diborane contains:


14.

The ΔHf of KF(s) is −563 kJ/mol. The ionisation energy of potassium K(g) is 419 kJ/mol and enthalpy of sublimation of potassium is 88 kJ/mol. The electron affinity of F(g) is −322 kJ/mol and F−F bond enthalpy is 158 kJ/mol. Calculate the absolute value of lattice energy (in kJ/mol) of KF(s)

Answer» The ΔHf of KF(s) is 563 kJ/mol. The ionisation energy of potassium K(g) is 419 kJ/mol and enthalpy of sublimation of potassium is 88 kJ/mol. The electron affinity of F(g) is 322 kJ/mol and FF bond enthalpy is 158 kJ/mol. Calculate the absolute value of lattice energy (in kJ/mol) of KF(s)
15.

Write the names of reagents and equations for the preparation of the following ether by Williamson's synthesis. 1-propoxypropane Ethoxybenzene 2-methoxy-2-methylpropane 1-methoxyethane

Answer»

Write the names of reagents and equations for the preparation of the following ether by Williamson's synthesis.
1-propoxypropane

Ethoxybenzene

2-methoxy-2-methylpropane

1-methoxyethane


    16.

    Acetone is isomeric to:

    Answer»

    Acetone is isomeric to:


    17.

    In the following reaction sequence the amount of D (in g) formed from 10 moles of acetophenone is : (Atomic weight in gmol−1 H=1, C=12, N=14, O=16, Br=80. The yield (%) corresponding to the product in each step is given in the parenthesis)

    Answer» In the following reaction sequence the amount of D (in g) formed from 10 moles of acetophenone is : (Atomic weight in gmol1 H=1, C=12, N=14, O=16, Br=80. The yield (%) corresponding to the product in each step is given in the parenthesis)
    18.

    The total number of hydroxyl groups present in chloroxylenol (x), Terpineol (y) & Bithionol (z) (x+y+z) are:

    Answer» The total number of hydroxyl groups present in chloroxylenol (x), Terpineol (y) & Bithionol (z) (x+y+z) are:
    19.

    Which of the following is in conjugation ?

    Answer»

    Which of the following is in conjugation ?


    20.

    Which of the following compounds is aromatic?

    Answer»

    Which of the following compounds is aromatic?

    21.

    Two spheres - 1,2 with flexible walls are connected by a tube of negligible volume. Their initial and final conditions are given by P1, V1, n1 and P2, V2, n2 respectively. The radius of these spheres depends on the temperature as 4πr2dr=kdT. Initially, sphere 1 was at 100 K and sphere 2 was at 200 K. As the temperature of sphere 1 is increased to 300 K, find the final mole ratio (n′1n′2).

    Answer»
    Two spheres - 1,2 with flexible walls are connected by a tube of negligible volume. Their initial and final conditions are given by P1, V1, n1 and P2, V2, n2 respectively. The radius of these spheres depends on the temperature as 4πr2dr=kdT. Initially, sphere 1 was at 100 K and sphere 2 was at 200 K. As the temperature of sphere 1 is increased to 300 K, find the final mole ratio (n1n2).

    22.

    For a solution of volatile liquids the partial vapour pressure of each component in solution is directly proportional to

    Answer»

    For a solution of volatile liquids the partial vapour pressure of each component in solution is directly proportional to


    23.

    Equilibrium constants are given (in atm) for the following reactions at 0oC SrCl2.6H2O(s)⇌SrCl2.2H2O(s)+4H2O(g), Kp=6.89×10−12 The vapour pressure of water at 0oC is 4.58 torr. Calculate the pressure of water vapour in equilibrium at 0oC

    Answer»

    Equilibrium constants are given (in atm) for the following reactions at 0oC SrCl2.6H2O(s)SrCl2.2H2O(s)+4H2O(g),
    Kp=6.89×1012
    The vapour pressure of water at 0oC is 4.58 torr.
    Calculate the pressure of water vapour in equilibrium at 0oC

    24.

    An oxide which gives H2O2 on treatment with dilute acid is:

    Answer»

    An oxide which gives H2O2 on treatment with dilute acid is:

    25.

    Which statement is true regarding the following structure?

    Answer»

    Which statement is true regarding the following structure?


    26.

    Given: Cu2++e−→Cu+;E∘=0.15VCu++e−→Cu;E∘=0.50VZn2++ze−→Zn;E∘=−0.76V If 9.65 amperes of current is passed, making Cu anode and Zn cathode for 1000 seconds in the cell Zn|Zn2+||Cu2+|Cu containing one litre of 0.55 M zinc (II) ions and one litre of 0.05 M copper (II) ions in the half cells, the E.M.F of cell the after passage of current would be (log 2 = 0.3, log 3 = 0.5, log 5 = 0.7) :

    Answer» Given:
    Cu2++eCu+;E=0.15VCu++eCu;E=0.50VZn2++zeZn;E=0.76V
    If 9.65 amperes of current is passed, making Cu anode and Zn cathode for 1000 seconds in the cell

    Zn|Zn2+||Cu2+|Cu
    containing one litre of 0.55 M zinc (II) ions and one litre of 0.05 M copper (II) ions in the half cells, the E.M.F of cell the after passage of current would be (log 2 = 0.3, log 3 = 0.5, log 5 = 0.7)
    :
    27.

    Question 19 Which of the following statement is not correct from the view point molecular orbital theory? (a) Be2 is not a stable molecule (b) He2 is not stable but He+2 is expected to exist. (c) Bond strength of N_2 is maximum amongst the homonuclear diatomic molecules belonging to the second period. (d) The order of energies of molecular orbitals in N2 molecule is σ2s<σ∗2s<σ2pz<(π∗2px≃π∗2py)<σ∗2pz

    Answer»

    Question 19

    Which of the following statement is not correct from the view point molecular orbital theory?

    (a) Be2 is not a stable molecule

    (b) He2 is not stable but He+2 is expected to exist.

    (c) Bond strength of N_2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.

    (d) The order of energies of molecular orbitals in N2 molecule is

    σ2s<σ2s<σ2pz<(π2pxπ2py)<σ2pz

    28.

    If the threshold wavelength (λ0) for ejection of electron from metal is 330 nm, then work function for the photoelectric emission is: (Planck's constant (h) = 6.6×10−34 J s)

    Answer»

    If the threshold wavelength (λ0) for ejection of electron from metal is 330 nm, then work function for the photoelectric emission is:
    (Planck's constant (h) = 6.6×1034 J s)

    29.

    Calculate the wavelength of the first time in the Balmer series of hydrogen spectrum.

    Answer»

    Calculate the wavelength of the first time in the Balmer series of hydrogen spectrum.


    30.

    If an element with atomic mass=50 crystalizes in FCC lattice, with edge length of unit cell as 0.5nm. What is the density of unit cell if it contains 0.25% Schottky defects (a) 2 g/cc (b)2.66 g/cc (c)3.06 g/cc (d)none of these

    Answer»

    If an element with atomic mass=50 crystalizes in FCC lattice, with edge length of unit cell as 0.5nm. What is the density of unit cell if it contains 0.25% Schottky defects

    (a) 2 g/cc (b)2.66 g/cc (c)3.06 g/cc (d)none of these

    31.

    Aqua-regia is:

    Answer»

    Aqua-regia is:


    32.

    For an isothermal irreversible expansion of 1 mole of a perfect gas, identify the correct relation where symbols have their usual meaning

    Answer»

    For an isothermal irreversible expansion of 1 mole of a perfect gas, identify the correct relation where symbols have their usual meaning

    33.

    E∘ for some half reaction given below: Find out the pair between which redox reaction is not possible Fe+3/Fe+2=+0.77, I2/I−=+0.54VCu+2/Cu=+0.34, Ag+/Ag=+0.80V

    Answer»

    E for some half reaction given below:
    Find out the pair between which redox reaction is not possible
    Fe+3/Fe+2=+0.77, I2/I=+0.54VCu+2/Cu=+0.34, Ag+/Ag=+0.80V


    34.

    Which of the following statements is correct regarding case of dehydration in alcohols [CPMT 1980, 85; MP PMT 2001; BHU 2002]

    Answer»

    Which of the following statements is correct regarding case of dehydration in alcohols [CPMT 1980, 85; MP PMT 2001; BHU 2002]


    35.

    The radius of isoelectronic species?

    Answer»

    The radius of isoelectronic species?

    36.

    Select option(s) in which correct major product is not given:

    Answer»

    Select option(s) in which correct major product is not given:

    37.

    The cyanamide ion (NCN−2) isiso electronic with

    Answer»

    The cyanamide ion (NCN2) isiso electronic with


    38.

    From the given set of minerals, the number of ores of copper is/are ___ Chalcocite, pyrargyrite, cuprite, carnallite, covellite, sphalerite, azurite, malachite, cryolite

    Answer»

    From the given set of minerals, the number of ores of copper is/are ___
    Chalcocite, pyrargyrite, cuprite, carnallite, covellite, sphalerite, azurite, malachite, cryolite

    39.

    A. Binary solid A plus B minus has a structure withB minus ions constituting the lattice and A plus occupied 25% tetrahedral holes formula of solid A2B AB AB2 AB4

    Answer» A. Binary solid A plus B minus has a structure withB minus ions constituting the lattice and A plus occupied 25% tetrahedral holes formula of solid

    A2B
    AB
    AB2
    AB4
    40.

    How do the large surface area of pentane leads to its high boiling point then iso pentane? ?

    Answer» How do the large surface area of pentane leads to its high boiling point then iso pentane? ?
    41.

    H2O2+2KI40% yield−−−−−→I2+2KOH H2O2+2KMnO4+3H2SO450% yield−−−−−→K2SO4+2MnSO4+3O2+4H2O 150 mL of H2O2 sample was divided into two parts. First part was treated with KI and formed KOH required 200 mL of M2 H2SO4 for neutralization. Other part was treated with KMnO4 for neutralization yielding 6.74 L of O2 at 1 atm and 273 K. Using % yield indicated, find volume strength of H2O2 sample used:

    Answer» H2O2+2KI40% yield−−−−I2+2KOH
    H2O2+2KMnO4+3H2SO450% yield−−−−K2SO4+2MnSO4+3O2+4H2O
    150 mL of H2O2 sample was divided into two parts. First part was treated with KI and formed KOH required 200 mL of M2 H2SO4 for neutralization. Other part was treated with KMnO4 for neutralization yielding 6.74 L of O2 at 1 atm and 273 K. Using % yield indicated, find volume strength of H2O2 sample used:
    42.

    The correct order of metal-carbon bond strength in the given metal carbonyls is:

    Answer»

    The correct order of metal-carbon bond strength in the given metal carbonyls is:

    43.

    Convert the given unlike fractions to like fractions: 34,811

    Answer»

    Convert the given unlike fractions to like fractions: 34,811


    44.

    Which of the following is the structure of D-xylose?

    Answer»

    Which of the following is the structure of D-xylose?

    45.

    Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be represented as v = 3.29 × 1015 (Hz) [1/32 – 1/n2 ] Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.

    Answer»

    Emission transitions in the Paschen series end at orbit n = 3 and start from orbit n and can be represented as v = 3.29 × 1015 (Hz) [1/32 – 1/n2 ] Calculate the value of n if the transition is observed at 1285 nm. Find the region of the spectrum.

    46.

    What are Diamagnetic substances

    Answer»

    What are Diamagnetic substances

    47.

    Which of the following is not known

    Answer»

    Which of the following is not known


    48.

    In diborane, the two H-B-H angles are nearly

    Answer»

    In diborane, the two H-B-H angles are nearly

    49.

    A salt is formed from a weak acid and weak base. If pKb &gt; pKa, then the pH of that salt solution is

    Answer»

    A salt is formed from a weak acid and weak base. If pKb > pKa, then the pH of that salt solution is


    50.

    The electrophile involved in Reimer-Tiemann reaction is:

    Answer» The electrophile involved in Reimer-Tiemann reaction is: