1.

Given that: S∘H2=131 JK−1mol−1S∘Cl2=223 JK−1mol−1and S∘HCl=187 JK−1mol−1 The standard entropy change in formation of 1 mole of HCl(g) from H2(g) and Cl2(g) will be: (Given, reaction for formation of HCl : H2+Cl2→2HCl)

Answer»

Given that:
S∘H2=131 JK−1mol−1S∘Cl2=223 JK−1mol−1and S∘HCl=187 JK−1mol−1
The standard entropy change in formation of 1 mole of HCl(g) from H2(g) and Cl2(g) will be:
(Given, reaction for formation of HCl : H2+Cl2→2HCl)


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