Given: Cu2++e−→Cu+;E∘=0.15VCu++e−→Cu;E∘=0.50VZn2++ze−→Zn;E∘=−0.76V If 9.65 amperes of current is passed, making Cu anode and Zn cathode for 1000 seconds in the cell Zn|Zn2+||Cu2+|Cu containing one litre of 0.55 M zinc (II) ions and one litre of 0.05 M copper (II) ions in the half cells, the E.M.F of cell the after passage of current would be (log 2 = 0.3, log 3 = 0.5, log 5 = 0.7) :

Given: Cu2++e−→Cu+;E∘=0.15VCu++e−→Cu;E∘=0.50VZn2++ze−→

1.	Given: Cu2++e−→Cu+;E∘=0.15VCu++e−→Cu;E∘=0.50VZn2++ze−→Zn;E∘=−0.76V If 9.65 amperes of current is passed, making Cu anode and Zn cathode for 1000 seconds in the cell Zn\|Zn2+\|\|Cu2+\|Cu containing one litre of 0.55 M zinc (II) ions and one litre of 0.05 M copper (II) ions in the half cells, the E.M.F of cell the after passage of current would be (log 2 = 0.3, log 3 = 0.5, log 5 = 0.7) :
Answer» Given: Cu2++e−→Cu+;E∘=0.15VCu++e−→Cu;E∘=0.50VZn2++ze−→Zn;E∘=−0.76V If 9.65 amperes of current is passed, making Cu anode and Zn cathode for 1000 seconds in the cell Zn\|Zn2+\|\|Cu2+\|Cu containing one litre of 0.55 M zinc (II) ions and one litre of 0.05 M copper (II) ions in the half cells, the E.M.F of cell the after passage of current would be (log 2 = 0.3, log 3 = 0.5, log 5 = 0.7) :