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2/9 + 4√5 = a + b√5 

As per the rule in maths, the first term of left hand side will be equal to first term of right hand side (in this type of question) 

So, 2/9 = a and 4√5 = b√5 

2/9 = a and (√5 is common in both i.e 4√5 and b√5) 

So, it will get cancelled 

a = 2/9 and b = 4 

A student was asked to mix the white of an egg with water and stir well. The student observed that a transparent mixture is formed.

To prepare colloidal solution of starch, we should Add starch to cold water & stir.

The size of colloidal particles is Between 10⁻⁷ cm and 10⁻⁵ cm.

(a) Suspension < Colloidal < True solution

A solution of egg albumin in water is a colloidal solution.

(d) All the above

There are some common thing you should follow to score better in your board examination. They are:

1. Make a strong grip over NCERT books. Do each and every question from all those chapters which are included in your syllabus. There is not a single question which comes out from NCERT book. You can read or download NCERT books for class 10 for quick revision.

2. Notes of each chapter are very important for quick revision. If you have made it than it is ok if not then don't waste your time in preparing notes at this time when your exam is near. Go online for notes of each subject. You can get class 10 science notes online.

3. If you have done these things, now it's time to solve more and more questions. First, solve CBSE sample papers for class 10 which CBSE board releases every year officially. Then solve at least the previous 10-year board question paper from the question bank.

4. You can also revise math formulas for quick revision of mathematics section. Refer here math formula.

If you follow this strategy then certainly you can score much better in board exams. 

"All the best for rest of things."

Key is used to join shaft and hub.

The Correct option is (b) Buyer 

(c) Gib and Cotter Joint

60° angle in degrees of a Metric thread.

A square lamina in isometric projection appears as Rhombus.

Correct option  (c)  15°

(d) Observer, Object and Plane

15° is the angle in degree between the main scale and isometric scale in the construction of isometric scale.

A circle drawn in isometric projection appears as Ellipse.

The angle between the flanks of a metric thread is 60°.

Correct option: (a)  Ellipse

The width of a key 'w' (as per standard dimensions) for a shaft of diameter d = 60 mm is 15 mm.

(c) Knuckle thread

Section lines are generally inclined with the base, at an angle of 45°.

The angle between the flanks of a BSW thread profile is 55°.

Correct option: (b)  Stud

D/4 is the width of the Rectangular Sunk Key, if the diameter of the shaft is D.

(d) External thread

Correct option (a) Rim

Stud part is called as “HEADLESS BOLT”.

(c) Crowning

(a) Flanged pipe joint

(c) Extension lines

Correct option: (d) 1 : 30

(a) Metric Thread Profile

The portion between the rim and the hub of a cast iron pulley Web.

ISOMETRIC SCALE

(a)  Marking of divisions of 10mm, including divisions of first part of 1mm on true length

(b)  Projections from scale 1:1 to get points on isometric scale, construction of isometric scale

(c)  Printing True Length / Scale 1:1, Isometric length/Isometric Scale and marking angles of 30° & 45°

Isometric scale

(i) Marking of divisions of 10mm, including division of first part of 1mm on true length

(ii) Projections from scale 1:1 to get points on isometric scale, construction of isometric scale

(iii) Printing ‘True length / Scale 1:1’, Isometric length/Isometric scale’ and marking angles of 30° and 45°

ISOMETRIC PROJECTION OF THE FRUSTUM OF A CONE

(a) Drawing upper & lower isometric ellipses

(b) Drawing both generators

(c) Marking vertical axis, central lines, direction of viewing

(d) Dimensions

SQUARE NUT

FRONT VIEW :

(i) Boundary lines with hidden lines showing threads with axis vertical and two opposite edges parallel to V.P.

(ii) Drawing arc with radius R.

TOP VIEW :

(i) Drawing three circles as per convention.

(ii) Square, circumscribing chamfer circle.

DETAILS :

Dimensions.

ISOMETRIC PROJECTION OF A SQUARE PYRAMID, PLACED CENTRALLY, ON A TRIANGULAR PRISM

TRIANGULAR PRISM

(a)  Drawing helping figure

(b)  Drawing both isometric triangles

(c)  Drawing vertical edges

(d)  Marking axis & direction of viewing

(e)  Dimensions

SQUARE PYRAMID

(a)  Drawing isometric square base

(b)  Drawing slant edges 

(c)  Marking vertical axis & central lines at base

(d)  Dimensions 

Knuckle Thread profile

(i) Distance, equal to pitch, marked correctly.

(ii) Semi-circular profile for threads (minimum two), drawn correctly

(iii) Dimensions and hatching lines

ISOMETRIC PROJECTION OF A SPHERE, PLACED CENTRALLY ON A HEXAGONAL PRISM SPHERE

(i) Locating the centre with isometric radius

(ii) Drawing the circle with true radius

(iii) Marking the vertical axis

(iv) Dimensions

HEXAGONAL PRISM

(i) Drawing helping figure

(ii) Drawing isometric hexagons

(iii) Drawing edges

(iv) Marking axis (⅟2) and direction of viewing (⅟2)

(v) Dimensions

Farmer should apply a biofertiliser to his crops as it contains micro organisms which when applied to the plants or soil promotes the growth of the crops without harming the nutrient quality of the plant.

Mediation of continuous dialogue between pollen grains and the pistil by the chemical components of the pollen and pistil interaction helps in recognition of right or wrong pollen grain. If the pollen is of wrong type, the pistil rejects the pollen by preventing pollen germination on stigma or pollen tube growth in the style.

Sexual reproduction of frogs and bony fishes has two main characteristics
(1) Both of these release mature gametes simultaneously.
(2) Both of them enhance the chances of syngamy (external fertilisation) by releasing a large number of gametes in water.

The proteins produced by genetically altered gene in a host are called recombinant proteins. Bioreactors are considered as vessels in which raw materials are biologically converted into specific products by microbes. It provides optimum growth conditions such as temperature, pH, substrate, vitamins, oxygen and salts.

Total oranges = 15, good oranges = 12, bad oranges = 3 

3 oranges are selected at random without replacement. 

Box is approved for sale if all the three selected oranges are good.

P(box approved for sale) = ¹²C₃/¹⁵C₃ = 44/91

Value reflected is honesty.

Xenogamy pollination as a result of which genetically different types of pollen grains of the same species land on the stigma.

(i) Homologous Organs: The study of these organs suggests that these organisms with organs having same structure but performing different functions have evolved from a common ancestor, e.g. forelimbs of different vertebrates. 

(ii) Analogous Organs: The study of these apparently similar organs suggests that the organisms with apparently similar organs do not share common ancestory. Similarity in these organs is superficial, design and the structure of these organs are very different, e.g. wings of bird and wings of butterfly. 

(iii) Fossils: They provide the missing link between the species, e.g. fossils of dinosaurs with feathers, fossils of prehistoric horse.

p(x) = x⁴ + 4x³ -2x² - 20x -15

x² - 5 is factor of p(x)

∴ p(x) = (x² -5) (x² + 4x +3)

or p(x) = (x² -5) (x -3) (x +1)

So, all the zeroes of p(x)(are √5, −√5, −3 and −1.