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Work function of nickel is 5.01 eV. When ultraviolet radiation of wavelength `200A` is incident of it, electrons are emitted. What will be the maximum velocity of emitted electrons?A. `3xx10^(8) ms^(-1)`B. `6.46xx10^(5)ms^(-1)`C. `10.36xx10^(5) ms^(-1)`D. `8.54xx10^(6) ms^(-1)` |
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Answer» Correct Answer - B Energy corresponding to `2000 A=(12375)/(2000)eV=6.2eV` Maximum kinetic energy is `(6.2-5.01)eV=1.19eV` Now, `(1)/(2)xx9.1xx10^(-31)xxv_(max)^2` `=1.19xx1.6xx10^(-19)` or `v_(max)^2=(1.19xx1.6xx10^(-19)xx2)/(9.1xx10^(-31))` `=.0418xx10^(12)=41.8xx10^(10)` or `v_(max)=6.46xx10^(5)ms^(-1)` |
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