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In question 23, if the intensity of light is made 4 I, the saturation current will becomeA. `0.4 mu A`B. `0.4xx2 mu A`C. `1.6 mu A`D. `0.4xx16 mu A` |
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Answer» Correct Answer - C Saturation current `prop` intensity `(i_(2))/(0.40) =(4 I)/(I) =4` `(i_(2))/(i_(1)) =4` `implies i_(2) =1.6 mu A` |
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