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In the previous question, if the intensity of light is made `4I_0`, then the stopping potential will becomeA. `1.36xx1V`B. `1.36xx2V`C. `1.36xx3V`D. `1.36xx4V` |
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Answer» Correct Answer - A Change in intensity from `I_0` to `4I_0` does not affect the stopping potential. |
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