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When a certain metallic surface is illuminated with monochromatic light of wavelength `lamda`, the stopping potential for photoelectric current is `3V_0` and when the same surface is illuminated with light of wavelength `2lamda`, the stopping potential is `V_0`. The threshold wavelength of this surface for photoelectrice effect isA. `6 lambda`B. `3 lambda`C. `4 lambda`D. `8 lambda` |
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Answer» Correct Answer - C `(hc)/(lambda) =phi +e.3 V_(0)` ….(i) `(hc)/(2lambda) =phi + e.V_(0)` ….(ii) 3(ii) - (i) `implies (hc)/(2 lambda) =3 phi - phi =2 phi =2. (hc)/(lambda_(0))` `lambda_(0) =4 lambda` |
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