Saved Bookmarks
| 1. |
The velocity of electromagnetic radiatior in a medium of permittivity `epsilon_(0)` and permeability `mu_(0)` is given byA. `sqrt((epsi_(0))/(mu_(0)))`B. `sqrt(mu_(0)epsi_(0))`C. `(1)/(sqrt(mu_(0)epsi_(0)))`D. `sqrt((mu_(0))/(epsi_(0)))` |
|
Answer» Correct Answer - C Velocity of electromagnetic radiation is the velocity of light (c), ie `c=(1)/(sqrt(mu_(0)epsi_(0)))` where `mu_(0)` is the permeability and `epsi_(0)` is the permittivity of free space. |
|