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A radioactive isotope having `t_(1//2)` =3 days was read after 12 days . If 3 g of the isotope is now left in the container, the initial weight of isotope wasA. 12 gB. 24 gC. 36 gD. 48 g |
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Answer» Correct Answer - D `T=nxxt_(1//2)` `12=nxx3` `n=4` `N=N_(0)xx((1)/(2))^(n)` `3=N_(0)xx((1)/(2))^(4)` `N_(0)=16xx3=48g` |
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