Solubility of `Ca(OH)_(2)` is s mol `L^(-1).` The solubility product ` – InterviewSolution

1.	Solubility of `Ca(OH)_(2)` is s mol `L^(-1).` The solubility product `(K_(sp))` under the same condition isA. `4s^(3)`B. `3s^(4)`C. `4s^(2)`D. `s^(3)`
Answer» Correct Answer - A `Ca(OH) hArr Ca^(2+)+2OH^(-)` `K_(sp)=[Ca^(2+)][OH^(-)]^(2)` `=(s)(2s)^((2)=4s^(2)`

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