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The mass of a `a_3^7 Li` nucleus is `0.042 u` less than the sum of the masses of all its nucleons. The binding energy per nucleon of `._3^7 Li` nucleus is nearly. |
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Answer» Correct Answer - `5.588 MeV//N` Here, `Deltam=0.042a.m.u` BE=`Deltamxx931.5MeV` `=0.042xx931.5MeV=39.123MeV` BE/nucleon `=39.123/7=5.588MeV//N` |
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