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A hydrogen atom initially in the ground level absorbs a photon, Which excites it to n=4 level. Determine the wavelength and frequency of photon. |
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Answer» For ground state, `n_1=1 and n_2=4`. Energy of photon absorbed, `E=E_2-E_1=(-13.6)/(n_2^2)-((-13.6)/(n_1^2))eV=13.6(1/(n_1^2)-1/(n_2^2))=13.6(1/(1^2)-1/(4^2))eV` `=13.6xx15/16eV=(13.6xx15)/16 xx1.6xx10^(-19)J=2.04xx10^(-18)"joule"` form `E=(hc)/lambda, lambda=(hc)/E=(6.6xx10^(-34)xx3xx10^8)/(2.04xx10^(-18))=9.7xx10^(-8)m, v=c/lambda=(3xx10^8)/(9.7xx10^(-8))=3.1xx10^(15)Hz` |
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