The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let `lambda_1`be the de-Broglie wavelength of the proton and `lambda_2` be the wavelength of the photon. The ratio `(lambda_1)/(lambda_2)` is proportional to (a)`E^0` (b) `E^(1//2)` (c ) `E^(-1)` (d)`E^(-2)`A. `E^0`B. `E^(1)/(2)`C. `E^-1`D. `E^-2`

The energy of a photon is equal to the kinetic energy of a proton. The

1.	The energy of a photon is equal to the kinetic energy of a proton. The energy of the photon is E. Let `lambda_1`be the de-Broglie wavelength of the proton and `lambda_2` be the wavelength of the photon. The ratio `(lambda_1)/(lambda_2)` is proportional to (a)`E^0` (b) `E^(1//2)` (c ) `E^(-1)` (d)`E^(-2)`A. `E^0`B. `E^(1)/(2)`C. `E^-1`D. `E^-2`
Answer» Correct Answer - B `lamda_1=(h)/(p)=(h)/(sqrt(2mE))` `lamda_2=(hc)/(E)=E^((1)/(2))`

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