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The electric field associated with a light wave is given by `E= E_0 sin [(1.57 xx 10^7 m^(-1)(x-ct)].` Find the stopping potential when this light is used in an experiment on photoelectric affect with a metal having work - function 1.9 eV.A. `0.6 V`B. `1.2 V`C. `1.8 V`D. `2.4 V` |
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Answer» Correct Answer - B `E =E_(0) sin (1.57xx10^(7))(x - ct)` `E =E_(0) sin .(omega)/(c)(x - ct)` `(omega)/(c) =1.57xx10^(7)` `(2pi upsilon)/(upsilon lambda) =1.57xx10^(7) =(pi)/(2)xx10^(7)` `lambda =4xx10^(-7) m=400 nm` `(1242)/(lambda) =(1242)/(400) =3.1 eV` |
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