1.

The decay constant for a radio nuclide, has a value of `1.386 day^(-1)`. After how much time will a given sample of this nuclide get reduced to only 6.25% of its present number ?

Answer» Correct Answer - `2days`
Here, `lambda=1.386 day^(-1), t=?`
`N/(N_(0))=6.25%`
Half life `T=0.693/lambda=0.693/1.386=1/2=0.5 day`
`N/(N_(0))=(1/2)^(n)=(6.25/100)=1/16=(1/2)^(4)`
`:. n=4=t/T, t=4T=4xx0.5=2 days`


Discussion

No Comment Found

Related InterviewSolutions