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The decay constant for a given radioactive sample is 0.3465 `day^-1`. What percentage of this sample will get decayed in a period of 4 days? |
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Answer» Here, `lambda=0.3465 day^-1, t=4days`. Half life, `T=0.693/lambda=0.693/0.3465=2days` No. of half lives, `n=t/T=4/2=2` `:. N/(N_0)=(1/2)^n=(1/2)^2=1/4=25%` Percentage of sample that will get decayed =100-25=75% |
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