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The deBroglie wavelength of a particle of kinetic energy K is `lamda`. What would be the wavelength of the particle, if its kinetic energy were `(K)/(4)`? |
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Answer» If `lamda` is the de Broglie wavelength of the particle of kinetic energy K, then `lamda=(h)/(sqrt(2mK))` Suppose that the de Broglie wavlength of the particle becomes `lamda^``, when its kinetic energy is `(K)/(4)`, then `lamda^`=(h)/(sqrt((2mK)/(4)))=2((h)/(sqrt(2mK)))=2lamda` |
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