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The de Broglie wavelength of neutrons in thermal equilibrium is (given `m_n=1.6xx10^(-27)`kg)`A. `(30.8)/(sqrtT)A`B. `(3.08)/(sqrtT)A`C. `(0.308)/(sqrtT)A`D. `(0.0308)/(sqrtT)A` |
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Answer» Correct Answer - A `lamda=(h)/(sqrt(2meT))` `=(6.62xx10^(-34))/(sqrt(2xx1.67xx10^(-27)xx1.38xx10^(-23)T))m` `=(6.62xx10^(-34))/(2.15xx10^(-25)sqrtT)m` `(3.079)/(sqrtT)xx10^(-9)m=(30.79)/(sqrtT)Aapprox(30.8)/(sqrtT)A` |
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