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The activity of a radioactive sample falls from `600 s^(-1) to 500 s^(-1) in 40 minutes. Calculate its half-life. |
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Answer» Correct Answer - `152mi n` form `A=A_(0)e^(-lambdat)` `500=600e^(-lambdat)` `e^(lambdat)=600/500` `lambdat log_(e) e=log_(e) (6//5)` `lambda=(log_(e) (6//5))/t` Half life, `T=0.693/(lamdba)=(0.693xxt)/(log_(e) (6//5))` `T=(0.693xx40)/(2.303xx0.792)=152min` |
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