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One Mev positron encounters one MeV electron travelling in opposite direction. What is the wavelength of photons produced, given rest mass energy of electron or positron `=0.512MeV` ? Take `h=6.62xx10^(-34)J-s`. |
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Answer» Correct Answer - `8.2xx10^(-13)m` The nuclear reaction is `._(+1)e^(0)+._(-1)e^(0)to 2gamma` Total energy before reaction =`1.512xx2MeV` After reaction, energy of each photon, `E=(1.512xx2)/2MeV` `E=1.512xx1.6xx10^(-13)J=(hc)/lambda` `lambda=(hc)/(1.512xx1.6xx10^(-13))=(6.6xx10^(-34)xx3xx10^(8))/(1.512xx1.6xx10^(-13))` `=8.2xx10^(-13)m` |
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