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`intsin^(-1)xdx` का मान ज्ञात कीजिए- |
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Answer» Correct Answer - `xsin^(-1)x+sqrt(1-x^2)` `I =int sin^(-1)x dx =int sin^(-1)x 1dx` `=sin^(-1)x int 1 dx -int {d/(dx)(sin^(-1)x)int 1dx}dx` `=sin^(-1)x.x-int1/sqrt(1-x^2)xdx` अब ` q-x^2=t^2` रखने पर `I=x sin^(-1)x - int1/t(-t)dt =x sin^(-1)x +int1 dt` `=x sin^(-1)x +sqrt(1-x^2)` |
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