`intsec^nxtanxdx,n!=0` – InterviewSolution

1.	`intsec^nxtanxdx,n!=0`
Answer» `I=int sec^(n)x tan x dx` `I=intsec^(n-1)x sec x tanx dx` Let `sec x= t rArr sec x tan x dx=dt` `therefore" "I=int l^(n-1)dt` ltbr. `=(t^(n))/(n)+c` `=(sec^(n)x)/(n)+c`

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