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Find the equation of the tangent to the curve `y=3x^(2)-x+1` at P(1, 3).A. `y=5x+2`B. `y=5x-2`C. `y=(1)/(5)x+2`D. `y=(1)/(5)x-2` |
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Answer» Correct Answer - B `y=3x^(2)-x+1` `therefore" "(dy)/(dx)=6x-1` `" "((dy)/(dx))_("(1, 3)")=6-1=5` `therefore" "m=5` Equation of tangent `y=mx+c` `y=5x+c" …(i)"` Put (1, 3) in equaiton (i), `3=5xx1+c` `therefore" "c=-2` Equation of tangent `y=5x-2` |
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