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`int cos^(-1)x dx ` मान ज्ञात कीजिए - |
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Answer» Correct Answer - `xcot^(-1)x+1/2log(1+x^2)` `intcot^(-1)=xdx =int(cot^(-1)x)1dx` `=cot^(-1)x int1dx-int{d/(dx)(cot^(-1)x)int1dx}dx` `xcot^(-1)x-int0(1/(1+x^2))x dx` अब माना `1+x^2=trArr 2x dx =dt` |
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