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In a photoelectric cell, the wavelength of incident light is chaged from `4000A` to `3600A`. The change in stopping potential will beA. 0.14 VB. 0.24 VC. 0.35 VD. 0.44 V

Answer» Correct Answer - C
`eV_S=hupsilon-phi_0`
`eV_s^`=hupsilon^`-phi_0`
`e(V_S^`-V_S)=hupsilon^`-hupsilon=((12374)/(3600)-(12375)/(4000))`
`V_S^`-V_S=3.44-3.09=0.35V`


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