1.

If the short wavelength limit of the continous spectrum coming out of a Coolidge tube is `10 A`, then the de Broglie wavelength of the electrons reaching the target netal in the Coolidge tube is approximatelyA. `0.3A`B. `3A`C. `30A`D. `10A`

Answer» Correct Answer - A
We have `KE=(p^2)/(2m_e)=(hc)/(lamda_(min))`
`P=sqrt((2hcm_e)/(lamda_(min)))`
For `lamda_(min)=10A`
`lamda_(de Broglie)cong0.3A`


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