1.

If the kinetic energy of the particle is increased to `16` times its previous value , the percentage change in the de - Broglie wavelength of the particle isA. 75B. 60C. 50D. 25

Answer» Correct Answer - A
de-Broglie wavelength
`lambda =(h)/(p) =(h)/(sqrt(2mK))`
`(lambda_(2))/(lambda_(1)) =sqrt((K_(1))/(K_(2))) =sqrt((K)/(16K)) =(1)/(4)`
`%` changed `=((lambda_(2))/(lambda_(1))-1)xx100= ((1)/(4)-1)xx100=-75%`
i.e. `75%` decrease


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