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Find the minimum energy required to separated a neutron form `._18Ar^(40)`. Given `M_n=1.008665 u` , mass of `._18Ar^(40)=39.962383u` and mass of `._18Ar^(39)=38.964314u`. |
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Answer» The nuclear reaction involved is `._18Ar^(40)` to `._18Ar^(39)+._0n^1` Mass defect `=39.962383-(38.964314+1.008665)` `Deltam=0.010596u` `:.` Minimum separation energy required `=Delta mxx931MeV` `=0.010596xx931=9.86MeV` |
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