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Find the de Broglie wavelength of 2 MeV proton. Mass of proton `=1.64xx10^(-27)kg`,`h=6.625xx10^(-34)Js` |
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Answer» Energy of proton, `E=2MeV=2xx1.6xx10^-13J` de Broglie wavelength, `lamda=(h)/(p)=(h)/(sqrt(2mE))` `implieslamda=(6.625xx10^-34)/(sqrt(2xx1.64xx10^-27xx1.6xx10^-13))` `implieslamda=2.044xx10^-14m` |
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