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Find the de Broglie wavelength of 2 MeV proton. Mass of proton `=1.64xx10^(-27)kg`,`h=6.625xx10^(-34)Js`

Answer» Energy of proton, `E=2MeV=2xx1.6xx10^-13J`
de Broglie wavelength, `lamda=(h)/(p)=(h)/(sqrt(2mE))`
`implieslamda=(6.625xx10^-34)/(sqrt(2xx1.64xx10^-27xx1.6xx10^-13))`
`implieslamda=2.044xx10^-14m`


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