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Explain with the help of a nuclear reaction in each of the following cases, how the neutron to proton ratio change during (i) `alpha`- decay (ii) `beta`- decay. |
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Answer» (i) `alpha`decay is represented as `._92U^(238) to ._90Th^(234)+._2He^4` Initial ratio of `("neutron number") /("proton number")=(238-92)/92=1.586` Final ratio of `("neutron number") /("proton number")=(234-90)/90=1.6` Clearly, the ratio increases slightly in `alpha`-decay. (ii) `beta`- decay may be represented as `._15P^(32) to ._16S^(32)+._(-1)e^0+barv` Initial ratio of `("neutron number") /("proton number")=(32-15)/15=1.13` Final ratio of `("neutron number") /("proton number")=(32-16)/16=1.00` Clearly, the ratio decraeses slightly in `beta`-decay. |
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